AktiraAktira JEE
JEE Main 2026

JEE Main 5 Apr 2026, Shift 2

75 questions. Answers are hidden — tap “Show answer” under each one.

Physics

  1. Match List-I with List-II.
    List-IList-II
    (A) Meter (L)I. hcG\sqrt{\dfrac{hc}{\mathrm{G}}}
    [6pt] (B) Second (S)II. Ghc5\sqrt{\dfrac{\mathrm{G}h}{\mathrm{c}^5}}
    [6pt] (C) Kilogram (M)III. K2L2c3Gh\sqrt{\dfrac{\mathrm{K^2L^2c^3}}{\mathrm{G}h}}
    [6pt] (D) Kelvin (K)IV. Ghc3\sqrt{\dfrac{\mathrm{G}h}{\mathrm{c}^3}}

    where h (Planck's constant), G (gravitational constant) and c (speed of light in vacuum) are taken as fundamental units.

    Choose the correct answer from the options given below:

    1. (1)A-II, B-IV, C-I, D-III
    2. (2)A-IV, B-II, C-I, D-III
    3. (3)A-IV, B-I, C-II, D-III
    4. (4)A-III, B-I, C-II, D-IV
    We corrected a printing error in the original paper

    Source printed “c (speed of light in vacuum) as fundamental units” (verb missing).

  2. In an experiment to determine the resistance of a given wire using Ohm's law, the voltmeter and ammeter readings are noted as 10V and 5 A, respectively. The least counts of voltmeter and ammeter are 500 mV and 200 mA, respectively. The estimated error in the resistance measurement is Ω\Omega
    1. (1)0.25
    2. (2)2
    3. (3)2.5
    4. (4)0.18
  3. A mass of 1 kg kept in an inclined plane with 30∘30^\circ inclination with respect to horizontal plane and it is at rest initially. Then the whole assembly is moved up with constant velocity of 4 m/s. The work done by the frictional force in time 2s is J.
    (Take g=10 m/s2g = 10\ \mathrm{m/s^2})
    1. (1)20
    2. (2)25
    3. (3)30
    4. (4)10
    We corrected a printing error in the original paper

    Source printed “kept in a inclined plane”.

  4. The velocity(vv) versus time (tt) plot of a particle is shown in the figure, for a time interval of 40s. The total distance travelled by the particle and the average velocity during this period are, respectively
    1. (1)25 m and zero
    2. (2)50 m and zero
    3. (3)100 m and zero
    4. (4)100 m and 2.5 m/s
  5. A wheel initially at rest is subjected to a uniform angular acceleration about its axis. In the first 2 s it rotates through an angle θ1\theta_1 and in the next 2 s it rotates through an angle θ2\theta_2. The ratio θ2θ1\dfrac{\theta_2}{\theta_1} is.
    1. (1)6
    2. (2)3
    3. (3)4
    4. (4)13\dfrac13
  6. An object of uniform density rolls up the curved path with the initial velocity v0v_0 as shown in the figure. If the maximum height attained by an object is 7v0210g\dfrac{7v_0^2}{10g} (gg = acceleration due to gravity), the object is a.
    1. (1)solid cylinder
    2. (2)ring
    3. (3)disc
    4. (4)solid sphere
  7. Q7 · MCQ · GravitationOpen
    A body of mass mm is taken from the surface of earth to a height equal to twice the radius of earth (ReR_e). The increase in potential energy will be.
    (gg is acceleration due to gravity at the surface of earth)
    1. (1)12mgRe\dfrac12 mgR_e
    2. (2)34mgRe\dfrac34 mgR_e
    3. (3)14mgRe\dfrac14 mgR_e
    4. (4)23mgRe\dfrac23 mgR_e
  8. Eight mercury drops, each of radius rr, coalesce to form a bigger drop. The surface energy released in this process is. (SS is the surface tension of mercury).
    1. (1)8πr2S8\pi r^2S
    2. (2)16πr2S16\pi r^2S
    3. (3)64πr2S64\pi r^2S
    4. (4)4πr2S4\pi r^2S
  9. An ideal gas at pressure PP and temperature TT is expanding such that PT3PT^3 = constant. The coefficient of volume expansion of the gas is.
    1. (1)2T\dfrac{2}{T}
    2. (2)1T\dfrac{1}{T}
    3. (3)4T\dfrac{4}{T}
    4. (4)3T\dfrac{3}{T}
  10. Q10 · MCQ · OscillationsOpen
    Match List-I with List-II.
    List-IList-II
    A.sin⁡2ωt\sin^2\omega tI.Periodic with time period T=πωT = \dfrac{\pi}{\omega} but not simple harmonic motion (SHM)
    B.sin⁡3(2ωt)\sin^3(2\omega t)II.Periodic with time period T=2πωT = \dfrac{2\pi}{\omega} but Not SHM
    C.sin⁡(ωt)+cos⁡(πωt)\sin(\omega t) + \cos(\pi\omega t)III.periodic with time period T=πωT = \dfrac{\pi}{\omega} and SHM
    D.cos⁡ωt+cos⁡2ωt\cos\omega t + \cos 2\omega tIV.Non-periodic
    Choose the correct answer from the options given below.
    1. (1)A-III, B-I, C-IV, D-II
    2. (2)A-II, B-I, C-III, D-IV
    3. (3)A-III, B-II, C-IV, D-I
    4. (4)A-II, B-I, C-IV, D-III
  11. A metal rod of length LL rotates about one end at origin with a uniform angular velocity ω\omega. The magnetic field radially falls off as B(r)=B0e−λrB(r) = B_0e^{-\lambda r}; λ\lambda being a positive constant. The emf induced (neglecting the centripetal force on electrons in the rod) is:
    1. (1)B0ω[1λ2−e−λL(1λ2+Lλ)]B_0\omega\left[\dfrac{1}{\lambda^2} - e^{-\lambda L}\left(\dfrac{1}{\lambda^2} + \dfrac{L}{\lambda}\right)\right]
    2. (2)B0ω[1λ2+e−λL(1λ2+Lλ)]B_0\omega\left[\dfrac{1}{\lambda^2} + e^{-\lambda L}\left(\dfrac{1}{\lambda^2} + \dfrac{L}{\lambda}\right)\right]
    3. (3)B0ω[4λ2−e−2λL(1λ2+2Lλ)]B_0\omega\left[\dfrac{4}{\lambda^2} - e^{-2\lambda L}\left(\dfrac{1}{\lambda^2} + \dfrac{2L}{\lambda}\right)\right]
    4. (4)B0ω[3λ2−e−3λL(3λ2+Lλ)]B_0\omega\left[\dfrac{3}{\lambda^2} - e^{-3\lambda L}\left(\dfrac{3}{\lambda^2} + \dfrac{L}{\lambda}\right)\right]
    We corrected a printing error in the original paper

