AktiraAktira JEE
JEE Main 2026

JEE Main 4 Apr 2026, Shift 2

75 questions. Answers are hidden — tap “Show answer” under each one.

Physics

  1. Match the LIST-I with LIST-II
    List-IList-II
    A.Planck's constantI.ML2T−2\mathrm{ML^2T^{-2}}
    B.Stopping potentialII.T−1\mathrm{T^{-1}}
    C.Work functionIII.ML2T−1\mathrm{ML^2T^{-1}}
    D.Threshold frequencyIV.ML2T−3A−1\mathrm{ML^2T^{-3}A^{-1}}
    Choose the correct answer from the options given below:
    1. (1)(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
    2. (2)(A)-(I), (B)-(II), (C)-(III), (D)-(IV)
    3. (3)(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
    4. (4)(A)-(I), (B)-(IV), (C)-(III), (D)-(II)
  2. Two cars A and B are moving in the same direction along a straight line with speeds 100 km/h and 80 km/h, respectively such that car A is moving ahead of car B. A person in car B throws a stone with a speed vv so that it hits the car A with a speed of 5 m/s. The value of vv is km/h.
    1. (1)18
    2. (2)28
    3. (3)38
    4. (4)48
  3. At t=0t = 0, a body of mass 100 g starts moving under the influence of a force (5i^+10j^)(5\hat i + 10\hat j) N. After 2 s its position is (2xi^+5yj^)(2x\hat i + 5y\hat j) m. The ratio x:yx : y is .
    1. (1)1:21 : 2
    2. (2)2:52 : 5
    3. (3)5:25 : 2
    4. (4)5:45 : 4
  4. If xx and yy coordinates of a projectile as a function of time (tt) are given as 24t24t and 43.6t−4.9t243.6t - 4.9t^2, respectively, then the angle (in degrees) made by the projectile with horizontal when t=2t = 2 s is .
    1. (1)60
    2. (2)45
    3. (3)30
    4. (4)75
  5. Q5 · MCQ · GravitationOpen
    The height in terms of radius of the earth (RR), at which the acceleration due to gravity becomes g9\dfrac{g}{9}, where gg is acceleration due to gravity on earth's surface, is .
    1. (1)3R\sqrt3 R
    2. (2)22R2\sqrt2 R
    3. (3)2R2R
    4. (4)49R\dfrac49 R
  6. A metal string A is suspended from a rigid support and its free end is attached to a block of mass MM. Second block having mass 2M2M is suspended at the bottom of the first block using a string B. The area of cross sections of strings A and B are same. The ratio of lengths of strings of A to B is 2 and the ratio of their Young's moduli (YA/YBY_A/Y_B) is 0.5. The ratio of elongations in A to B is .
    1. (1)1
    2. (2)4
    3. (3)8
    4. (4)6
  7. A water spray gun is attached to a hose of cross sectional area 30 cm230\ \mathrm{cm^2}. The gun comprises of 10 perforations each of cross sectional area of 15 mm215\ \mathrm{mm^2}. If the water flows in the hose with the speed of 50 cm/s, calculate the speed at which the water flows out from each perforation. (Neglect any edge effects)
    1. (1)100 m/s
    2. (2)10 m/s
    3. (3)1000 m/s
    4. (4)15×10215\times10^{2} m/s
  8. Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R

    Assertion A: If the average kinetic energy of H2\mathrm{H_2} and O2\mathrm{O_2} molecules, kept in two different sized containers are same, then their temperatures will be same.

    Reason R: The r.m.s. speed of H2\mathrm{H_2} and O2\mathrm{O_2} molecules are same at same temperature.

    Choose the correct answer from the options given below

    1. (1)Both A and R are true and R is the correct explanation of A
    2. (2)Both A and R are true but R is NOT the correct explanation of A
    3. (3)A is true but R is false
    4. (4)A is false but R is true
  9. The temperature of a metal strip having coefficient of linear expansion α\alpha is increased from T1T_1 to T2T_2 resulting in increase of its length by ΔL1\Delta L_1. The temperature is further increased from T2T_2 to T3T_3 such that the increase in its length is ΔL2\Delta L_2.

    Given T3+T1=2T2T_3 + T_1 = 2T_2 and T2−T1=ΔTT_2 - T_1 = \Delta T, the value of ΔL2\Delta L_2 is .

