AktiraAktira JEE
ChemistryJEE Main 5 Apr 2026, Shift 2·Q6·MCQ·Easy–moderate

Equilibrium · Kp from equilibrium amounts

The reaction A(g)⇌B(g)+C(g)\ce{A(g) <=> B(g) + C(g)} was initiated with the amount ‘a' of A(g). At equilibrium it is found that the amount of A(g) remaining is (a−x)(a - x) at a total pressure of pp.

The equilibrium constant KpK_\mathrm{p} of the reaction can be calculated from the expression :

  1. (1)x2a2+x2×p\dfrac{x^2}{a^2 + x^2}\times p
  2. (2)x2a2−x2×p\dfrac{x^2}{a^2 - x^2}\times p
  3. (3)a+x2x2×p\dfrac{a + x^2}{x^2}\times p
  4. (4)a−x2x2×p\dfrac{a - x^2}{x^2}\times p

Video solution coming soon

We're animating every PYQ step by step. Subscribe to get them first.

Subscribe

See the full 5 Apr 2026, Shift 2 paper