    Source printed “rotates about on end at origin”.

  12. Under steady state condition the potential difference across the capacitor in the circuit isV.
    1. (1)0.5
    2. (2)1.5
    3. (3)0
    4. (4)2
  13. A particle of charge qq and mass mm is projected from origin with an initial velocity v⃗=(v02x^+v02y^)\vec v = \left(\dfrac{v_0}{\sqrt2}\hat{\mathrm x} + \dfrac{v_0}{\sqrt2}\hat{\mathrm y}\right). There exists a uniform magnetic field B⃗=B0z^\vec B = B_0\hat{\mathrm z} and a space varying electric field E⃗=E0e−λxx^\vec E = E_0e^{-\lambda x}\hat{\mathrm x} within the region 0≤x≤L0 \le x \le L. After travelling a distance such that x-coordinate has changed from x=0x = 0 to x=Lx = L, the change in the kinetic energy is.
    1. (1)qE0λ[1−e−λL]\dfrac{qE_0}{\lambda}\left[1 - e^{-\lambda L}\right]
    2. (2)(v0qB02λ)[2−e−2λL]\left(\dfrac{v_0qB_0}{2\lambda}\right)\left[2 - e^{-2\lambda L}\right]
    3. (3)qE0λ[1+e−λL]\dfrac{qE_0}{\lambda}\left[1 + e^{-\lambda L}\right]
    4. (4)q[E0+v0B0λ][1−e−λL/2]q\left[\dfrac{E_0 + v_0B_0}{\lambda}\right]\left[1 - e^{-\lambda L/2}\right]
  14. Given below are two statements : one is labelled as Assertion (A) : and the other is labelled as Reason (R).

    Assertion (A) : The electromagnetic wave exerts pressure on the surface on which it is allowed to fall.

    Reason (R) : There is no mass associated with the electromagnetic waves.

    In the light of the above statements, choose the correct answer from the options given below :

    1. (1)Both (A) and (R) are true and (R) is the correct explanation of (A)
    2. (2)Both (A) and (R) are true but (R) is not the correct explanation of (A)
    3. (3)(A) is true but (R) is false
    4. (4)(A) is false but (R) is true
    We corrected a printing error in the original paper

    Source printed “on which they are allowed to fall”.

  15. Q15 · MCQ · Ray OpticsOpen
    A thin convex lens and a thin concave lens are kept in contact and are co-axial. Which of the following statements is correct for this combination of two lenses?
    1. (1)behaves as concave lens if ∣fconvex∣>∣fconcave∣|f_{\text{convex}}| > |f_{\text{concave}}|
    2. (2)behaves as concave lens if ∣fconvex∣<∣fconcave∣|f_{\text{convex}}| < |f_{\text{concave}}|
    3. (3)behaves as convex lens if ∣fconvex∣>∣fconcave∣|f_{\text{convex}}| > |f_{\text{concave}}|
    4. (4)Focal length of the lens system will change if the positions of two lenses are interchanged
    We corrected a printing error in the original paper

    Source printed “if the position of two lenses are interchanged”.

  16. Q16 · MCQ · Ray OpticsOpen
    An object AB is placed 15 cm on the left of a convex lens P of focal length 10 cm. Another convex lens Q is now placed 15 cm right of lens P. If the focal length of lens Q is 15 cm, the final image is
    1. (1)virtual, formed at 7.5 cm right of lens Q, with a size bigger than that of AB
    2. (2)real, formed at 7.5 cm right of lens Q, with a size same as that of AB
    3. (3)formed at infinity.
    4. (4)real, formed at 7 cm right of lens Q, with a size smaller than that of AB
    We corrected a printing error in the original paper

    Source printed option (2) “with a size same than that of AB”.

