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JEE Main 2026

JEE Main 4 Apr 2026, Shift 1

75 questions. Answers are hidden — tap “Show answer” under each one.

Physics

  1. In a screw gauge when the circular scale is given five complete rotations it moves linearly by 2.5 mm. If the circular scale has 100 divisions, the least count of screw gauge is mm.
    1. (1)1×10−21\times10^{-2}
    2. (2)1×10−31\times10^{-3}
    3. (3)5×10−25\times10^{-2}
    4. (4)5×10−35\times10^{-3}
  2. The increase in the pressure required to decrease the volume (ΔV\Delta V) of water is 6.3×107 N/m26.3\times10^{7}\ \mathrm{N/m^2}. The percentage decrease in the volume is . (Bulk modulus of water =2.1×109 N/m2= 2.1\times10^{9}\ \mathrm{N/m^2}.)
    1. (1)2 %
    2. (2)3 %
    3. (3)6 %
    4. (4)4 %
  3. The time taken by a block of mass m to slide down from the highest point to the lowest point on a rough inclined plane is 50 % more compared to the time taken by the same block on identical inclined smooth plane. Both inclined planes are at 45∘45^\circ with the horizontal. The coefficient of kinetic friction between the rough inclined surface and block is .
    1. (1)3/4
    2. (2)2/3
    3. (3)5/9
    4. (4)4/9
  4. Q4 · MCQ · NucleiOpen
    Two nuclei of mass number 3 combine with another nucleus of mass number 4 to yield a nucleus of mass number 10. If the binding energy per nucleon for the mass number 3, 4 and 10 are 5.6 MeV, 7.4 MeV and 6.1 MeV, respectively, then in the process, ΔMc2=\Delta Mc^2 = MeV.
    1. (1)6.9
    2. (2)7.9
    3. (3)2.2
    4. (4)4.3
  5. A solid sphere of mass MM and radius RR is divided into two unequal parts. The smaller part having mass M/8M/8 is converted into a sphere of radius rr and the larger part is converted into a circular disc of thickness tt and radius 2R2R. If I1I_1 is moment of inertia of a sphere having radius rr about an axis through its centre and I2I_2 is the moment of inertia of a disc about its diameter, the ratio of their moment of inertia I2/I1=I_2/I_1 = .
    1. (1)35
    2. (2)70
    3. (3)140
    4. (4)210
    We corrected a printing error in the original paper

    Source printed “mas”.

  6. The two projectiles are projected with the same initial velocities at the 15∘15^\circ and 30∘30^\circ with respect to the horizontal. The ratio of their ranges is 1:x1 : x. The value of xx is
    1. (1)2\sqrt2
    2. (2)3\sqrt3
    3. (3)232\sqrt3
    4. (4)12\dfrac{1}{\sqrt2}
  7. The graph shows variation of stopping potential VoV_o with the frequency ν\nu of the incident radiation for three photosensitive metals X1X_1, X2X_2 and X3X_3. Which metal will give out electrons with greater kinetic energy, for the same wavelength of incident radiation?
    1. (1)X1X_1
    2. (2)X2X_2
    3. (3)X3X_3
    4. (4)All the metals will give out photo electrons with same kinetic energies.
  8. Q8 · MCQ · Wave OpticsOpen
    A slit of width aa is illuminated by light of wavelength λ\lambda. The linear separation between 1st1^{\text{st}} and 3rd3^{\text{rd}} minima in the diffraction pattern produced on a screen placed at a distance DD from the slit system is .
    1. (1)Dλa\dfrac{D\lambda}{a}
    2. (2)1.5Dλa1.5\dfrac{D\lambda}{a}
    3. (3)2Dλa2\dfrac{D\lambda}{a}
    4. (4)3Dλa3\dfrac{D\lambda}{a}
  9. A string A of length 0.314 m of Young's modulus 2×1010 N/m22\times10^{10}\ \mathrm{N/m^2} is connected to another string B of length and Young's modulus both twice of those of A. This series combination of strings is then suspended from a rigid support and its free end is fixed to a load of mass 0.8 kg. The net change in length of the combination is mm.
    (radius of both the strings is 0.2 mm and acceleration due to gravity =10 m/s2= 10\ \mathrm{m/s^2})
    (Mass of both strings is to be neglected as compared to the mass of load)
    1. (1)3
    2. (2)2
    3. (3)1.9
    4. (4)1
  10. One gas of n1n_1 mole of molecules at temperature T1T_1, volume V1V_1, and pressure P1P_1, and another gas of n2n_2 mole of molecules at temperature T2T_2, volume V2V_2, and pressure P2P_2, are mixed resulting in pressure PP and volume VV of the mixture. The temperature of the mixture is .
    1. (1)(T1+T2)/2(T_1 + T_2)/2
    2. (2)T1T2PV/(T2P1V1+T1P2V2)T_1T_2PV/(T_2P_1V_1 + T_1P_2V_2)
    3. (3)(T2P1V1+T1P2V2)/(T1T2PV)(T_2P_1V_1 + T_1P_2V_2)/(T_1T_2PV)
    4. (4)∣T1−T2∣/2|T_1 - T_2|/2
    We corrected a printing error in the original paper

    Source printed option (3) as “(T2P1V1+T1P2V2) (T1T2PV)(T_2P_1V_1 + T_1P_2V_2)\,(T_1T_2PV)” (the “/” missing).

