PhysicsJEE Main 4 Apr 2026, Shift 2·Q12·MCQ·Moderate

Electric Potential and Capacitance · Capacitance

From the circuit given below, the capacitance between terminals A and B shown in the circuit is

\mu

F. (take

C_1 = C_2 = C_3 = 1\ \mu

F and

C_4 = 2\ \mu

F.)

(1)2
(2)7/2
(3)7/3
(4)5/2

We corrected a printing error in the original paper

Answer corrected; the source key is (2) — the top wire joins A to the $C_2$ / $C_3$ junction, so $C_1 \parallel C_2 = 2\ \mu$ F in series with $C_4 = 2\ \mu$ F gives $1\ \mu$ F, plus $C_3 = 1\ \mu$ F across A–B: $C_{AB} = 2\ \mu$ F (the source's own solution also ends at $2\ \mu$ F).

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Electric Potential and Capacitance · Capacitance

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