  17. Q17 · MCQ · Wave OpticsOpen
    The maximum intensity in a Young's double slit experiment is I0I_0. Distance between the slits (dd) is 5λ5\lambda, where λ\lambda is the wavelength of light used. The intensity of the fringe, exactly opposite to one of the slits on the screen, placed at D=10 dD = 10\,d is
    1. (1)I04\dfrac{I_0}{4}
    2. (2)I02\dfrac{I_0}{2}
    3. (3)I0I_0
    4. (4)3I04\dfrac{3I_0}{4}
  18. An electron is travelling with a velocity vv in free space and when it enters a medium, its velocity is reduced by 20%. The de Broglie wavelength of electron in the medium is αλ0\alpha\lambda_0, where λ0\lambda_0 is its de Broglie wavelength in free space. The value of α\alpha is
    1. (1)1.20
    2. (2)1.0
    3. (3)1.25
    4. (4)0.75
  19. Q19 · MCQ · NucleiOpen
    Assuming the experimental mass of 612C{}^{12}_{6}\mathrm{C} nucleus as 12u, the mass defect of 612C{}^{12}_{6}\mathrm{C} nucleus is MeV/c2\mathrm{MeV/c^2}. (Mass of proton =1.00727= 1.00727u. mass of neutron =1.00866= 1.00866 u, 1 u =931.5 MeV/c2= 931.5\ \mathrm{MeV/c^2} and c is the speed of the light in vacuum.)
    1. (1)127.5
    2. (2)89.03
    3. (3)272.0
    4. (4)92.0
    We corrected a printing error in the original paper

    Source printed “experimental mass of 612{}^{12}_{6}C as 12u, the mass defect of 612{}^{12}_{6}C atom”; corrected to the intended “612{}^{12}_{6}C nucleus” in both places (the data give proton, not hydrogen-atom, masses and no electron mass; the key 89.03 is the nuclear defect).

  20. In a semiconductor p-n diode, the doping concentrations on p-side and n-side are 101510^{15} atoms/cm3\mathrm{cm^3} and 101810^{18} atoms/cm3\mathrm{cm^3} , respectively. Which one of the following statements is true?
    1. (1)Widths of depletion region on either side of the interface are equal
    2. (2)The depletion region width is more on p-side compared to that in n-side
    3. (3)The depletion region width is more on n-side compared to that in p-side
    4. (4)No depletion region forms because of unequal doping concentrations on p and n-sides
    We corrected a printing error in the original paper

    Source printed “Which one of the following statement is true?”.

  21. A copper wire of length 3 m is stretched by 3 mm by applying an external force. The volume of the wire is 600×10−6 m3600\times10^{-6}\ \mathrm{m^3}. The elastic potential energy stored in the wire in stretched condition would be J.
    (Given Young modulus of copper =1.1×1011 N/m2= 1.1\times10^{11}\ \mathrm{N/m^2})
  22. The heat extracted out of x gram of water initially at 50∘50^\circC to cool it down to 0∘0^\circC is sufficient to evaporate (1000−x)(1000 - x) gram of water also initially at 50∘50^\circC. The value of x (closest integer) is.
    (Take latent heat of water 2256 kJ/kg, specific heat capacity of water 4200 J/kg. K)
    We corrected a printing error in the original paper

    Source printed the latent heat as “2256 kJ/kg. K”.

  23. Q23 · Numerical · Alternating CurrentOpen
    A series LCR circuit with R=20 ΩR = 20\ \Omega, L=1.6L = 1.6 H and C=40 μFC = 40\ \mu\mathrm{F} is connected to a variable frequency a.c. source. The inductive reactance at resonant frequency is Ω\Omega.
  24. Q24 · Numerical · Current ElectricityOpen
    When an external resistance of 5 Ω5\ \Omega is connected across terminals of a cell, a current of 0.25 A flows through it. When the 5 Ω5\ \Omega resistor is replaced by a 2 Ω2\ \Omega resistor, a current of 0.5 A flows through it. The internal resistance of the cell is Ω\Omega.
  25. Q25 · Numerical · Electromagnetic InductionOpen
    A circular loop of radius 20 cm and resistance 2 Ω2\ \Omega is placed in a time varying magnetic field B⃗=(2t2+2t+3)\vec B = (2t^2 + 2t + 3) T. At t=0t = 0, for the plane of the loop being perpendicular to the magnetic field, the induced current in the loop at t=3t = 3 s is α50\dfrac{\alpha}{50} A. The value of α\alpha is (Take π=22/7\pi = 22/7)
    We corrected a printing error in the original paper

    Source printed “perpendicular to the magnetic field and, the induced current”.

Chemistry

  1. What volume of hydrogen gas at STP would be liberated by action of 50 mL of HX2SOX4\ce{H2SO4} of 50% purity (density =1.3= 1.3 g mL−1^{-1}) on 20 g of zinc ?