  11. An ideal gas undergoes a process maintaining relation between pressure (PP) and volume (VV) as P=Po(1+(VoV)2)−1P = P_o\left(1 + \left(\dfrac{V_o}{V}\right)^{2}\right)^{-1}, where PoP_o and VoV_o are constants. If two samples A and B (two moles each) with initial volume VoV_o and 3Vo3V_o respectively undergo above mentioned process, then the difference of the initial temperatures of these samples, TB−TAT_B - T_A is
    (RR = gas constant)
    1. (1)9PoVo8R\dfrac{9P_oV_o}{8R}
    2. (2)11PoVo10R\dfrac{11P_oV_o}{10R}
    3. (3)7PoVo6R\dfrac{7P_oV_o}{6R}
    4. (4)13PoVo11R\dfrac{13P_oV_o}{11R}
    We corrected a printing error in the original paper

    Source printed “undergo above mentioned process and attain same pressure, then the difference at the temperatures”; corrected to the intended “undergo above mentioned process, then the difference of the initial temperatures” (two samples on the same P(V)P(V) curve at the same pressure would have equal temperatures; the key is TB−TAT_B - T_A at VoV_o and 3Vo3V_o).

  12. A voltmeter with internal resistance of x Ωx\ \Omega can be used to measure upto 20 V. In order to increase its measuring range to 30 V, the required modification is to .
    1. (1)connect resistor of x2 Ω\dfrac{x}{2}\,\Omega, in series with voltmeter.
    2. (2)connect resistor of x2 Ω\dfrac{x}{2}\,\Omega, in parallel to voltmeter.
    3. (3)connect resistor of x Ωx\ \Omega, in series with voltmeter.
    4. (4)connect resistor of 2x Ω2x\ \Omega, in parallel to voltmeter.
  13. Two 4 bits binary numbers, A=1101A = 1101 and B=1010B = 1010 are given in the inputs of a logic circuit shown in figure below. The output (YY) will be :
    1. (1)Y=1101Y = 1101
    2. (2)Y=0010Y = 0010
    3. (3)Y=0111Y = 0111
    4. (4)Y=1000Y = 1000
  14. Q14 · MCQ · Ray OpticsOpen
    A rod of length 10 cm lies along the principal axis of a concave mirror of focal length 10 cm as shown in figure. The length of the image is cm.
    1. (1)2.5
    2. (2)5
    3. (3)7.5
    4. (4)7
    We corrected a printing error in the original paper

    Source printed “principle axis”.

  15. A parallel plate air capacitor is connected to a battery. The plates are pulled apart at uniform speed vv. If xx is the separation between the plates at any instant, then the time rate of change of electrostatic energy of the capacitor is proportional to xαx^{\alpha}, where α\alpha is .
    1. (1)−2-2
    2. (2)1
    3. (3)−1-1
    4. (4)2
  16. An insulated wire is wound so that it forms a flat coil with N=200N = 200 turns. The radius of the innermost turn is r1=3r_1 = 3 cm, and of the outermost turn r2=6r_2 = 6 cm. If 20 mA current flows in it then the magnetic moment will be α×10−2 A m2\alpha\times10^{-2}\ \mathrm{A\,m^2}. The value of α\alpha is .
    1. (1)4.4
    2. (2)2.64
    3. (3)3.25
    4. (4)1.2
    We corrected a printing error in the original paper

    Source printed “If 20 mA current flow in it”.

  17. Consider a circuit consisting of a capacitor (20 μ20\ \muF), resistor (100 Ω100\ \Omega) and two identical diodes as shown in figure. The resistance of diode under forward biasing condition is 10 Ω10\ \Omega. The time constant of the circuit is α×10−3\alpha\times10^{-3} s. The value of α\alpha is .
    1. (1)2.2
    2. (2)2.0
    3. (3)2.1
    4. (4)2.4
  18. The voltage and the current between A and B points shown in the circuit are .
    1. (1)24 V, 12 A
    2. (2)24 V, 4 A
    3. (3)18 V, 12 A
    4. (4)27 V, 4 A
  19. Q19 · MCQ · Ray OpticsOpen
    A telescope with objective diameter RR is used to observe a distant star emitting light of wavelength 500 nm, at a resolution of 5×10−75\times10^{-7} radian. The value of RR is cm.
    1. (1)61
    2. (2)122
    3. (3)244
    4. (4)305
  20. Q20 · MCQ · Wave OpticsOpen
    An unpolarized light is incident on the plane interface of air-dielectric medium shown in figure. If the incident angle is equal to Brewster angle, identify the expression representing reflected wave.
    1. (1)Eyj^sin⁡(kx−kz−ωt)E_y\hat j\sin(kx - kz - \omega t)
    2. (2)(Exi^+Ezk^)sin⁡(kx+ky−ωt)(E_x\hat i + E_z\hat k)\sin(kx + ky - \omega t)
    3. (3)(Eyj^+Ezk^)sin⁡(ky+kz−ωt)(E_y\hat j + E_z\hat k)\sin(ky + kz - \omega t)
    4. (4)(Exi^+Eyj^+Ezk^)sin⁡(kx+ky−kz−ωt)(E_x\hat i + E_y\hat j + E_z\hat k)\sin(kx + ky - kz - \omega t)
    We corrected a printing error in the original paper