    1. (1)ΔL1[1+2α2(ΔT)2]\Delta L_1[1 + 2\alpha^2(\Delta T)^2]
    2. (2)ΔL1[1+α2(ΔT)2]\Delta L_1[1 + \alpha^2(\Delta T)^2]
    3. (3)ΔL1[1+2α ΔT]\Delta L_1[1 + 2\alpha\,\Delta T]
    4. (4)ΔL1[1+α ΔT]\Delta L_1[1 + \alpha\,\Delta T]
  10. Q10 · MCQ · OscillationsOpen
    A uniform disc of radius RR and mass MM is free to oscillate about the axis A as shown in the figure. For small oscillations the time period is . (gg is acceleration due to gravity)
    1. (1)2π5R4g2\pi\sqrt{\dfrac{5R}{4g}}
    2. (2)2π2R3g2\pi\sqrt{\dfrac{2R}{3g}}
    3. (3)2π3R2g2\pi\sqrt{\dfrac{3R}{2g}}
    4. (4)2π3Rg2\pi\sqrt{\dfrac{3R}{g}}
  11. A rigid dipole undergoes a simple harmonic motion about its centre in the presence of an electric field E⃗1=E0x^\vec E_1 = E_0\hat x. If another electric field E⃗2=2E0(y^+z^)\vec E_2 = 2E_0(\hat y + \hat z) is introduced to the system, what will be the percentage change in the frequency of the oscillation (approximate)?
    1. (1)73%
    2. (2)63%
    3. (3)83%
    4. (4)53%
  12. From the circuit given below, the capacitance between terminals A and B shown in the circuit is μ\muF. (take C1=C2=C3=1 μC_1 = C_2 = C_3 = 1\ \muF and C4=2 μC_4 = 2\ \muF.)
    1. (1)2
    2. (2)7/2
    3. (3)7/3
    4. (4)5/2
    We corrected a printing error in the original paper

    Answer corrected; the source key is (2) — the top wire joins A to the C2C_2/C3C_3 junction, so C1∥C2=2 μC_1 \parallel C_2 = 2\ \muF in series with C4=2 μC_4 = 2\ \muF gives 1 μ1\ \muF, plus C3=1 μC_3 = 1\ \muF across A–B: CAB=2 μC_{AB} = 2\ \muF (the source's own solution also ends at 2 μ2\ \muF).

  13. Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R

    Assertion A: In electrostatics, a conductor does not store any net charge inside.

    Reason R: Inside the capacitor (with no dielectric medium), the free charge carriers, if placed between the plates of capacitor, experience force and drift.

    Choose the correct answer from the options given below.

    1. (1)Both A and R are true and R is the correct explanation of A.
    2. (2)Both A and R are true but R is NOT the correct explanation of A.
    3. (3)A is true but R is false
    4. (4)A is false but R is true
  14. A solenoid has a core made of material with relative permeability 400. The magnetic field produced in the interior of solenoid is 1.0 T. The magnetic intensity in SI units is α×105\alpha\times10^{5}. The value of α\alpha is . (Free space permeability μ0=4π×10−7\mu_0 = 4\pi\times10^{-7} SI units).
    1. (1)25π\dfrac{25}{\pi}
    2. (2)116π\dfrac{1}{16\pi}
    3. (3)1π\dfrac{1}{\pi}
    4. (4)14π\dfrac{1}{4\pi}
    We corrected a printing error in the original paper

    Source printed “The magnetic intensity is SI units”.

  15. A magnetic field vector in an electromagnetic wave is represented by, B⃗=B0sin⁡(2πνt−2πxλ)j^.\vec B = B_0\sin\left(2\pi\nu t - \frac{2\pi x}{\lambda}\right)\hat j. Its associated electric field vector is .
    1. (1)E⃗=−νλB0sin⁡(2πνt−2πxλ)k^\vec E = -\nu\lambda B_0\sin\left(2\pi\nu t - \dfrac{2\pi x}{\lambda}\right)\hat k
    2. (2)E⃗=−νλB0sin⁡(2πνt−2πxλ)i^\vec E = -\nu\lambda B_0\sin\left(2\pi\nu t - \dfrac{2\pi x}{\lambda}\right)\hat i
    3. (3)E⃗=νλB0sin⁡(2πνt−2πxλ)k^\vec E = \nu\lambda B_0\sin\left(2\pi\nu t - \dfrac{2\pi x}{\lambda}\right)\hat k
    4. (4)E⃗=νλB0sin⁡(2πνt−2πxλ)i^\vec E = \nu\lambda B_0\sin\left(2\pi\nu t - \dfrac{2\pi x}{\lambda}\right)\hat i
    We corrected a printing error in the original paper

    Source printed the frequency as a Latin “v” (2πvt2\pi\mathrm{v}t, vλB0\mathrm{v}\lambda B_0) instead of ν\nu.

  16. Q16 · MCQ · Ray OpticsOpen
    A convex lens is made from glass material having refractive index of 1.4 with same radius of curvature on both sides. The ratio of its focal length and radius of curvature is .
    1. (1)0.5
    2. (2)2.5
    3. (3)0.8
    4. (4)1.25
  17. Q17 · MCQ · Wave OpticsOpen
    An unpolarized light of certain intensity passes through a combination of two polarizers whose transmission axes are at 30∘30^\circ and 90∘90^\circ, respectively, with respect to the horizontal axis. A third polarizer with its transmission axis at 60∘60^\circ with the horizontal axis is placed between the two existing polarizers. The ratio of the output intensities with and without the third polarizer is .
    1. (1)3/4
    2. (2)4/3
    3. (3)9/4
    4. (4)4/9
  18. Q18 · MCQ · AtomsOpen

    In Rutherford's alpha-particle scattering experiment, only a few alpha particles rebound back because

    (A) The size of gold nucleus is very small as compared to the size of gold atom.

    (B) Alpha particle and gold nucleus have equal charge.

    (C) The impact parameter is minimum for a few alpha particles.

    (D) A few alpha particles have very high kinetic energy.