    Given : Molar mass of H, O, S, Zn are 1, 16, 32, 65 g mol−1^{-1} respectively.

    1. (1)5.824 L
    2. (2)7.428 L
    3. (3)6.892 L
    4. (4)8.375 L
  2. Which of the following statement(s) is/are true ?
    • (A)If two orbitals have the same value of (n+l)(n + l), the orbital with lower value of nn will have lower energy.
    • (B)Energies of the orbitals in the same subshell increase with increase in atomic number.
    • (C)The size of 2px_x orbital is less than the size of 3px_x orbital.
    • (D)Among 5f, 6s, 4d, 5p and 5d orbitals, none of the orbitals have 2 radial nodes.
    Choose the correct answer from the options given below :
    1. (1)A, B and C only
    2. (2)A and C only
    3. (3)C and D only
    4. (4)A only
  3. The covalent radii of atoms A and B are rAr_\mathrm{A} and rBr_\mathrm{B}, respectively. The covalent bond length and total length of AB molecule are respectively :
    1. (1)(rA+rB)(r_\mathrm{A} + r_\mathrm{B}), 2(rA+rB)2(r_\mathrm{A} + r_\mathrm{B})
    2. (2)12(rA+rB)\dfrac{1}{2}(r_\mathrm{A} + r_\mathrm{B}), (rA+rB)(r_\mathrm{A} + r_\mathrm{B})
    3. (3)(rA+rB)(r_\mathrm{A} + r_\mathrm{B}), (rA+rB)(r_\mathrm{A} + r_\mathrm{B})
    4. (4)2(rA+rB)2(r_\mathrm{A} + r_\mathrm{B}), 12(rA+rB)\dfrac{1}{2}(r_\mathrm{A} + r_\mathrm{B})
  4. Q4 · MCQ · ThermodynamicsOpen

    Consider the following data for the reaction

    XX2(g)+YX2(g)⇌2 XY(g)\ce{X2(g) + Y2(g) <=> 2XY(g)}

    at 600 K. The ΔrG⊖\Delta_\mathrm{r}G^\ominus (in kJ mol−1^{-1}) for the reaction is:

    Compound
    ΔfH600 K⊖\Delta_f H^\ominus_{600\,\mathrm{K}}
    (kJ mol−1^{-1})
    S600 K⊖S^\ominus_{600\,\mathrm{K}}
    (J mol−1^{-1}K−1^{-1})
    XY(g)42200
    XX2\ce{X2}(g)8140
    YX2\ce{Y2}(g)80250
    1. (1)−21000-21000
    2. (2)−10-10
    3. (3)−1000-1000
    4. (4)−9.012-9.012
  5. Q5 · MCQ · ThermodynamicsOpen
    The correct order of molar heat capacities measured at 298 K and 1 bar is :
    1. (1)Copper (s) >> Bromine (l) >> Helium (g)
    2. (2)Bromine (l) >> Copper (s) >> Helium (g)
    3. (3)Helium (g) >> Bromine (l) >> Copper (s)
    4. (4)Helium (g) >> Bromine (l) == Copper (s)
  6. Q6 · MCQ · EquilibriumOpen

    The reaction A(g)⇌B(g)+C(g)\ce{A(g) <=> B(g) + C(g)} was initiated with the amount ‘a' of A(g). At equilibrium it is found that the amount of A(g) remaining is (a−x)(a - x) at a total pressure of pp.

    The equilibrium constant KpK_\mathrm{p} of the reaction can be calculated from the expression :

    1. (1)x2a2+x2×p\dfrac{x^2}{a^2 + x^2}\times p
    2. (2)x2a2−x2×p\dfrac{x^2}{a^2 - x^2}\times p
    3. (3)a+x2x2×p\dfrac{a + x^2}{x^2}\times p
    4. (4)a−x2x2×p\dfrac{a - x^2}{x^2}\times p
  7. One half cell in a voltaic cell is constructed by dipping silver rod in AgNOX3\ce{AgNO3} solution of unknown concentration, other half cell is Zn rod dipped in 1 molar solution of ZnSOX4\ce{ZnSO4}.

    A voltage of 1.60 V is measured at 298 K for this cell. What is the concentration of AgX+\ce{Ag+} ions used in terms of log⁡x\log x (x=[AgX+]x = [\ce{Ag+}]) ?

    EZn2+/Zn⊖=−0.76E^\ominus_{\mathrm{Zn^{2+}/Zn}} = -0.76 V, EAg+/Ag⊖=+0.80E^\ominus_{\mathrm{Ag^{+}/Ag}} = +0.80 V,

    2.303RTF=0.059\dfrac{2.303RT}{F} = 0.059 V

    1. (1)23.9\dfrac{2}{3.9}
    2. (2)45.9\dfrac{4}{5.9}
    3. (3)2.92\dfrac{2.9}{2}
    4. (4)5.94\dfrac{5.9}{4}
  8. Given below are two statements :

    Statement-I : The number of pairs among [AlX2OX3\ce{Al2O3}, CrX2OX3\ce{Cr2O3}], [ClX2OX7\ce{Cl2O7}, MnX2OX7\ce{Mn2O7}], [NaX2O\ce{Na2O}, VX2OX3\ce{V2O3}] and [CO\ce{CO}, NX2O\ce{N2O}] that contain oxides of same nature (acidic, basic, neutral or amphoteric) is 4.