    Source printed option (1) as “(Exi^+Eyj^)sin⁡(kx−kz−ωt)(E_x\hat i + E_y\hat j)\sin(kx - kz - \omega t)”; corrected to the intended “Eyj^sin⁡(kx−kz−ωt)E_y\hat j\sin(kx - kz - \omega t)” (at the Brewster angle the reflected light is polarised perpendicular to the plane of incidence xzxz, and an Exi^E_x\hat i component is not transverse to the reflected direction); source printed option (3) as “(Exj^+Eyk^)(E_x\hat j + E_y\hat k)”.

  21. Q21 · Numerical · Work, Energy and PowerOpen
    A 1 kg block subjected to two simultaneous forces (2i^+3j^+4k^)(2\hat i + 3\hat j + 4\hat k) N and (3i^−j^−2k^)(3\hat i - \hat j - 2\hat k) N is moved a distance of 25 m along (3i^−4j^)(3\hat i - 4\hat j) direction. The work done in this process is J.
  22. The surface tension of a soap solution is 3.5×10−23.5\times10^{-2} N/m. The work required to increase the radius of a soap bubble from 1 cm to 2 cm is α×10−6\alpha\times10^{-6} J. The value of α\alpha is . (π=22/7\pi = 22/7)
  23. Q23 · Numerical · OscillationsOpen
    The velocity of a particle executing simple harmonic motion along x-axis is described as v2=50−x2v^2 = 50 - x^2, where xx represents displacement. If the time period of motion is α7\dfrac{\alpha}{7} s, the value of α\alpha is .
    We corrected a printing error in the original paper

    Source printed the period as “x7\dfrac{x}{7} s, the value of xx” (xx already denotes the displacement).

  24. Q24 · Numerical · Work, Energy and PowerOpen
    A body of mass 2 kg begins to move under the influence of time dependent force F⃗=(2ti^+6t2j^)\vec F = (2t\hat i + 6t^2\hat j) N, where i^\hat i and j^\hat j are unit vectors along x and y-axis respectively. The power produced by the force at t=2t = 2 s is W.
  25. Q25 · Numerical · Alternating CurrentOpen
    An inductor, a capacitor and a resistor of 100 Ω100\ \Omega are connected in series across an a.c power supply 220 V, 70 Hz. The power factor of the given circuit is 0.5. The difference in the inductive reactance and capacitance reactance is 3 α Ω\sqrt3\,\alpha\ \Omega. The value of α\alpha is .
    We corrected a printing error in the original paper

    Source printed “An inductor of 10 mH, capacitor of 0.1 μ0.1\ \muF and a resistor of 100 Ω100\ \Omega are connected in series aross”; corrected to the intended “An inductor, a capacitor and a resistor of 100 Ω100\ \Omega are connected in series across” (10 mH and 0.1 μ0.1\ \muF at 70 Hz give a power factor of about 0.004, contradicting the stated 0.5 on which the key rests).

Chemistry

  1. Number of moles and number of molecules in 1.4187 L of SOX2\ce{SO2} at STP respectively are
    1. (1)0.1266; 3.812×10223.812\times10^{22}
    2. (2)0.0633; 3.812×10223.812\times10^{22}
    3. (3)0.1266; 7.6238×10227.6238\times10^{22}
    4. (4)0.0633; 7.6238×10227.6238\times10^{22}
  2. What is the ratio of wave number of first line (lowest energy line) of Balmer series of H atomic spectrum to first line of its Brackett series?
    1. (1)5:1
    2. (2)5:0.81
    3. (3)5:1.75
    4. (4)5:27
  3. Which of the following is correct set of 4 quantum number of 19th^\text{th} electron in Chromium (Atomic number == 24) in accordance with Aufbau principle?
    1. (1)n=3n = 3, ℓ=2\ell = 2, m=+2m = +2, s=+12s = +\dfrac{1}{2}
    2. (2)n=3n = 3, ℓ=2\ell = 2, m=−2m = -2, s=+12s = +\dfrac{1}{2}
    3. (3)n=4n = 4, ℓ=1\ell = 1, m=0m = 0, s=+12s = +\dfrac{1}{2}
    4. (4)n=4n = 4, ℓ=0\ell = 0, m=0m = 0, s=+12s = +\dfrac{1}{2}
  4. Q4 · MCQ · ThermodynamicsOpen

    Given below are two statements:

    Statement I : For an ideal gas, heat capacity at constant volume is always greater than the heat capacity at constant pressure.

