PhysicsJEE Main 4 Apr 2026, Shift 1·Q11·MCQ·Easy–moderate

Kinetic Theory of Gases · Gas laws and molecular picture

An ideal gas undergoes a process maintaining relation between pressure (

P

) and volume (

V

) as

P = P_o\left(1 + \left(\dfrac{V_o}{V}\right)^{2}\right)^{-1}

, where

P_o

and

V_o

are constants. If two samples A and B (two moles each) with initial volume

V_o

and

3V_o

respectively undergo above mentioned process, then the difference of the initial temperatures of these samples,

T_B - T_A

is
(

R

= gas constant)

(1) $\dfrac{9P_oV_o}{8R}$
(2) $\dfrac{11P_oV_o}{10R}$
(3) $\dfrac{7P_oV_o}{6R}$
(4) $\dfrac{13P_oV_o}{11R}$

We corrected a printing error in the original paper

Source printed “undergo above mentioned process and attain same pressure, then the difference at the temperatures”; corrected to the intended “undergo above mentioned process, then the difference of the initial temperatures” (two samples on the same $P(V)$ curve at the same pressure would have equal temperatures; the key is $T_B - T_A$ at $V_o$ and $3V_o$ ).

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Kinetic Theory of Gases · Gas laws and molecular picture

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