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MathsJEE Main 4 Apr 2026, Shift 2·Q2·MCQ·Easy–moderate

Complex Numbers · Modulus of complex numbers

Let S={z∈C:z2+4z+16=0}S = \{z \in \mathbb{C} : z^2 + 4z + 16 = 0\}. Then ∑z∈S∣z+3 i∣2\displaystyle\sum_{z\in S}\left\lvert z + \sqrt3\,i\right\rvert^2 is equal to:
  1. (1)42
  2. (2)23
  3. (3)27
  4. (4)38

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