    Statement II : In a constant volume process, no work is produced and all the heat withdrawn goes into the chaotic motion and is reflected by a temperature increase of the ideal gas.

    In the light of the above statements, choose the correct answer from the options given below

    1. (1)Both Statement I and Statement II are true
    2. (2)Both Statement I and Statement II are false
    3. (3)Statement I is true but Statement II is false
    4. (4)Statement I is false but Statement II is true
  5. Q5 · MCQ · EquilibriumOpen

    At T(K), the equilibrium constant of

    AX2(g)+BX2(g)⇌C(g)\ce{A2(g) + B2(g) <=> C(g)} is 2.7×10−52.7\times10^{-5}.

    What is the equilibrium constant for

    13 AX2(g)+13 BX2(g)⇌13 C(g)\ce{1/3 A2(g) + 1/3 B2(g) <=> 1/3 C(g)} at the same temperature?

    1. (1)(2.7×10−5)3(2.7\times10^{-5})^{3}
    2. (2)6×10−26\times10^{-2}
    3. (3)2.7×10−5\sqrt{2.7\times10^{-5}}
    4. (4)3×10−23\times10^{-2}
  6. In order to oxidise a mixture of 1 mole each of FeCX2OX4\ce{FeC2O4}, FeX2(CX2OX4)X3\ce{Fe2(C2O4)3}, FeSOX4\ce{FeSO4} and FeX2(SOX4)X3\ce{Fe2(SO4)3} in acidic medium, the number of moles of KMnOX4\ce{KMnO4} required is :
    1. (1)3
    2. (2)2
    3. (3)5
    4. (4)7
  7. Consider the first order reaction R→P\ce{R -> P}.

    The fraction of molecules decomposed in the given first order reaction can be expressed as

    1. (1)1−ek1t1-e^{k_1t}
    2. (2)1+ek1t1+e^{k_1t}
    3. (3)1+e−k1t1+e^{-k_1t}
    4. (4)1−e−k1t1-e^{-k_1t}
  8. A monoatomic anion (AX−\ce{A^-}) has 45 neutrons and 36 electrons. Atomic mass, group in the periodic table and physical state at room temperature of the element (A) respectively are :
    1. (1)80, 17, liquid
    2. (2)81, 16, solid
    3. (3)80, 16, gas
    4. (4)81, 15, gas
  9. Given below are two statements :

    Statement I : The covalency of oxygen is generally two but it can exceed upto four. The oxidation state of oxygen in SOX2\ce{SO2} is −2-2 and in OFX2\ce{OF2} it is +2+2.

    Statement II : The anomalous behaviour of oxygen when compared to the other elements of group 16 is due to its small size and high electronegativity.

    In the light of the above statements, choose the correct answer from the options given below :