    Statement-II : Among NaX2O\ce{Na2O}, AlX2OX3\ce{Al2O3}, CO\ce{CO} and ClX2OX7\ce{Cl2O7}, the most basic and acidic oxides are NaX2O\ce{Na2O} and ClX2OX7\ce{Cl2O7}, respectively.

    In the light of the above statements, choose the correct answer from the options given below :

    1. (1)Both Statement-I and Statement-II are true.
    2. (2)Both Statement-I and Statement-II are false.
    3. (3)Statement-I is true but Statement-II is false.
    4. (4)Statement-I is false but Statement-II is true.
  9. Given below are two statements :

    Statement-I : Aluminium upon reaction with NaOH forms [Al(OH)X6]X3−\ce{[Al(OH)6]^{3-}} ion.

    Statement-II : The geometry of IClX4X−\ce{ICl4-}, ClOX3X−\ce{ClO3-} and IBrX2X−\ce{IBr2-} is square planar, pyramidal and linear respectively.

    In the light of the above statements, choose the correct answer from the options given below :

    1. (1)Both Statement-I and Statement-II are true.
    2. (2)Both Statement-I and Statement-II are false.
    3. (3)Statement-I is true but Statement-II is false.
    4. (4)Statement-I is false but Statement-II is true.
  10. Q10 · MCQ · d- and f-BlockOpen

    Given below are two statements :

    Statement-I : Presence of large number of unpaired electrons in transition metal atoms results in higher enthalpies of their atomisation.

    Statement-II : dxy=dxz=dyz<dx2−y2=dz2d_{xy} = d_{xz} = d_{yz} < d_{x^2-y^2} = d_{z^2} and dx2−y2=dz2<dxy=dxz=dyzd_{x^2-y^2} = d_{z^2} < d_{xy} = d_{xz} = d_{yz} are the d-orbital splittings in [Fe(HX2O)X6]X3+\ce{[Fe(H2O)6]^{3+}} and [Ni(Cl)X4]X2−\ce{[Ni(Cl)4]^{2-}} complex ions respectively.

    In the light of the above statements, choose the correct answer from the options given below :

    1. (1)Both Statement-I and Statement-II are correct.
    2. (2)Both Statement-I and Statement-II are incorrect.
    3. (3)Statement-I is correct but Statement-II is incorrect.
    4. (4)Statement-I is incorrect but Statement-II is correct.
  11. Identify the correct statements from the following:
    • (A)[Fe(CX2OX4)X3]X3−\ce{[Fe(C2O4)3]^{3-}} is the most stable complex among [Fe(OH)X6]X3−\ce{[Fe(OH)6]^{3-}}, [Fe(CX2OX4)X3]X3−\ce{[Fe(C2O4)3]^{3-}} and [Fe(SCN)X6]X3−\ce{[Fe(SCN)6]^{3-}}
    • (B)The stability of [Cu(NHX3)X4]X2+\ce{[Cu(NH3)4]^{2+}} is greater than that of [Cu(en)X2]X2+\ce{[Cu(en)2]^{2+}}
    • (C)The hybridization of Fe in KX4[Fe(CN)X6]\ce{K4[Fe(CN)6]} is d2^2sp3^3
    • (D)[Fe(NOX2)X3ClX3]X3−\ce{[Fe(NO2)3Cl3]^{3-}} exhibits linkage isomerism
    • (E)NOX2X−\ce{NO2-} and SCNX−\ce{SCN-} ligands are NOT ambidentate ligands
    Choose the correct answer from the options given below :
    1. (1)A, B, C, D and E
    2. (2)B, C and D only
    3. (3)A, C and D only
    4. (4)A, C and E only
  12. Match List-I with List-II.

    List-I

    (Purification technique)

    List-II

    (Used to separate)

    A.Simple distillationI.Steam volatile compound
    B.Fractional distillationII.Two liquids with large difference in boiling points
    C.Steam distillationIII.Liquid decomposing at its boiling point
    D.Distillation under reduced pressureIV.Two liquids with close boiling points
    Choose the correct answer from the options given below :
    1. (1)A-II, B-III, C-I, D-IV
    2. (2)A-II, B-IV, C-I, D-III
    3. (3)A-II, B-IV, C-III, D-I
    4. (4)A-IV, B-III, C-II, D-I
    We corrected a printing error in the original paper

    Answer corrected; the source key is (3) — steam distillation separates steam-volatile compounds (C-I) and distillation under reduced pressure is used for liquids that decompose at their boiling point (D-III).

  13. Q13 · MCQ · HydrocarbonsOpen

    IUPAC names of some alkenes are given below :

    Find out the correct stability order.

    • (A)2-Methylbut-2-ene
    • (B)cis-But-2-ene
    • (C)2,3-Dimethylbut-2-ene
    • (D)Prop-1-ene
    Choose the correct answer from the options given below :
    1. (1)C >> A >> B >> D
    2. (2)C >> A >> D >> B
    3. (3)B >> D >> A >> C
    4. (4)A >> B >> C >> D
    We corrected a printing error in the original paper

    Source printed “IUPAC name of the some alkenes are given below”.