    (E) Only a few alpha particles undergo head-on collision with the nuclei.

    Choose the correct answer from the options given below:

    1. (1)A, B Only
    2. (2)B, E Only
    3. (3)C, D Only
    4. (4)A, C, E Only
  19. The de Broglie wavelength associated with an electron accelerated through a potential difference VV is λe\lambda_e and the de Broglie wavelength associated with a proton accelerated through the same potential difference is λp\lambda_p. If their corresponding masses are mem_e and mpm_p, respectively, then the ratio of their de Broglie wavelengths (λeλp)\left(\dfrac{\lambda_e}{\lambda_p}\right) is .
    1. (1)mpme\sqrt{\dfrac{m_p}{m_e}}
    2. (2)memp\sqrt{\dfrac{m_e}{m_p}}
    3. (3)mpme\dfrac{m_p}{m_e}
    4. (4)(mpme)2\left(\dfrac{m_p}{m_e}\right)^2
  20. Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R

    Assertion A: A diode under reverse-biased condition provides very small current which is nearly independent of voltage until a critical limit at which the current increases drastically.

    Reason R: Below the critical voltage limit, only majority charge carriers flow which increases drastically above critical voltage.

    Choose the correct answer from the options given below.

    1. (1)Both A and R are true and R is the correct explanation of A.
    2. (2)Both A and R are true but R is NOT the correct explanation of A.
    3. (3)A is true but R is false
    4. (4)A is false but R is true
  21. Q21 · Numerical · Semiconductor ElectronicsOpen
    A diode has Zener voltage of 10 V and maximum power dissipation of 0.5 W, then the minimum resistance to be used in series with this diode for safety when it is connected to a 25 V power supply is Ω\Omega.
  22. Q22 · Numerical · Motion in a PlaneOpen
    A gun mounted on the ground fires bullets in all directions with same speed. The farthest distance the bullets could reach is 6.4 m. The speed of the bullets from the gun is m/s. (take g=10 m/s2g = 10\ \mathrm{m/s^2})
  23. Q23 · Numerical · Magnetism and MatterOpen
    Two identical small bar magnets each of dipole moment 35 J/T3\sqrt5\ \mathrm{J/T} are placed at a center to center separation of 10 cm, with their axes perpendicular to each other as shown in figure. The value of magnetic field at the point P midway between the magnets is α×10−3\alpha\times10^{-3} T. The value of α\alpha is . (μ0=4π×10−7\mu_0 = 4\pi\times10^{-7} Tm/A)
  24. A circular coil of radius 2 cm and 125 turns carries a current of 1 A. The coil is placed in a uniform magnetic field of magnitude 0.4 T. The axis of the coil makes an angle of 30∘30^\circ with the direction of the magnetic field. The torque acting on the coil is α×10−4\alpha\times10^{-4} N.m. The value of α\alpha is . (π=3.14\pi = 3.14)
  25. Q25 · Numerical · Wave OpticsOpen
    In a double slit experiment, when one of the slits is covered by a transparent mica sheet of refractive index 1.56, the central fringe shifts to the position of 7th7^{\text{th}} bright fringe, obtained with both slits uncovered. If the light source wavelength is 450 nm, the thickness of mica sheet is α×10−9\alpha\times10^{-9} m. The value of α\alpha is .

Chemistry

  1. The correct order of total number of atoms present in
    • (A)2 moles of cyclohexane
    • (B)684 g of sucrose
    • (C)90.8 L of dihydrogen at STP
    1. (1)C >> A >> B
    2. (2)C >> B >> A
    3. (3)B >> C >> A
    4. (4)B >> A >> C
    We corrected a printing error in the original paper

    Answer corrected; the source key is (3) — (A) 2 mol C6_6H12_{12} = 36 mol atoms, (B) 684 g sucrose = 2 mol = 90 mol atoms, (C) 90.8 L H2_2 = 4 mol = 8 mol atoms, so B >> A >> C; also source printed “total number of atoms of present in” and option (4) “B >> A C”.

  2. The species having identical radii according to the Bohr's theory are :
    • (A)H (first orbit)
    • (B)HeX+\ce{He+} (first orbit)
    • (C)HeX+\ce{He+} (second orbit)
    • (D)LiX2+\ce{Li^2+} (first orbit)
    • (E)BeX3+\ce{Be^3+} (Second orbit)
    Choose the correct answer from the options given below :
    1. (1)A and C Only
    2. (2)A and E Only
    3. (3)B and E Only
    4. (4)C and D Only
  3. Which of the following pictorial diagram most correctly represents the π∗\pi^* (π\pi – antibonding) molecular orbital between two atoms if the internuclear axis is taken to be in the z-direction (→z–axis\xrightarrow{\text{z--axis}}) ?
    1. (1)
    2. (2)
    3. (3)
    4. (4)
  4. Q4 · MCQ · SolutionsOpen
    At 27∘^\circC, 0.1 M, 1 L KX4[Fe(CN)X6]\ce{K4[Fe(CN)6]} aqueous solution and 0.1 M, 1 L FeClX3\ce{FeCl3} aqueous solution are placed in a container separated by a semi permeable membrane AB. Assume complete dissociation of both the solutes. Which of the following statement is correct ?
    1. (1)Blue color is formed on both sides.
    2. (2)Ionic solutes in aqueous solution can pass through semi-permeable membrane.
    3. (3)Solution on side ‘y' is hypotonic.
    4. (4)To cause the reverse flow of solvent during osmosis, external pressure (any value) should be applied to side ‘x'.
  5. Q5 · MCQ · EquilibriumOpen
    20 mL of a solution of acetic acid required 28.4 mL of 0.1 M NaOH for its neutralization. A solution (X) was prepared by mixing 20 mL of the above acetic acid and 14.2 mL of 0.1 M NaOH solution. What is the pH of the solution (X) ? (pKa\mathrm{p}K_\mathrm{a} value of acetic acid is 4.75).
    1. (1)7.0
    2. (2)4.75
    3. (3)3.5
    4. (4)4.82
    We corrected a printing error in the original paper