    1. (1)Both Statement I and Statement II are true
    2. (2)Both Statement I and Statement II are false
    3. (3)Statement I is true but Statement II is false
    4. (4)Statement I is false but Statement II is true
  10. Q10 · MCQ · d- and f-BlockOpen
    The correct statements among the following are,
    • (A)Mo(VI) and W(VI) are less stable than Cr(VI).
    • (B)CeX4+\ce{Ce^{4+}} and TbX4+\ce{Tb^{4+}} are oxidant while EuX2+\ce{Eu^{2+}} and YbX2+\ce{Yb^{2+}} are reductant.
    • (C)Cm and Am have seven unpaired electrons.
    • (D)Actinoid contraction is greater from element to element than lanthanoid contraction.
    Choose the correct answer from the options given below :
    1. (1)A and B Only
    2. (2)C and D Only
    3. (3)B and D Only
    4. (4)A and C Only
  11. Q11 · MCQ · d- and f-BlockOpen
    Correct statements from the following are
    • (A)Potassium dichromate is an oxidising agent and it oxidises FeSOX4\ce{FeSO4} to FeX2(SOX4)X3\ce{Fe2(SO4)3} in acidic medium.
    • (B)Sodium dichromate can be used as primary standard in volumetric estimation.
    • (C)CrOX4X2−\ce{CrO4^2-} and CrX2OX7X2−\ce{Cr2O7^2-} are interconvertible in aqueous solution by varying the pH of the solution.
    • (D)Cr–O–Cr bond angle in CrX2OX7X2−\ce{Cr2O7^2-} is 126∘^\circ.
    Choose the correct answer from the options given below :
    1. (1)A, B and C only
    2. (2)A, C and D only
    3. (3)A and C only
    4. (4)B and D only
  12. Match the List-I with List-II
    List-IList-II
    Complex ionCalculated spin only
    magnetic moment (BM)
    A.[Cr(HX2O)X6]X2+\ce{[Cr(H2O)6]^2+}I.3.87
    B.[Co(HX2O)X6]X2+\ce{[Co(H2O)6]^2+}II.5.92
    C.[Cu(HX2O)X6]X2+\ce{[Cu(H2O)6]^2+}III.4.90
    D.[Mn(HX2O)X6]X2+\ce{[Mn(H2O)6]^2+}IV.1.73
    Choose the correct answer from the options given below:
    1. (1)A-I, B-III, C-IV, D-II
    2. (2)A-II, B-I, C-III, D-IV
    3. (3)A-IV, B-II, C-I, D-III
    4. (4)A-III, B-I, C-IV, D-II
  13. Increasing order of electron withdrawing power of following functional groups is :
    • (a)−CN\ce{-CN}
    • (b)−COOH\ce{-COOH}
    • (c)−NOX2\ce{-NO2}
    • (d)−I\ce{-I}
    1. (1)c << b << d << a
    2. (2)c << a << b << d
    3. (3)d << b << a << c
    4. (4)a << b << c << d
  14. Q14 · MCQ · HydrocarbonsOpen
    An alkene (X) on ozonolysis followed by reduction gives following products.
    The alkene (X) is :
    1. (1)
    2. (2)
    3. (3)
    4. (4)
  15. Match the List-I with List-II
    List_IList-II
    Name of reactionReagent or catalyst used
    A.Finkelstein reactionI.SbFX3\ce{SbF3}
    B.Swarts reactionII.Na, dry ether
    C.Sandmeyer's reactionIII.NaI
    D.Fittig reactionIV.CuX2ClX2\ce{Cu2Cl2}
    Choose the correct answer from the options given below :
    1. (1)A-I, B-IV, C-III, D-III
    2. (2)A-III, B-I, C-IV, D-II
    3. (3)A-IV, B-II, C-I, D-III
    4. (4)A-I, B-III, C-II D-IV
    We corrected a printing error in the original paper

    Source printed “Fitting reaction” in List-I (D).

  16. Amongst the following, the total number of compounds soluble in aqueous NaOH at room temperature is:
    1. (1)5
    2. (2)4
    3. (3)6
    4. (4)3
  17. Q17 · MCQ · AminesOpen
    Product C of the following reaction sequence will be
    1. (1)1-Bromo-4-nitrobenzene
    2. (2)1,3,5-Tribromo-2-nitrobenzene
    3. (3)4-Bromo-1-nitrobenzene
    4. (4)1,3,5-Tribromobenzene
  18. Q18 · MCQ · BiomoleculesOpen
    Statement-I : The structure of Maltose is given below :

    Maltose is a non reducing sugar

    Statement-II : The structure of Lactose is given below

    Lactose is a reducing sugar

    In the light of the above statements, choose the correct answer from the options given below

    1. (1)Both Statement I and Statement II are true
    2. (2)Both Statement I and Statement II are false
    3. (3)Statement I is true but Statement II is false
    4. (4)Statement I is false but Statement II is true
  19. Q19 · MCQ · BiomoleculesOpen
    Match the LIST-I with LIST-II :
    List-IList-II
    Name ofOne letter
    amino acidsymbol/type)
    AArginineI.D / Non-essential
    BAspartic acidII.R / Essential
    CLysineIII.E / Non-essential
    DGlutamic acidIV.K/Essential
    Choose the correct answer from the options given below :
    1. (1)A-II, B-I, C-IV, D-III
    2. (2)A-IV, B-III, C-II, D-I
    3. (3)A-III, B-IV, C-I, D-II
    4. (4)A-II, B-IV, C-I, D-III
  20. Q20 · MCQ · EquilibriumOpen
    Identify the colour of compound ‘X' in the sequence of the reaction.
    1. (1)Violet
    2. (2)Green
    3. (3)Red
    4. (4)Colourless
  21. Q21 · Numerical · Chemical BondingOpen
    According to Lewis theory, the total number of σ\sigma bond-pairs and lone pair of electrons around the central atom of XeOX6X4−\ce{XeO6^4-} ion is .
  22. Consider the following sequence of reactions to give the major product (X)

    P g of the major product (X) formed is reacted with NaHCOX3\ce{NaHCO3} solution to liberate a gas which occupied 11.2 dm3^3 at STP.

    P == g.

    (Given molar mass in g mol−1^{-1} H : 1, C : 12, O : 16, Cl : 35.5)

    We corrected a printing error in the original paper

    Source printed “NaHCOX3\ce{NaHCO3}soluion”.

