AktiraAktira JEE
Physics chapters

Units and Measurements

32 JEE Main questions · Physics

Significant figures & errors

  1. PhysicsJEE Main 21 Jan 2026, Shift 1·Q5·MCQ·Easy–moderate
    Open
    In an experiment the values of two spring constants were measured as k1=(10±0.2)k_1 = (10 \pm 0.2) N/m and k2=(20±0.3)k_2 = (20 \pm 0.3) N/m. If these springs are connected in parallel, then the percentage error in equivalent spring constant is:
    1. (1)2.67%
    2. (2)2.33%
    3. (3)1.33%
    4. (4)1.67%
  2. PhysicsJEE Main 21 Jan 2026, Shift 2·Q11·MCQ·Easy
    Open
    Keeping the significant figures in view, the sum of the physical quantities 52.01m, 153.2 m and 0.123 m is :
    1. (1)205 m
    2. (2)205.333 m
    3. (3)205.33 m
    4. (4)205.3 m
  3. PhysicsJEE Main 21 Jan 2026, Shift 2·Q12·MCQ·Easy–moderate
    Open
    A spherical body of radius r and density σ\sigma falls freely through a viscous liquid having density ρ\rho and viscosity η\eta and attains a terminal velocity v0v_0. Estimated maximum error in the quantity η\eta is : (Ignore errors associated with σ\sigma, ρ\rho and g, gravitational acceleration)
    1. (1)2Δrr−Δv0v02\dfrac{\Delta r}{r} - \dfrac{\Delta v_0}{v_0}
    2. (2)2Δrr+Δv0v0\dfrac{2\Delta r}{r} + \dfrac{\Delta v_0}{v_0}
    3. (3)2[Δrr+Δv0v0]2\left[\dfrac{\Delta r}{r} + \dfrac{\Delta v_0}{v_0}\right]
    4. (4)2[Δrr−Δv0v0]2\left[\dfrac{\Delta r}{r} - \dfrac{\Delta v_0}{v_0}\right]
  4. PhysicsJEE Main 23 Jan 2026, Shift 1·Q4·MCQ·Easy–moderate
    Open
    Four persons measure the length of a rod as 20.00 cm, 19.75 cm, 17.01 cm and 18.25 cm. The relative error in the measurement of average length of the rod is:
    1. (1)0.24
    2. (2)0.18
    3. (3)0.06
    4. (4)0.08
  5. PhysicsJEE Main 23 Jan 2026, Shift 1·Q19·MCQ·Easy–moderate
    Open

    In a screw gauge, the zero of the circular scale lies 3 divisions above the horizontal pitch line when their metallic studs are brought in contact. Using this instrument thickness of a sheet is measured. If pitch scale reading is 1 mm and the circular scale reading is 51 then the correct thickness of the sheet is mm.

    [Assume least count is 0.01 mm]

    1. (1)1.50
    2. (2)1.48
    3. (3)1.54
    4. (4)1.51
  6. PhysicsJEE Main 23 Jan 2026, Shift 2·Q10·MCQ·Easy–moderate
    Open
    To compare EMF of two cells using potentiometer the balancing lengths obtained are 200 cm and 150 cm. The least count of scale is 1 cm. The percentage error in the ratio of EMFs is
    1. (1)1.45
    2. (2)1.65
    3. (3)1.75
    4. (4)1.55

    Flawed question. No option is correct: (1/200+1/150)×100=1.17%(1/200 + 1/150)\times100 = 1.17\% (the source's own solution says no option matches) and no evident intended version gives the key 1.65. It is shown for completeness and is left out of practice tests.

  7. PhysicsJEE Main 24 Jan 2026, Shift 2·Q2·MCQ·Easy–moderate
    Open
    In a vernier callipers, 50 vernier scale divisions are equal to 48 main scale divisions. If one main scale division =0.05= 0.05 mm, then the least count of the vernier callipers is mm.
    1. (1)0.002
    2. (2)0.05
    3. (3)0.02
    4. (4)0.005
  8. PhysicsJEE Main 28 Jan 2026, Shift 1·Q17·MCQ·Easy–moderate
    Open
    When both jaws of vernier callipers touch each other, zero mark of the vernier scale is right to zero mark of main scale, 4th4^{\text{th}} mark on vernier scale coincides with certain mark on the main scale. While measuring the length of a cylinder, observer observes 15 divisions on main scale and 5th5^{\text{th}} division of vernier scale coincides with a main scale division. Measured length of cylinder is mm. (Least count of Vernier calliper =0.1= 0.1 mm)
    1. (1)15.4
    2. (2)15.1
    3. (3)15.5
    4. (4)15.9
    We corrected a printing error in the original paper

    Source printed “coincides with a min scale division”.