    Source printed option (2) as “4.45” (no option was then correct); corrected to the intended “4.75” — 14.2 mL is exactly half the 28.4 mL needed, so pH = pKaK_\mathrm{a} = 4.75 (source key (2)).

  6. Match the LIST-I with LIST-II
    List-IList-II
    ReactionMechanism
    A.Williamson SynthesisI.Electrophilic addition
    B.Friedel Crafts ReactionII.Free radical substitution
    C.Bromination of vinyl benzeneIII.Nucleophilic substitution
    D.Chlorination of toluene in lightIV.Electrophilic substitution
    Choose the correct answer from the options given below:
    1. (1)A-III, B-I, C-II, D-IV
    2. (2)A-III, B-IV, C-II, D-I
    3. (3)A-III, B-IV, C-I, D-II
    4. (4)A-I, B-III, C-IV, D-II
    We corrected a printing error in the original paper

    Source printed “Friedel Craft Reaction”.

  7. The 1st^\mathrm{st} ionization enthalpy for Mg is +737+737 kJ/mol. The most probable estimated value of the 2nd^\mathrm{nd} ionization enthalpy of Mg is .
    1. (1)−906-906 kJ/mol
    2. (2)−856-856 kJ/mol
    3. (3)+1450+1450 kJ/mol
    4. (4)+590+590 kJ/mol
  8. The electronegativity of a group 13 element ‘E' is same as that of Ge (on Pauling scale and upto one decimal point). The CORRECT statements about EX3+\ce{E^3+} are
    • (A)It can act as a reducing agent.
    • (B)It can act as an oxidizing agent.
    • (C)EX3+\ce{E^3+} is more stable than EX+\ce{E+}.
    • (D)The standard electrode potential value for EX3+\ce{E^3+}/E is positive.
    Choose the correct answer from the options given below
    1. (1)A and C Only
    2. (2)B and C Only
    3. (3)B and D Only
    4. (4)A and D Only
  9. Q9 · MCQ · d- and f-BlockOpen

    Pairs of elements with the same number of electrons in their respective 4f orbital are

    [Atomic number, Eu-63, Gd-64, Dy-66, Ho-67, Tm-69, Yb-70, Lu-71, Hf-72]

    • (A)(Eu and Gd)
    • (B)(Dy and Ho)
    • (C)(Yb and Hf)
    • (D)(Lu and Tm)
    Choose the correct answer from the options given below:
    1. (1)B and C Only
    2. (2)A and B Only
    3. (3)A and D Only
    4. (4)A and C Only
  10. Consider the metal complexes [Ni(en)X3]X2+\ce{[Ni(en)3]^2+} (A), [NiClX4]X2−\ce{[NiCl4]^2-} (B) and [Ni(NHX3)X6]X2+\ce{[Ni(NH3)6]^2+} (C). Choose the CORRECT option by considering the number of unpaired electron present in (A), (B) and (C) respectively and the order of frequency of absorption.
    1. (1)2, 2, 2 and (A) >> (C) >> (B)
    2. (2)0, 2, 0 and (A) >> (C) >> (B)
    3. (3)2, 2, 0 and (B) >> (C) >> (A)
    4. (4)2, 2, 2 and (C) >> (A) >> (B)
  11. Consider the following molecules/species:
    The correct order of carbon – oxygen double bond length is:
    1. (1)x >> y >> z
    2. (2)y >> z >> x
    3. (3)z >> x >> y
    4. (4)x >> z >> y
    We corrected a printing error in the original paper

    In structure (y) the source printed the lower group as “CH”; corrected in the figure to “CH3_3” (propanone), the subscript copied from the upper CH3_3 of the same drawing.

  12. Q12 · MCQ · d- and f-BlockOpen
    Consider ∣x∣\lvert x\rvert is the difference in oxidation states of Mn in highest manganese fluoride and highest manganese oxide. The ions with ∣x∣\lvert x\rvert number of unpaired electrons from the following are:
    • (A)ScX3+\ce{Sc^3+}
    • (B)ZnX2+\ce{Zn^2+}
    • (C)VX2+\ce{V^2+}
    • (D)FeX2+\ce{Fe^2+}
    • (E)CoX2+\ce{Co^2+}
    Choose the correct answer from the options given below:
    1. (1)A and B Only
    2. (2)C, D and E Only
    3. (3)C and E Only
    4. (4)B and E Only
  13. Consider the given graph showing variation of reactant concentration with time.