  23. 2.0 g of a bromo hydrocarbon (X) was subjected to Carius analysis, gave 3.36 g of AgBr. The percentage of carbon in the compound (X) is 26.7%. Total number of carbon atoms in the empirical formula for compound (X) is .

    (Given molar mass in g mol−1^{-1} H : 1, C : 12, Br : 80, Ag : 108)

  24. Q24 · Numerical · EquilibriumOpen

    The pH of a solution obtained by mixing 5 mL of 0.1 M NHX4OH\ce{NH4OH} solution with 250 mL of 0.1 M NHX4Cl\ce{NH4Cl} solution is × 10−2\times\,10^{-2}. (Nearest integer)

    Given : pKbK_\mathrm{b} (NHX4OH\ce{NH4OH}) =4.74= 4.74

    log⁡2=0.30\log 2 = 0.30

    log⁡3=0.48\log 3 = 0.48

    log⁡5=0.70\log 5 = 0.70

    We corrected a printing error in the original paper

    Source printed “The pH a solution”.

  25. Q25 · Numerical · SolutionsOpen

    A non-volatile, non-electrolyte solid solute when dissolved in 40 g of a solvent, the vapour pressure of the solvent decreased from 760 mm Hg to 750 mm Hg. If the same solution boils at 320 K, then the number of moles of the solvent present in the solution is . (Nearest integer)

    [Given : boiling point of the pure solvent =319.5= 319.5 K, KbK_\mathrm{b} of the solvent =0.3= 0.3 K kg mol−1^{-1}]