  9. In an experiment, a set of readings are obtained 1.24 mm, 1.25 mm, 1.23 mm, 1.21 mm. The expected least count of the instrument used in recording these readings is mm.
    1. (1)0.01
    2. (2)0.001
    3. (3)0.1
    4. (4)0.05
    We corrected a printing error in the original paper

    Source printed “a set of reading are obtained −1.24-1.24 mm” (stray minus sign on the first reading).

  10. PhysicsJEE Main 28 Jan 2026, Shift 2·Q19·MCQ·Easy–moderate
    Open
    The time period of a simple harmonic oscillator is T=2πmkT = 2\pi\sqrt{\dfrac{m}{k}}. The measured value of mass (mm) of the object is 10 g with an accuracy of 10 mg, and time for 50 oscillations of the spring is found to be 60 s using a watch of 2 s resolution. Percentage error in determination of spring constant(kk) is %.
    1. (1)3.43
    2. (2)3.35
    3. (3)7.60
    4. (4)6.76
    We corrected a printing error in the original paper

    Source printed “T=2πk/mT = 2\pi\sqrt{k/m}” (kk and mm interchanged).

  11. PhysicsJEE Main 2 Apr 2026, Shift 1·Q2·MCQ·Moderate
    Open
    The diameter of a wire measured by a screw gauge of least count 0.001 cm is 0.08 cm. The length measured by a scale of least count 0.1 cm is 150 cm. When a weight of 100 N is applied to the wire, the extension in length is 0.5 cm, measured by a micrometer of least count 0.001 cm. The error in the measured Young's modulus is α×109 N/m2\alpha\times10^{9}\ \mathrm{N/m^2}. The value of α\alpha is .
    (Ignore the contribution of the load to Young's modulus error calculation)
    1. (1)1.3
    2. (2)1.65
    3. (3)0.13
    4. (4)0.25
  12. PhysicsJEE Main 2 Apr 2026, Shift 2·Q7·MCQ·Easy–moderate
    Open
    In a screw gauge the zero of main scale reference line coincides with the fifth division of the circular scale when two studs are in contact. There are 100 divisions in circular scale and pitch of screw gauge is 0.1 mm. When diameter of a sphere is measured, the reading of main scale is 5 mm and 50th50^{\text{th}} division of circular scale coincides with the reference line of main scale. The diameter of sphere is mm.
    1. (1)5.045
    2. (2)5.055
    3. (3)5.450
    4. (4)5.550
  13. PhysicsJEE Main 4 Apr 2026, Shift 1·Q1·MCQ·Easy–moderate
    Open
    In a screw gauge when the circular scale is given five complete rotations it moves linearly by 2.5 mm. If the circular scale has 100 divisions, the least count of screw gauge is mm.
    1. (1)1×10−21\times10^{-2}
    2. (2)1×10−31\times10^{-3}
    3. (3)5×10−25\times10^{-2}
    4. (4)5×10−35\times10^{-3}
  14. PhysicsJEE Main 5 Apr 2026, Shift 1·Q1·MCQ·Easy–moderate
    Open
    In a Vernier calipers, when both jaws touch each other, zero of the Vernier scale is shifted to the right of zero of the main scale and 7th7^{\text{th}} Vernier division coincides with a main scale reading. If the value of 1 main scale division is 1 mm and there are 10 Vernier scale divisions, then the Vernier caliper has
    1. (1)0.07 cm negative zero error
    2. (2)0.7 cm negative zero error
    3. (3)0.07 cm positive zero error
    4. (4)0.7 cm positive zero error
  15. PhysicsJEE Main 5 Apr 2026, Shift 2·Q2·MCQ·Easy–moderate
    Open
    In an experiment to determine the resistance of a given wire using Ohm's law, the voltmeter and ammeter readings are noted as 10V and 5 A, respectively. The least counts of voltmeter and ammeter are 500 mV and 200 mA, respectively. The estimated error in the resistance measurement is Ω\Omega
    1. (1)0.25
    2. (2)2
    3. (3)2.5
    4. (4)0.18
  16. PhysicsJEE Main 6 Apr 2026, Shift 1·Q1·MCQ·Easy–moderate
    Open
    The density ρ\rho of a uniform cylinder is determined by measuring its mass m, length ll and diameter d. The measured values of m, ll and d are 97.42±0.0297.42 \pm 0.02 g, 8.35±0.058.35 \pm 0.05 mm and 20.20±0.0220.20 \pm 0.02 mm, respectively. Calculated percentage fractional error in ρ\rho is .
    1. (1)0.63%
    2. (2)0.82%
    3. (3)0.72%
    4. (4)0.25%
  17. PhysicsJEE Main 6 Apr 2026, Shift 2·Q1·MCQ·Easy–moderate
    Open
    The percentage error in the calculated volume of a sphere, if there is 2% error in its diameter measurement, is .
    1. (1)1
    2. (2)2
    3. (3)6
    4. (4)8