    Three different reactions were started with identical initial concentration of reactants. Which of the following statement is correct ?

    1. (1)The order of all the three reactions is same.
    2. (2)The rate constant of reaction 3 is larger than the rate constant of reaction 2 if the order of reaction is same for both.
    3. (3)The SI unit of rate constant of reaction 1 is s−1^{-1}.
    4. (4)Thermal decomposition of HI on gold surface is an example of reaction 2.
  14. Q14 · MCQ · HydrocarbonsOpen

    Compound (X) is subjected to the sequence of reactions as shown above. Molar mass of the major product (Y) formed is g mol−1^{-1}.

    (Given molar mass in g mol−1^{-1} C : 12, H : 1, O : 16)

    1. (1)90
    2. (2)118
    3. (3)160
    4. (4)125
  15. The following structures are
      and 
    1. (1)enantiomer
    2. (2)Identical molecules
    3. (3)Diastereomers
    4. (4)meso compound
  16. The descending order of acidity among the following compounds is
    (A) (B) 
    (C) (D) 
    (E) 
    Choose the correct answer from the option given below options
    1. (1)B >> D >> E >> A >> C
    2. (2)D >> B >> E >> A >> C
    3. (3)C >> A >> B >> D >> E
    4. (4)D >> E >> B >> A >> C
  17. Q17 · MCQ · AminesOpen
    The strongest conjugate acid will result from
    1. (1)
    2. (2)
    3. (3)
    4. (4)
  18. Q18 · MCQ · BiomoleculesOpen
    A D-aldotetrose on oxidation with concentrated HNOX3\ce{HNO3} resulted in optically inactive dicarboxylic acid. The structure of the D-aldotetrose is :
    1. (1)
    2. (2)
    3. (3)
    4. (4)
  19. Among FeX3+\ce{Fe^3+}, PbX2+\ce{Pb^2+}, CuX2+\ce{Cu^2+} and MnX2+\ce{Mn^2+}, identify the one that gets precipitated out while passing HX2S\ce{H2S} in presence of NHX4OH\ce{NH4OH} as group reagent. The highest possible oxidation state of the corresponding metal is
    1. (1)+3+3
    2. (2)+4+4
    3. (3)+2+2
    4. (4)+7+7
  20. Match the LIST-I with LIST-II
    List-IList-II
    CompoundTest
    A.IHinsberg's reagent test
    B.IIPhthalein dye test
    C.III.Lucas test
    D.IV.Tollen's test
    Choose the correct answer from the options given below :
    1. (1)A-III, B-I, C-IV, D-II
    2. (2)A-III, B-IV, C-I, D-II
    3. (3)A-I, B-III, C-II, D-IV
    4. (4)A-I, B-II, C-III, D-IV
  21. Q21 · Numerical · ThermodynamicsOpen

    If 3.365 g of ethanol (ll) is burnt completely in a bomb calorimeter at 298.15 K, the heat produced is 99.472 kJ. The ∣ΔHf∘∣\lvert\Delta H_\mathrm{f}^\circ\rvert of ethanol at 298.15 K is × 102\times\,10^{2} kJ mol−1^{-1}. (Nearest integer)

    Given :

    Standard enthalpy of combustion of graphite =−393.5= -393.5 kJ mol−1^{-1}

    Standard enthalpy of formation of water (ll) =−285.8= -285.8 kJ mol−1^{-1}

    Molar mass in g mol−1^{-1} of C, H, O are 12, 1 and 16 respectively.

    We corrected a printing error in the original paper

    Answer corrected; the source key is 282 — ΔUc=−1359.8\Delta U_\mathrm{c} = -1359.8 kJ mol−1^{-1}, ΔHc=−1362.3\Delta H_\mathrm{c} = -1362.3 kJ mol−1^{-1}, ΔfH=−282.1\Delta_\mathrm{f}H = -282.1 kJ mol−1^{-1} = −2.82×102-2.82\times10^{2}, so the blank before “× 102\times\,10^{2}” is 3; also source printed “If 3.365 g of ethanol (ll) burnt completely”.

  22. Q22 · Numerical · ThermodynamicsOpen

    For the following reaction at 50∘^\circC and 2 atm pressure,

    2 NX2OX5(g)⇌2 NX2OX4(g)+OX2(g)\ce{2N2O5(g) <=> 2N2O4(g) + O2(g)}

    NX2OX5\ce{N2O5} is 50% dissociated

    The magnitude of standard free energy change at this temperature is x.

    x = J mol−1^{-1} [Nearest integer]

    Given : R=8.314R = 8.314 J mol−1^{-1} K−1^{-1}, log⁡2=0.30\log 2 = 0.30, log⁡3=0.48\log 3 = 0.48, ln⁡10=2.303\ln 10 = 2.303, ∘^\circC + 273 = K

    We corrected a printing error in the original paper

    Source printed “R = 8.314 mol−1^{-1} K−1^{-1}” (unit J missing).