Maths

  1. Let [⋅][\cdot] denote the greatest integer function. If the domain of the function f(x)=cos⁡−1(4x+2[x]3)f(x) = \cos^{-1}\left(\dfrac{4x + 2\left[x\right]}{3}\right) is [α,β][\alpha, \beta], then 12(α+β)12(\alpha + \beta) is equal to:
    1. (1)6
    2. (2)8
    3. (3)9
    4. (4)4
  2. If the set of all solutions of ∣x2+x−9∣=∣x∣+∣x2−9∣\lvert x^2 + x - 9\rvert = \lvert x\rvert + \lvert x^2 - 9\rvert is [α,β]∪[γ,∞)[\alpha, \beta] \cup [\gamma, \infty), then (α2+β2+γ2)(\alpha^2 + \beta^2 + \gamma^2) is equal to:
    1. (1)9
    2. (2)18
    3. (3)36
    4. (4)72
  3. Let zz be a complex number such that ∣z+2∣=∣z−2∣\lvert z + 2\rvert = \lvert z - 2\rvert and arg⁡(z+3z−i)=π4\arg\left(\dfrac{z + 3}{z - i}\right) = \dfrac{\pi}{4}. Then ∣z∣2\lvert z\rvert^2 is equal to:
    1. (1)9
    2. (2)4
    3. (3)5
    4. (4)1
  4. The number of functions f:{1,2,3,4}→{a,b,c}f : \{1, 2, 3, 4\} \to \{a, b, c\}, which are not onto, is:
    1. (1)48
    2. (2)45
    3. (3)51
    4. (4)35
  5. Let S={A=[abcd]:a,b,c,d∈{0,1,2,3,4} and A2−4A+3I=0}S = \left\{A = \begin{bmatrix} a & b\\ c & d\end{bmatrix} : a, b, c, d \in \{0, 1, 2, 3, 4\} \text{ and } A^2 - 4A + 3I = 0\right\} be a set of 2×22 \times 2 matrices. Then the number of matrices in SS, for which the sum of the diagonal elements is equal to 4, is:
    1. (1)20
    2. (2)17
    3. (3)21
    4. (4)19
  6. Let A=[112−201135].A = \begin{bmatrix} 1 & 1 & 2\\ -2 & 0 & 1\\ 1 & 3 & 5\end{bmatrix}. Then the sum of all elements of the matrix adj⁡(adj⁡(2(adj⁡A)−1))\operatorname{adj}(\operatorname{adj}(2(\operatorname{adj}A)^{-1})) is equal to:
    1. (1)3
    2. (2)4
    3. (3)−4-4
    4. (4)−3-3
  7. The first term of an A.P. of 30 non-negative terms is 103\dfrac{10}{3}. If the sum of this A.P. is the cube of its last term, then its common difference is:
    1. (1)587\dfrac{5}{87}
    2. (2)2583\dfrac{25}{83}
    3. (3)1529\dfrac{15}{29}
    4. (4)529\dfrac{5}{29}
  8. The number of ways, of forming a queue of 4 boys and 3 girls such that all the girls are not together, is:
    1. (1)5040
    2. (2)3050
    3. (3)3410
    4. (4)4320
  9. Let the smallest value of k∈Nk \in \mathbb{N}, for which the coefficient of x3x^3 in (1+x)3+(1+x)4+(1+x)5+…+(1+x)99+(1+kx)100(1 + x)^3 + (1 + x)^4 + (1 + x)^5 + \ldots + (1 + x)^{99} + (1 + kx)^{100}, x≠0x \neq 0, is (43n+1014)(100C3)\left(43n + \dfrac{101}{4}\right)\left({}^{100}C_3\right) for some n∈Nn \in \mathbb{N}, be pp. Then the value of p+np + n is:
    1. (1)10
    2. (2)11
    3. (3)12
    4. (4)13
  10. Q10 · MCQ · StatisticsOpen
    Suppose that the mean and median of the non-negative numbers 21, 8, 17, aa, 51, 103, bb, 13, 67, (a>b)(a > b), are 40 and 21, respectively. If the mean deviation about the median is 26, then 2a2a is equal to:
    1. (1)109
    2. (2)117
    3. (3)161
    4. (4)131
  11. Q11 · MCQ · Straight LinesOpen
    Let the line L1:x+3=0L_1 : x + 3 = 0 intersect the lines L2:x−y=0L_2 : x - y = 0 and L3:3x+y=0L_3 : 3x + y = 0 at the points AA and BB, respectively. Let the bisector of the obtuse angle between the lines L2L_2 and L3L_3 intersect the line L1L_1 at the point CC. Then BC2:AC2BC^2 : AC^2 is equal to:
    1. (1)5:15 : 1
    2. (2)1:51 : 5
    3. (3)2:32 : 3
    4. (4)3:23 : 2
  12. Q12 · MCQ · Straight LinesOpen
    Let the vertex AA of a triangle ABCABC be (1,2)(1, 2), and the mid-point of the side ABAB be (5,−1)(5, -1). If the centroid of this triangle is (3,4)(3, 4) and its circumcenter is (α,β)(\alpha, \beta), then 21(α+β)21(\alpha + \beta) is equal to:
    1. (1)309
    2. (2)403
    3. (3)497
    4. (4)524
  13. Q13 · MCQ · CirclesOpen
    Suppose the two chords, drawn from the point (1,2)(1, 2) on the circle x2+y2+x−3y=0x^2 + y^2 + x - 3y = 0 are bisected by the yy-axis. If the other ends of these chords are RR and SS, and the mid point of the line segment RSRS is (α,β)(\alpha, \beta), then 6(α+β)6(\alpha + \beta) is equal to:
    1. (1)1
    2. (2)3
    3. (3)4
    4. (4)6
  14. Q14 · MCQ · 3D GeometryOpen
    A line with direction ratios 1,−1,21, -1, 2 intersects the lines x2=y3=z+13\dfrac{x}{2} = \dfrac{y}{3} = \dfrac{z + 1}{3} and x+1−1=y−21=z4\dfrac{x + 1}{-1} = \dfrac{y - 2}{1} = \dfrac{z}{4} at the points PP and QQ, respectively. If the length of the line segment PQPQ is α\alpha, then 225α2225\alpha^2 is equal to:
    1. (1)1024
    2. (2)1014
    3. (3)1104
    4. (4)1204
  15. Q15 · MCQ · 3D GeometryOpen
    The square of the distance of the point (−2,−8,6)(-2, -8, 6) from the line x−11=y−12=z−1\dfrac{x - 1}{1} = \dfrac{y - 1}{2} = \dfrac{z}{-1} along the line x+51=y+5−1=z2\dfrac{x + 5}{1} = \dfrac{y + 5}{-1} = \dfrac{z}{2} is equal to:
    1. (1)3
    2. (2)6
    3. (3)8
    4. (4)12
  16. If y=tan⁡−1(3cos⁡x−4sin⁡x4cos⁡x+3sin⁡x)+2tan⁡−1(x1+1−x2)y = \tan^{-1}\left(\dfrac{3\cos x - 4\sin x}{4\cos x + 3\sin x}\right) + 2\tan^{-1}\left(\dfrac{x}{1 + \sqrt{1 - x^2}}\right), then dydx\dfrac{dy}{dx} at x=32x = \dfrac{\sqrt3}{2} is equal to:
    1. (1)3
    2. (2)−1-1
    3. (3)1
    4. (4)2
  17. Let ff be a real polynomial of degree nn such that f(x)=f′(x) f′′(x)f(x) = f'(x)\,f''(x), for all x∈Rx \in \mathbb{R}. If f(0)=0f(0) = 0, then 36(f′(2)+f′′(2)+∫02f(x) dx)36\left(f'(2) + f''(2) + \displaystyle\int_0^2 f(x)\,dx\right) is equal to:
    1. (1)42
    2. (2)46
    3. (3)56
    4. (4)66
  18. The area of the region {(x,y):y≤π−∣x∣, y≤∣xsin⁡x∣, y≥0}\{(x, y) : y \le \pi - \lvert x\rvert,\ y \le \lvert x\sin x\rvert,\ y \ge 0\} is:
    1. (1)1+π281 + \dfrac{\pi^2}{8}
    2. (2)2+π242 + \dfrac{\pi^2}{4}
    3. (3)π28−1\dfrac{\pi^2}{8} - 1
    4. (4)4+π224 + \dfrac{\pi^2}{2}
  19. Let ∫−22(∣sin⁡x∣+[xsin⁡x])dx=2(3−cos⁡2)+β\displaystyle\int_{-2}^{2}\left(\lvert\sin x\rvert + [x\sin x]\right)dx = 2(3 - \cos 2) + \beta, where [⋅][\cdot] is the greatest integer function. Then βsin⁡(β2)\beta\sin\left(\dfrac{\beta}{2}\right) equals.
    1. (1)1
    2. (2)2
    3. (3)4
    4. (4)8
  20. Let y=y(x)y = y(x) be the solution of the differential equation dydx=(1+x+x2)(1−y+y2)\dfrac{dy}{dx} = (1 + x + x^2)(1 - y + y^2), y(0)=12y(0) = \dfrac12. Then (2y(1)−1)(2y(1) - 1) is equal to
    1. (1)3tan⁡(1136)\sqrt3\tan\left(\dfrac{11\sqrt3}{6}\right)
    2. (2)32tan⁡(11312)\dfrac{\sqrt3}{2}\tan\left(\dfrac{11\sqrt3}{12}\right)
    3. (3)3tan⁡(11312)\sqrt3\tan\left(\dfrac{11\sqrt3}{12}\right)
    4. (4)32tan⁡(1136)\dfrac{\sqrt3}{2}\tan\left(\dfrac{11\sqrt3}{6}\right)

