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MathsJEE Main 4 Apr 2026, Shift 1·Q15·MCQ·Moderate

3D Geometry · Distance measured along a line

The square of the distance of the point (−2,−8,6)(-2, -8, 6) from the line x−11=y−12=z−1\dfrac{x - 1}{1} = \dfrac{y - 1}{2} = \dfrac{z}{-1} along the line x+51=y+5−1=z2\dfrac{x + 5}{1} = \dfrac{y + 5}{-1} = \dfrac{z}{2} is equal to:
  1. (1)3
  2. (2)6
  3. (3)8
  4. (4)12

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See the full 4 Apr 2026, Shift 1 paper