Dimensional analysis

  1. PhysicsJEE Main 21 Jan 2026, Shift 1·Q7·MCQ·Easy–moderate
    Open
    Consider a modified Bernoulli equation. (P+ABt2)+ρg(h+Bt)+12ρV2=constant\left(P + \frac{A}{Bt^2}\right) + \rho g(h + Bt) + \frac12\rho V^2 = \text{constant} If tt has the dimension of time then the dimensions of AA and BB are , respectively.
    1. (1)[ML0T−1][\mathrm{ML^0T^{-1}}] and [M0LT][\mathrm{M^0LT}]
    2. (2)[ML0T−1][\mathrm{ML^0T^{-1}}] and [M0LT−1][\mathrm{M^0LT^{-1}}]
    3. (3)[ML0T−2][\mathrm{ML^0T^{-2}}] and [M0LT−2][\mathrm{M^0LT^{-2}}]
    4. (4)[ML0T−2][\mathrm{ML^0T^{-2}}] and [M0LT−1][\mathrm{M^0LT^{-1}}]
  2. PhysicsJEE Main 22 Jan 2026, Shift 1·Q19·MCQ·Easy–moderate
    Open
    Match the LIST-I with LIST-II
    List-IList-II
    A.Spring constantI.ML2T−2K−1\mathrm{ML^2T^{-2}K^{-1}}
    B.Thermal conductivityII.ML0T−2\mathrm{ML^0T^{-2}}
    C.Boltzmann constantIII.ML2T−3A−2\mathrm{ML^2T^{-3}A^{-2}}
    D.Inductive reactanceIV.MLT−3K−1\mathrm{MLT^{-3}K^{-1}}
    Choose the correct answer from the options given below:
    1. (1)(A)-(II), (B)-(I), (C)-(IV), (D)-(III)
    2. (2)(A)-(I), (B)-(IV), (C)-(II), (D)-(III)
    3. (3)(A)-(III), (B)-(II), (C)-(IV), (D)-(I)
    4. (4)(A)-(II), (B)-(IV), (C)-(I), (D)-(III)
  3. PhysicsJEE Main 22 Jan 2026, Shift 2·Q1·MCQ·Easy–moderate
    Open
    If ϵ\epsilon, E and t represent the free space permittivity, electric field and time respectively, then the unit of ϵEt\dfrac{\epsilon E}{t} will be :
    1. (1)Am
    2. (2)Am2\mathrm{Am^2}
    3. (3)A/m2\mathrm{A/m^2}
    4. (4)A/m
  4. PhysicsJEE Main 23 Jan 2026, Shift 2·Q23·Numerical·Easy–moderate
    Open
    A ball of radius rr and density ρ\rho dropped through a viscous liquid of density σ\sigma and viscosity η\eta attains its terminal velocity at time tt, given by t=A ρa rb ηc σdt = A\,\rho^{a}\,r^{b}\,\eta^{c}\,\sigma^{d}, where AA is a constant and aa, bb cc and dd are integers. The value of b+ca+d\dfrac{b+c}{a+d} is .
  5. PhysicsJEE Main 24 Jan 2026, Shift 1·Q1·MCQ·Easy–moderate
    Open
    Match the List-I with List-II
    List-IList-II
    A.Magnetic inductionI.M L T−2A−2\mathrm{M\,L\,T^{-2}A^{-2}}
    B.Magnetic fluxII.M L2 T−2A−2\mathrm{M\,L^{2}\,T^{-2}A^{-2}}
    C.Magnetic permeabilityIII.M L0 T−2A−1\mathrm{M\,L^{0}\,T^{-2}A^{-1}}
    D.Self inductanceIV.M L2 T−2A−1\mathrm{M\,L^{2}\,T^{-2}A^{-1}}
    Choose the correct answer from the options given below:
    1. (1)(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
    2. (2)(A)-(III), (B)-(IV), (C)-(II), (D)-(I)