  23. Q23 · Numerical · ElectrochemistryOpen

    An electrochemical cell consists of the following two redox couples,

    Mx+\mathrm{M}^{x+}(aq)/M(s) [Ered⊖=+0.15E^\ominus_\mathrm{red} = +0.15 V] and

    FeX3+\ce{Fe^3+}(aq)/Fe(s) [Ered⊖=−0.036E^\ominus_\mathrm{red} = -0.036 V]

    The cell EMF (EcellE_\mathrm{cell}) is recorded to be 0.2057 V.

    If the reaction quotient of the electrochemical reaction is found to be 10−210^{-2}, then the value of x is (Nearest integer)

    [Given : M is a p-block metal and 2.303RTF=0.059\dfrac{2.303RT}{F} = 0.059 V]

    We corrected a printing error in the original paper

    Source printed “An electrochemical cell. consist of”.

  24. Q24 · Numerical · Chemical KineticsOpen
    For a first order reaction A→B\ce{A -> B}
    t/ min[A]/M
    00.6500
    x0.0650
    200.00065
    x = min. (Nearest integer)
  25. In sulphur estimation, 2.0×10−32.0\times10^{-3} mol of an organic compound (X) (molar mass 76 g mol−1^{-1}) gave 0.4813 g of barium sulphate (molar mass 233 g mol−1^{-1}). The percentage of sulphur in the compound (X) is × 10−1\times\,10^{-1}%

    (Nearest integer)