  14. Identify the correct IUPAC name of hydrocarbon (x) containing three primary carbon atoms and with molar mass 72 g mol−1^{-1}.
    1. (1)1,1-Dimethylcyclopropane
    2. (2)2,2-Dimethylpropane
    3. (3)2-Methylbutane
    4. (4)n-pentane
  15. Complete the following reaction sequence and give the name of major product ‘P'.
    1. (1)2-Chloropropanoic acid
    2. (2)3-Chloropropanoic acid
    3. (3)1-Chloropropane
    4. (4)2-Chloropropane
  16. Given below are two statements :

    Statement-I : The condensation reaction between CHX3−CH=O\ce{CH3-CH=O} and under optimum pH will produce

    Statement-II : The molecule, will generate Ph−CH=O\ce{Ph-CH=O} in the presence of dilute acid.

    In the light of the above statements, choose the correct answer from the options given below :

    1. (1)Both Statement-I and Statement-II are true.
    2. (2)Both Statement-I and Statement-II are false.
    3. (3)Statement-I is true but Statement-II is false.
    4. (4)Statement-I is false but Statement-II is true.
  17. Q17 · MCQ · AminesOpen

    Given below are two statements :

    Statement-I : Heating benzamide with bromine in an ethanolic solution of sodium hydroxide will give benzylamine.

    Statement-II : Nitration of aniline with HNOX3\ce{HNO3}/HX2SOX4\ce{H2SO4} at 288 K produces m-nitroaniline in higher amount than o-nitroaniline (pH adjusted).

    In the light of the above statements, choose the correct answer from the options given below :

    1. (1)Both Statement-I and Statement-II are true.
    2. (2)Both Statement-I and Statement-II are false.
    3. (3)Statement-I is true but Statement-II is false.
    4. (4)Statement-I is false but Statement-II is true.
  18. Q18 · MCQ · BiomoleculesOpen
    Identify the incorrect statement about tertiary structure of proteins.
    1. (1)They can be fibrous or globular in structure.
    2. (2)The main forces that stabilize the structure are hydrogen bonding, disulphide links, van der Waals and electrostatic forces of attraction.
    3. (3)The structure remains intact when exposed to pH changes.
    4. (4)A linear polypeptide chain will convert to a secondary structure and then further folding of the secondary structure will convert to tertiary structure.
  19. Q19 · MCQ · BiomoleculesOpen

    Given below are two statements :

    Statement-I : and are two anomers of D-(+)-glucose.

    Statement-II : The open chain forms of D-glucose and D-fructose contain three similar chiral carbons at C3_3, C4_4 and C5_5.

    In the light of the above statements, choose the correct answer from the options given below :

    1. (1)Both Statement-I and Statement-II are true.
    2. (2)Both Statement-I and Statement-II are false.
    3. (3)Statement-I is true but Statement-II is false.
    4. (4)Statement-I is false but Statement-II is true.
  20. A paper dipped in a dil. HX2SOX4\ce{H2SO4} solution of ‘X' upon treatment with SOX2\ce{SO2} gas turns into green. The compound ‘X' is :
    1. (1)KI-starch
    2. (2)KMnOX4\ce{KMnO4}
    3. (3)Pb(CHX3COO)X2\ce{Pb(CH3COO)2}
    4. (4)KX2CrX2OX7\ce{K2Cr2O7}
  21. Q21 · Numerical · Coordination CompoundsOpen
    The total number of unpaired electrons present in the d3^3, d4^4 (low spin) d5^5 (high spin), d6^6 (high spin) and d7^7 (low spin) octahedral complex systems is .
  22. Q22 · Numerical · Haloalkanes & HaloarenesOpen
    RMgI when treated with ice cold water liberated a gas which occupied 1.4 dm3^3/g at STP. The gas produced is further reacted with iodine in presence of HIOX3\ce{HIO3} to give compound (X). Compound (X) in presence of Na and dry ether produced compound (Y). Molar mass of compound (Y) is g mol−1^{-1}. (Nearest integer)
  23. Q23 · Numerical · SolutionsOpen

    20 g hemoglobin in a 1 L aqueous solution (A) at 300 K is separated from pure water by semi permeable membrane. At equilibrium the height of solution in a tube dipped in a solution (A) is found to be 80.0 mm higher than the tube dipped in water.

    The molar mass of hemoglobin is kg mol−1^{-1}. (Nearest integer)

    (Given : g=10g = 10 m s−2^{-2}, R=8.3R = 8.3 kPa dm3^3 K−1^{-1} mol−1^{-1}, density of solution =1000= 1000 kg m−3^{-3})

  24. Q24 · Numerical · ElectrochemistryOpen

    At 298 K, the molar conductivity of x% (w/w) MX solution (aqueous) is 123.5 S cm2^2 mol−1^{-1}. The conductance of same solution is 1.9×10−31.9\times10^{-3} S. The value of x is × 10−2\times\,10^{-2}.