    3. (3)(A)-(I), (B)-(III), (C)-(IV), (D)-(II)
    4. (4)(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
  6. PhysicsJEE Main 28 Jan 2026, Shift 2·Q20·MCQ·Easy
    Open
    Match List-I with List-II.
    List-IList-II
    A.Coefficient of viscosityI.[ML−1T−2][\mathrm{ML^{-1}T^{-2}}]
    B.Surface tensionII.[ML2T−2][\mathrm{ML^{2}T^{-2}}]
    C.PressureIII.[ML0T−2][\mathrm{ML^{0}T^{-2}}]
    D.Surface energyIV.[ML−1T−1][\mathrm{ML^{-1}T^{-1}}]
    Choose the correct answer from the options given below:
    1. (1)(A)-(I), (B)-(II), (C)-(IV), (D)-(III)
    2. (2)(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
    3. (3)(A)-(I), (B)-(III), (C)-(II), (D)-(IV)
    4. (4)(A)-(IV), (B)-(I), (C)-(II), (D)-(III)
  7. PhysicsJEE Main 2 Apr 2026, Shift 1·Q1·MCQ·Easy–moderate
    Open
    The dimensional formula of 12ϵ0E2\dfrac12\epsilon_0E^2 (ϵ0=\epsilon_0 = permittivity of vacuum and E=E = electric field) is MaLbTc\mathrm{M^aL^bT^c}. The value of 2a−b+c=2a - b + c = .
    1. (1)0
    2. (2)1
    3. (3)−1-1
    4. (4)2
  8. PhysicsJEE Main 2 Apr 2026, Shift 2·Q1·MCQ·Easy–moderate
    Open
    Dimensions of universal gravitational constant (G) in terms of Planck's constant (hh), distance (LL), mass (MM) and time (TT) are .
    1. (1)[hTLM−2][\mathrm{hTLM^{-2}}]
    2. (2)[hT−1LM−2][\mathrm{hT^{-1}LM^{-2}}]
    3. (3)[hTL2M−2][\mathrm{hTL^{2}M^{-2}}]
    4. (4)[h−1T−1LM−2][\mathrm{h^{-1}T^{-1}LM^{-2}}]
  9. PhysicsJEE Main 4 Apr 2026, Shift 2·Q1·MCQ·Easy
    Open
    Match the LIST-I with LIST-II
    List-IList-II
    A.Planck's constantI.ML2T−2\mathrm{ML^2T^{-2}}
    B.Stopping potentialII.T−1\mathrm{T^{-1}}
    C.Work functionIII.ML2T−1\mathrm{ML^2T^{-1}}
    D.Threshold frequencyIV.ML2T−3A−1\mathrm{ML^2T^{-3}A^{-1}}
    Choose the correct answer from the options given below:
    1. (1)(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
    2. (2)(A)-(I), (B)-(II), (C)-(III), (D)-(IV)
    3. (3)(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
    4. (4)(A)-(I), (B)-(IV), (C)-(III), (D)-(II)
  10. PhysicsJEE Main 5 Apr 2026, Shift 1·Q2·MCQ·Easy–moderate
    Open
    L, C and R represent physical quantities inductance, capacitance and resistance respectively. The dimensional formula M L2T−4A−2\mathrm{M\,L^{2}T^{-4}A^{-2}} corresponds to .
    1. (1)RLC\dfrac{R}{\sqrt{LC}}
    2. (2)RLC\dfrac{R}{LC}
    3. (3)CLR\dfrac{C}{\sqrt{LR}}
    4. (4)1RLC\dfrac{1}{R}\sqrt{\dfrac{L}{C}}
    We corrected a printing error in the original paper

    Source printed “represents”.