Maths

  1. For the function f:[1,∞)→[1,∞)f : [1, \infty) \to [1, \infty) defined by f(x)=(x−1)4+1f(x) = (x-1)^4 + 1, among the two statements:
    (I) The set S={x∈[1,∞):f(x)=f−1(x)}S = \{x \in [1, \infty) : f(x) = f^{-1}(x)\} contains exactly two elements, and
    (II) The set S={x∈[1,∞):f(x)=f−1(x+1)}S = \{x \in [1, \infty) : f(x) = f^{-1}(x+1)\} is an empty set,
    1. (1)only (I) is TRUE
    2. (2)only (II) is TRUE
    3. (3)both (I) and (II) are TRUE
    4. (4)neither (I) nor (II) is TRUE
  2. Let S={z∈C:z2+4z+16=0}S = \{z \in \mathbb{C} : z^2 + 4z + 16 = 0\}. Then ∑z∈S∣z+3 i∣2\displaystyle\sum_{z\in S}\left\lvert z + \sqrt3\,i\right\rvert^2 is equal to:
    1. (1)42
    2. (2)23
    3. (3)27
    4. (4)38
  3. If the system of equations: x+y+z=5x+2y+3z=9x+3y+λz=μ\begin{aligned} x + y + z &= 5\\ x + 2y + 3z &= 9\\ x + 3y + \lambda z &= \mu\end{aligned} has infinitely many solutions, then the value of λ+μ\lambda + \mu is:
    1. (1)16
    2. (2)18
    3. (3)19
    4. (4)21
  4. If α=1\alpha = 1 and β=1+i2\beta = 1 + i\sqrt2, where i=−1i = \sqrt{-1} are two roots of the equation x3+ax2+bx+c=0x^3 + ax^2 + bx + c = 0, a,b,c∈Ra, b, c \in \mathbb{R}, then ∫−11(x3+ax2+bx+c)dx\displaystyle\int_{-1}^{1}\left(x^3 + ax^2 + bx + c\right)dx is equal to:
    1. (1)−2-2
    2. (2)−4-4
    3. (3)−8-8
    4. (4)−10-10
  5. If the quadratic equation (λ+2)x2−3λx+4λ=0(\lambda + 2)x^2 - 3\lambda x + 4\lambda = 0, λ≠−2\lambda \neq -2, has two positive roots, then the number of possible integral values of λ\lambda is:
    1. (1)1
    2. (2)2
    3. (3)3
    4. (4)4
  6. Let A=[1274−2838−7]A = \begin{bmatrix} 1 & 2 & 7\\ 4 & -2 & 8\\ 3 & 8 & -7\end{bmatrix} and det⁡(A−αI)=0\det(A - \alpha I) = 0, where α\alpha is a real number. If the largest possible value of α\alpha is pp, then the circle (x−p)2+(y−2p)2=320(x-p)^2 + (y-2p)^2 = 320, intersects the co-ordinate axes at
    1. (1)1 point
    2. (2)2 points
    3. (3)3 points
    4. (4)4 points
  7. Let α=14+18+116+…∞\alpha = \dfrac14 + \dfrac18 + \dfrac1{16} + \ldots\infty and β=13+19+127+…∞\beta = \dfrac13 + \dfrac19 + \dfrac1{27} + \ldots\infty. Then the value of (0.2)log⁡5(α)+(0.04)log⁡5(β)(0.2)^{\log_{\sqrt5}(\alpha)} + (0.04)^{\log_5(\beta)} is equal to:
    1. (1)4
    2. (2)5
    3. (3)8
    4. (4)25
  8. Q8 · MCQ · StatisticsOpen
    For 10 observations x1,x2,…,x10x_1, x_2, \ldots, x_{10}, if ∑i=110(xi+2)2=180\displaystyle\sum_{i=1}^{10}(x_i + 2)^2 = 180 and ∑i=110(xi−1)2=90\displaystyle\sum_{i=1}^{10}(x_i - 1)^2 = 90, then their standard deviation is:
    1. (1)2
    2. (2)3\sqrt3
    3. (3)222\sqrt2
    4. (4)3
  9. In the expansion of (9x−13x)18\left(9x - \dfrac{1}{3\sqrt{x}}\right)^{18}, x>0x > 0, if the term independent of xx is (221)k(221)k. then kk is equal to:
    1. (1)84
    2. (2)78
    3. (3)168
    4. (4)198
  10. Q10 · MCQ · Conic SectionsOpen
    Let P(3cos⁡α,2sin⁡α)P(3\cos\alpha, 2\sin\alpha), α≠0\alpha \neq 0, be a point on the ellipse x29+y24=1\dfrac{x^2}{9} + \dfrac{y^2}{4} = 1, QQ be a point on the circle x2+y2−14x−14y+82=0x^2 + y^2 - 14x - 14y + 82 = 0 and RR be a point on the line x+y=5x + y = 5 such that the centroid of the triangle PQRPQR is (2+cos⁡α,3+23sin⁡α)\left(2 + \cos\alpha, 3 + \dfrac23\sin\alpha\right). Then the sum of the ordinates of all possible points RR is:
    1. (1)6
    2. (2)2
    3. (3)4
    4. (4)8
  11. Q11 · MCQ · Conic SectionsOpen
    Let H:x2a2−y2b2=1H : \dfrac{x^2}{a^2} - \dfrac{y^2}{b^2} = 1 be a hyperbola such that the distance between its foci is 6 and the distance between its directrices is 83\dfrac83. If the line x=αx = \alpha intersects the hyperbola HH at the points AA and BB such that the area of the triangle AOBAOB is 4154\sqrt{15}, where OO is the origin, then α2\alpha^2 equals
    1. (1)12
    2. (2)16
    3. (3)24
    4. (4)25
  12. max⁡0≤x≤π(16sin⁡(x2)cos⁡3(x2))\displaystyle\max_{0 \le x \le \pi}\left(16\sin\left(\frac{x}{2}\right)\cos^3\left(\frac{x}{2}\right)\right) is equal to:
    1. (1)332\dfrac{3\sqrt3}{2}
    2. (2)333\sqrt3
    3. (3)434\sqrt3
    4. (4)636\sqrt3
  13. Q13 · MCQ · 3D GeometryOpen
    The shortest distance between the lines r⃗=(13i^+2j^+83k^)+λ(2i^−5j^+6k^)\vec r = \left(\frac13\hat i + 2\hat j + \frac83\hat k\right) + \lambda\left(2\hat i - 5\hat j + 6\hat k\right) and r⃗=(−23i^−13k^)+μ(j^−k^)\vec r = \left(-\dfrac23\hat i - \dfrac13\hat k\right) + \mu\left(\hat j - \hat k\right), λ,μ∈R\lambda, \mu \in \mathbb{R}, is:
    1. (1)5\sqrt5
    2. (2)3
    3. (3)232\sqrt3
    4. (4)15\sqrt{15}
  14. Q14 · MCQ · 3D GeometryOpen
    If (2α+1,α2−3α,α−12)\left(2\alpha + 1, \alpha^2 - 3\alpha, \dfrac{\alpha - 1}{2}\right) is the image of (α,2α,1)(\alpha, 2\alpha, 1) in the line x−23=y−12=z1\dfrac{x-2}{3} = \dfrac{y-1}{2} = \dfrac{z}{1}, then the possible value(s) of α\alpha is(are):
    1. (1)Only 3
    2. (2)Only 3 and −1-1
    3. (3)Only 3, 14\dfrac14 and −1-1
    4. (4)Only 3 and 14\dfrac14
  15. Q15 · MCQ · VectorsOpen
    Let u^\hat u and v^\hat v be unit vectors inclined at an acute angle such that ∣u^×v^∣=32\lvert\hat u \times \hat v\rvert = \dfrac{\sqrt3}{2}. If A⃗=λu^+v^+(u^×v^)\vec A = \lambda\hat u + \hat v + (\hat u \times \hat v). Then λ\lambda is equal to:
    1. (1)43(A⃗⋅u^)−23(A⃗⋅v^)\dfrac43\left(\vec A\cdot\hat u\right) - \dfrac23\left(\vec A\cdot\hat v\right)
    2. (2)23(A⃗⋅u^)−13(A⃗⋅v^)\dfrac23\left(\vec A\cdot\hat u\right) - \dfrac13\left(\vec A\cdot\hat v\right)
    3. (3)43(A⃗⋅u^)+23(A⃗⋅v^)\dfrac43\left(\vec A\cdot\hat u\right) + \dfrac23\left(\vec A\cdot\hat v\right)
    4. (4)(A⃗⋅u^)−12(A⃗⋅v^)\left(\vec A\cdot\hat u\right) - \dfrac12\left(\vec A\cdot\hat v\right)
  16. Let for some α∈R\alpha \in \mathbb{R}, f:R→Rf : \mathbb{R} \to \mathbb{R} be a function satisfying f(x+y)=f(x)+2y2+y+αxyf(x + y) = f(x) + 2y^2 + y + \alpha xy for all x,y∈Rx, y \in \mathbb{R}. If f(0)=−1f(0) = -1 and f(1)=2f(1) = 2, then the value of ∑n=15(α+f(n))\displaystyle\sum_{n=1}^{5}\left(\alpha + f(n)\right) is:
    1. (1)110
    2. (2)140
    3. (3)150
    4. (4)170
  17. Let A={(a,b,c):a,b,cA = \{(a, b, c) : a, b, c are non-negative integers and a+b+2c=22}a + b + 2c = 22\}. The n(A)n(A) is equal to:
    1. (1)121
    2. (2)124
    3. (3)144
    4. (4)169
  18. The area of the region bounded by the curves x+3y2=0x + 3y^2 = 0 and x+4y2=1x + 4y^2 = 1 is equal to:
    1. (1)13\dfrac13
    2. (2)23\dfrac23
    3. (3)43\dfrac43
    4. (4)53\dfrac53
  19. Let y=y(x)y = y(x) be the solution of the differential equation: dydx+(6x2+(3x2+2x3+4)e−2x(x3+2)(2+e−2x))y=2+e−2x,\frac{dy}{dx} + \left(\frac{6x^2 + \left(3x^2 + 2x^3 + 4\right)e^{-2x}}{\left(x^3 + 2\right)\left(2 + e^{-2x}\right)}\right)y = 2 + e^{-2x}, x∈(−1,2)x \in (-1, 2), satisfying y(0)=32y(0) = \dfrac32. If y(1)=α(2+e−2)y(1) = \alpha\left(2 + e^{-2}\right), then α\alpha is equal to:
    1. (1)138\dfrac{13}{8}
    2. (2)613\dfrac{6}{13}
    3. (3)1213\dfrac{12}{13}
    4. (4)1312\dfrac{13}{12}
    We corrected a printing error in the original paper