    (Given : cell constant =1.3= 1.3 cm−1^{-1}; molar mass of MX is 75 g mol−1^{-1}, density of aqueous solution of MX at 298 K is 1.0 g mL−1^{-1})

  25. Q25 · Numerical · Chemical KineticsOpen
    For a reaction A→P\ce{A -> P} at T K, the half life (t1/2t_{1/2}) is plotted as a function of initial concentration [A]0[\mathrm{A}]_0 of A as given below :
    The value of x in the given figure is s (Nearest integer)

Maths

  1. Let α,β\alpha, \beta be the roots of the equation x2−x+p=0x^2 - x + p = 0 and γ,δ\gamma, \delta be the roots of the equation x2−4x+q=0x^2 - 4x + q = 0; p,q∈Zp, q \in \mathbb{Z}. If α,β,γ,δ\alpha, \beta, \gamma, \delta are in G.P., then ∣p+q∣\lvert p + q\rvert equals:
    1. (1)16
    2. (2)32
    3. (3)34
    4. (4)38
    We corrected a printing error in the original paper

    Source printed “be the roots the equation x2−4x+q=0x^2 - 4x + q = 0” (missing “of”).

  2. Let z1,z2∈Cz_1, z_2 \in \mathbb{C} be the distinct solutions of the equation z2+4z−(1+12i)=0z^2 + 4z - (1 + 12i) = 0. Then ∣z1∣2+∣z2∣2\lvert z_1\rvert^2 + \lvert z_2\rvert^2 is equal to:
    1. (1)18
    2. (2)22
    3. (3)29
    4. (4)34
  3. If f:N→Zf : \mathbb{N} \to \mathbb{Z} is defined by f(n)=∣n−1−5−2n23(2k+1)2k+1−3n33k(2k+1)3k(k+2)+1∣, k∈N, andf(n) = \begin{vmatrix} n & -1 & -5\\ -2n^2 & 3(2k+1) & 2k+1\\ -3n^3 & 3k(2k+1) & 3k(k+2)+1 \end{vmatrix},\ k \in \mathbb{N}, \text{ and} ∑n=1kf(n)=98\displaystyle\sum_{n=1}^{k} f(n) = 98, then kk is equal to:
    1. (1)3
    2. (2)4
    3. (3)5
    4. (4)6
  4. Let MM be a 3×33 \times 3 matrix such that M(100)=(123),M(010)=(012)andM(001)=(−111).M\begin{pmatrix}1\\0\\0\end{pmatrix} = \begin{pmatrix}1\\2\\3\end{pmatrix},\quad M\begin{pmatrix}0\\1\\0\end{pmatrix} = \begin{pmatrix}0\\1\\2\end{pmatrix} \quad\text{and}\quad M\begin{pmatrix}0\\0\\1\end{pmatrix} = \begin{pmatrix}-1\\1\\1\end{pmatrix}. If M(xyz)=(1711)M\begin{pmatrix}x\\y\\z\end{pmatrix} = \begin{pmatrix}1\\7\\11\end{pmatrix}, then x+y+zx + y + z equals:
    1. (1)4
    2. (2)5
    3. (3)7
    4. (4)11
    We corrected a printing error in the original paper

    Answer corrected; the source key is (3) — the columns of MM are (1,2,3)(1,2,3), (0,1,2)(0,1,2), (−1,1,1)(-1,1,1), so x−z=1x - z = 1, 2x+y+z=72x + y + z = 7, 3x+2y+z=113x + 2y + z = 11 give (x,y,z)=(2,2,1)(x,y,z) = (2,2,1) and x+y+z=5x + y + z = 5, option (2).

  5. If the sum of the first 10 terms of the series 11+14×4+21+24×4+31+34×4+41+44×4+…\frac{1}{1 + 1^4\times4} + \frac{2}{1 + 2^4\times4} + \frac{3}{1 + 3^4\times4} + \frac{4}{1 + 4^4\times4} + \ldots is mn\dfrac{m}{n}, gcd⁡(m,n)=1\gcd(m, n) = 1, then m+nm + n is equal to:
    1. (1)256
    2. (2)264
    3. (3)276
    4. (4)284
  6. Let A1,A2,A3,…,A39A_1, A_2, A_3, \ldots, A_{39} be 39 arithmetic means between the numbers 59 and 159. Then the mean of A25A_{25}, A28A_{28}, A31A_{31} and A36A_{36} is equal to:
    1. (1)129
    2. (2)136
    3. (3)131.50
    4. (4)134
  7. The coefficient of x2x^2 in the expansion of (2x2+1x)10\left(2x^2 + \dfrac{1}{x}\right)^{10}, x≠0x \neq 0, is:
    1. (1)3240
    2. (2)3360
    3. (3)3480
    4. (4)3600
    We corrected a printing error in the original paper

    Answer corrected; the source key is (3) — the general term is (10r)210−rx20−3r\binom{10}{r}2^{10-r}x^{20-3r}, so r=6r = 6 and the coefficient is (106)24=3360\binom{10}{6}2^4 = 3360, option (2).