  11. PhysicsJEE Main 5 Apr 2026, Shift 2·Q1·MCQ·Easy–moderate
    Open
    Match List-I with List-II.
    List-IList-II
    (A) Meter (L)I. hcG\sqrt{\dfrac{hc}{\mathrm{G}}}
    [6pt] (B) Second (S)II. Ghc5\sqrt{\dfrac{\mathrm{G}h}{\mathrm{c}^5}}
    [6pt] (C) Kilogram (M)III. K2L2c3Gh\sqrt{\dfrac{\mathrm{K^2L^2c^3}}{\mathrm{G}h}}
    [6pt] (D) Kelvin (K)IV. Ghc3\sqrt{\dfrac{\mathrm{G}h}{\mathrm{c}^3}}

    where h (Planck's constant), G (gravitational constant) and c (speed of light in vacuum) are taken as fundamental units.

    Choose the correct answer from the options given below:

    1. (1)A-II, B-IV, C-I, D-III
    2. (2)A-IV, B-II, C-I, D-III
    3. (3)A-IV, B-I, C-II, D-III
    4. (4)A-III, B-I, C-II, D-IV
    We corrected a printing error in the original paper

    Source printed “c (speed of light in vacuum) as fundamental units” (verb missing).

  12. PhysicsJEE Main 6 Apr 2026, Shift 1·Q2·MCQ·Easy–moderate
    Open
    The potential energy of a particle changes with distance x from a fixed origin as V=Axx+BV = \dfrac{A\sqrt{x}}{x + B}, where A and B are constants with appropriate dimensions. The dimensions of AB are .
    1. (1)[M1L5/2T−2][\mathrm{M^1L^{5/2}T^{-2}}]
    2. (2)[M3/2L5/2T−2][\mathrm{M^{3/2}L^{5/2}T^{-2}}]
    3. (3)[M1L2T−2][\mathrm{M^1L^2T^{-2}}]
    4. (4)[M1L7/2T−2][\mathrm{M^1L^{7/2}T^{-2}}]
    We corrected a printing error in the original paper

    Source printed “A and B are constant with appropriate dimensions. The dimension of AB are”.

  13. PhysicsJEE Main 6 Apr 2026, Shift 2·Q2·MCQ·Easy–moderate
    Open
    Match List-I with List-II.
    List-IList-II
    A.Boltzmann constantI.[M−1L3T−2][\mathrm{M^{-1}L^{3}T^{-2}}]
    B.Stefan's constantII.[M L2T−1][\mathrm{M\,L^{2}T^{-1}}]
    C.Planck's constantIII.[ML2T−2K−1][\mathrm{ML^{2}T^{-2}K^{-1}}]
    D.Gravitational constantIV.[ML0T−3K−4][\mathrm{ML^{0}T^{-3}K^{-4}}]
    1. (1)(A)-(I), (B)-(II), (C)-(III), (D)-(IV)
    2. (2)(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
    3. (3)(A)-(III), (B)-(IV), (C)-(II), (D)-(I)
    4. (4)(A)-(II), (B)-(I), (C)-(IV), (D)-(III)
  14. PhysicsJEE Main 8 Apr 2026, Shift 2·Q2·MCQ·Moderate
    Open
    Consider the equation H=xp ϵq ErtsH = \dfrac{x^{p}\,\epsilon^{q}\,E^{r}}{t^{s}}
    Where H=H = magnetic field intensity; E=E = electric field; ϵ=\epsilon = permittivity, x=x = distance, t=t = time. The values of pp, qq, rr and ss respectively are:
    1. (1)1, 1, 1, 1
    2. (2)−1-1, 1, 2, 1
    3. (3)1, −1-1, −2-2, 1
    4. (4)−1-1, −2-2, −2-2, 1
    We corrected a printing error in the original paper

    Source printed “H=H = magnetic field” (with H=BH = B in tesla no option fits); corrected to the intended “H=H = magnetic field intensity” (A/m).

Units and SI

  1. PhysicsJEE Main 8 Apr 2026, Shift 2·Q1·MCQ·Easy
    Open
    A new unit (α\alpha) of length is chosen such that it is equal to the distance travelled by light in vacuum in 1 s. What is the distance between Venus and Earth in terms of α\alpha units if light takes 6 min. 40 s to cover this distance?
    1. (1)200 α200\,\alpha
    2. (2)400 α400\,\alpha
    3. (3)300 α300\,\alpha
    4. (4)500 α500\,\alpha
    We corrected a printing error in the original paper

    Source printed “such that it is equal to the speed of light in vacuum” (a length cannot equal a speed); corrected to the intended “equal to the distance travelled by light in vacuum in 1 s”.