    Source printed “than α\alpha is equal to”.

  20. The integral ∫01cot⁡−1(1+x+x2)dx\displaystyle\int_0^1\cot^{-1}\left(1 + x + x^2\right)dx is equal to:
    1. (1)2tan⁡−12+12log⁡e(54)+π22\tan^{-1}2 + \dfrac12\log_e\left(\dfrac54\right) + \dfrac{\pi}{2}
    2. (2)2tan⁡−12+12log⁡e(54)−π22\tan^{-1}2 + \dfrac12\log_e\left(\dfrac54\right) - \dfrac{\pi}{2}
    3. (3)2tan⁡−12−12log⁡e(54)+π22\tan^{-1}2 - \dfrac12\log_e\left(\dfrac54\right) + \dfrac{\pi}{2}
    4. (4)2tan⁡−12−12log⁡e(54)−π22\tan^{-1}2 - \dfrac12\log_e\left(\dfrac54\right) - \dfrac{\pi}{2}
  21. Q21 · Numerical · ProbabilityOpen
    From a month of 31 days, 3 different dates are selected at random. If the probability that these dates are in an increasing A.P. is equal to ab\dfrac{a}{b}, where a,b∈Na, b \in \mathbb{N} and gcd⁡(a,b)=1\gcd(a, b) = 1, then a+ba + b is equal to .
  22. Let f(x)={ex−1,x<0x2−5x+6,x≥0f(x) = \begin{cases} e^{x-1}, & x < 0\\ x^2 - 5x + 6, & x \ge 0\end{cases} and g(x)=f(∣x∣)+∣f(x)∣g(x) = f(\lvert x\rvert) + \lvert f(x)\rvert. If the number of points where gg is not continuous and is not differentiable are α\alpha and β\beta respectively, then α+β\alpha + \beta is equal to .
  23. Q23 · Numerical · Straight LinesOpen
    Let AA, BB be points on the two half-lines x−3 ∣y∣=αx - \sqrt3\,\lvert y\rvert = \alpha, α>0\alpha > 0 at a distance of α\alpha from their point of intersection PP. The line segment ABAB meets the angle bisector of the given half-lines at the point QQ. If PQ=92PQ = \dfrac92 and RR is the radius of the circumcircle of △PAB\triangle PAB, then α2R\dfrac{\alpha^2}{R} is equal to .
  24. Q24 · Numerical · Conic SectionsOpen
    Let AA, BB and CC be the vertices of a variable right angled triangle inscribed in the parabola y2=16xy^2 = 16x. Let the vertex BB containing the right angle be (4,8)(4, 8) and the locus of the centroid of △ABC\triangle ABC be a conic C0C_0. Then three times the length of latus rectum of C0C_0 is .
  25. Q25 · Numerical · Differential EquationsOpen
    Let ff be a twice differentiable function such that f(x)=∫0xtan⁡(t−x) dt−∫0xf(t)tan⁡t dt,x∈(−π2,π2)f(x) = \int_0^x\tan(t - x)\,dt - \int_0^x f(t)\tan t\,dt,\quad x \in \left(-\frac{\pi}{2}, \frac{\pi}{2}\right) Then f′′(π6)+12f′(−π6)+f(π6)f''\left(\dfrac{\pi}{6}\right) + 12f'\left(-\dfrac{\pi}{6}\right) + f\left(\dfrac{\pi}{6}\right) is equal to .