AktiraAktira JEE
PhysicsJEE Main 28 Jan 2026, Shift 2·Q19·MCQ·Easy–moderate

Units and Measurements · Significant figures & errors

The time period of a simple harmonic oscillator is T=2πmkT = 2\pi\sqrt{\dfrac{m}{k}}. The measured value of mass (mm) of the object is 10 g with an accuracy of 10 mg, and time for 50 oscillations of the spring is found to be 60 s using a watch of 2 s resolution. Percentage error in determination of spring constant(kk) is %.
  1. (1)3.43
  2. (2)3.35
  3. (3)7.60
  4. (4)6.76
We corrected a printing error in the original paper

Source printed “T=2πk/mT = 2\pi\sqrt{k/m}” (kk and mm interchanged).

Video solution coming soon

We're animating every PYQ step by step. Subscribe to get them first.

Subscribe

See the full 28 Jan 2026, Shift 2 paper

More on Significant figures & errors