    Flawed question. Ill-posed: the solution with y(0)=1/2y(0) = 1/2 blows up near x=0.99x = 0.99 (its arctangent would have to reach 113/12>π/211\sqrt3/12 > \pi/2), so y(1)y(1) does not exist; the keyed (3) is only a formal value (about −102-102, impossible for an increasing yy starting at 1/21/2), and no minimal change gives a valid question with these options. It is shown for completeness and is left out of practice tests.

  21. Q21 · Numerical · ProbabilityOpen
    A coin is tossed 8 times. If the probability that exactly 4 heads appear in the first six tosses and exactly 3 heads appear in the last five tosses is pp, then 96p96p is equal to .
  22. Q22 · Numerical · Conic SectionsOpen
    Consider the parabola P:y2=4kxP : y^2 = 4kx and the ellipse E:x2a2+y2b2=1E : \dfrac{x^2}{a^2} + \dfrac{y^2}{b^2} = 1. Let the line segment joining the points of intersection of PP and EE, be their latus rectums. If the eccentricity of EE is ee, then e2+22e^2 + 2\sqrt2 is equal to .
  23. Q23 · Numerical · TrigonometryOpen
    If A=sin⁡3∘cos⁡9∘+sin⁡9∘cos⁡27∘+sin⁡27∘cos⁡81∘A = \dfrac{\sin 3^\circ}{\cos 9^\circ} + \dfrac{\sin 9^\circ}{\cos 27^\circ} + \dfrac{\sin 27^\circ}{\cos 81^\circ} and B=tan⁡81∘−tan⁡3∘B = \tan 81^\circ - \tan 3^\circ, then BA\dfrac{B}{A} is equal to .
  24. Q24 · Numerical · TrigonometryOpen
    Let a⃗k=(tan⁡θk)i^+j^\vec a_k = (\tan\theta_k)\hat i + \hat j and b⃗k=i^−(cot⁡θk)j^\vec b_k = \hat i - (\cot\theta_k)\hat j, where θk=2k−1π2n+1\theta_k = \dfrac{2^{k-1}\pi}{2^n + 1}, for some n∈Nn \in \mathbb{N}, n>5n > 5. Then the value of ∑k=1n∣a⃗k∣2∑k=1n∣b⃗k∣2\dfrac{\displaystyle\sum_{k=1}^{n}\lvert\vec a_k\rvert^2}{\displaystyle\sum_{k=1}^{n}\lvert\vec b_k\rvert^2} is .
    We corrected a printing error in the original paper

    Source printed “b⃗k=i^−(cos⁡θk)j^\vec b_k = \hat i - (\cos\theta_k)\hat j”; corrected to the intended “(cot⁡θk)j^(\cot\theta_k)\hat j” (with cos⁡\cos the ratio depends on nn, e.g. 166.5 for n=6n = 6, and is never 3; with cot⁡\cot it is 3 for every nn, as the key and the source's solution use).

  25. The number of points, at which the function f(x)=max⁡{6x,2+3x2}+∣x−1∣cos⁡∣x2−14∣f(x) = \max\{6x, 2 + 3x^2\} + \lvert x - 1\rvert\cos\left\lvert x^2 - \dfrac14\right\rvert, x∈(−π,π)x \in (-\pi, \pi), is not differentiable, is .
    We corrected a printing error in the original paper

    Source printed “fucntion”.