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MathsJEE Main 4 Apr 2026, Shift 1·Q23·Numerical·Moderate

Trigonometry · Telescoping trigonometric sums

If A=sin⁡3∘cos⁡9∘+sin⁡9∘cos⁡27∘+sin⁡27∘cos⁡81∘A = \dfrac{\sin 3^\circ}{\cos 9^\circ} + \dfrac{\sin 9^\circ}{\cos 27^\circ} + \dfrac{\sin 27^\circ}{\cos 81^\circ} and B=tan⁡81∘−tan⁡3∘B = \tan 81^\circ - \tan 3^\circ, then BA\dfrac{B}{A} is equal to .

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