  8. Q8 · MCQ · ProbabilityOpen
    The probabilities that players AA and BB of a team are selected for the captaincy for a tournament are 0.6 and 0.4, respectively. If AA is selected the captain, the probability that the team wins the tournament is 0.8 and if BB is selected the captain, the probability that the team wins the tournament is 0.7. Then the probability, that the team wins the tournament, is:
    1. (1)0.74
    2. (2)0.76
    3. (3)0.72
    4. (4)0.78
  9. A box contains 5 blue, 6 yellow and 4 red balls. The number of ways, of drawing 8 balls containing at least two balls of each colour, is:
    1. (1)4100
    2. (2)4140
    3. (3)4230
    4. (4)4290
  10. Q10 · MCQ · StatisticsOpen
    A variable XX takes values 0,0,2,6,12,20,…,n(n−1)0, 0, 2, 6, 12, 20, \ldots, n(n-1) with frequencies nC0{}^{n}C_{0}, nC1{}^{n}C_{1}, nC2{}^{n}C_{2}, nC3{}^{n}C_{3}, nC4{}^{n}C_{4}, nC5{}^{n}C_{5}, …\ldots, nCn{}^{n}C_{n}, respectively. If the mean of this data is 60, then its median is:
    1. (1)56
    2. (2)42
    3. (3)72
    4. (4)90
  11. Q11 · MCQ · CirclesOpen
    Let the point PP be the vertex of the parabola y=x2−6x+12y = x^2 - 6x + 12. If a line passing through the point PP intersects the circle x2+y2−2x−4y+3=0x^2 + y^2 - 2x - 4y + 3 = 0 at the points RR and SS, then the maximum value of (PR+PS)2(PR + PS)^2 is:
    1. (1)10
    2. (2)20
    3. (3)25
    4. (4)5
  12. Q12 · MCQ · Conic SectionsOpen
    Let the directrix of the parabola P:y2=8xP : y^2 = 8x, cut xx-axis at the point AA. Let B(α,β)B(\alpha, \beta), α>1\alpha > 1, be a point on PP such that the slope of ABAB is 3/53/5. If BCBC is a focal chord of PP, then six times the area of ΔABC\Delta ABC is:
    1. (1)80
    2. (2)160
    3. (3)174
    4. (4)192
  13. Q13 · MCQ · Conic SectionsOpen
    Let the eccentricity ee of a hyperbola satisfy the equation 6e2−11e+3=06e^2 - 11e + 3 = 0. If the foci of the hyperbola are (3,5)(3, 5) (3,−4)(3, -4), then the length of its latus rectum is:
    1. (1)113\dfrac{11}{3}
    2. (2)173\dfrac{17}{3}
    3. (3)152\dfrac{15}{2}
    4. (4)172\dfrac{17}{2}
  14. Q14 · MCQ · 3D GeometryOpen
    Let a triangle PQRPQR be such that PP and QQ lie on the line x+38=y−42=z+12\dfrac{x+3}{8} = \dfrac{y-4}{2} = \dfrac{z+1}{2} and are at a distance of 6 units from R(1,2,3)R(1, 2, 3). If (α,β,γ)(\alpha, \beta, \gamma) is the centroid of ΔPQR\Delta PQR, then α+β+γ\alpha + \beta + \gamma is equal to:
    1. (1)4
    2. (2)5
    3. (3)6
    4. (4)8
  15. Q15 · MCQ · 3D GeometryOpen
    If the distance of the point (a,2,5)(a, 2, 5) from the image of the point (1,2,7)(1, 2, 7) in the line x1=y−11=z−22\dfrac{x}{1} = \dfrac{y-1}{1} = \dfrac{z-2}{2} is 4, then the sum of all possible values of aa is equal to:
    1. (1)11
    2. (2)9
    3. (3)6
    4. (4)4
  16. Q16 · MCQ · VectorsOpen
    Let OO be the origin, OP→=a⃗\overrightarrow{OP} = \vec a and OQ→=b⃗\overrightarrow{OQ} = \vec b. If RR is the point on OP→\overrightarrow{OP} such that OP→=5OR→\overrightarrow{OP} = 5\overrightarrow{OR}, and MM is the point such that OQ→=5RM→\overrightarrow{OQ} = 5\overrightarrow{RM}, then PM→\overrightarrow{PM} is equal to:
    1. (1)15(a⃗−4b⃗)\dfrac15\left(\vec a - 4\vec b\right)
    2. (2)15(b⃗−4a⃗)\dfrac15\left(\vec b - 4\vec a\right)
    3. (3)15(−a⃗+4b⃗)\dfrac15\left(-\vec a + 4\vec b\right)
    4. (4)15(−b⃗+4a⃗)\dfrac15\left(-\vec b + 4\vec a\right)
  17. Let f(x)=lim⁡y→0(1−cos⁡(xy))tan⁡(xy)y3f(x) = \displaystyle\lim_{y\to0}\frac{(1 - \cos(xy))\tan(xy)}{y^3}. Then the number of solutions of the equation f(x)=sin⁡xf(x) = \sin x, x∈Rx \in \mathbb{R} is:
    1. (1)0
    2. (2)2
    3. (3)3
    4. (4)1
  18. Let (21−a+21+a)\left(2^{1-a} + 2^{1+a}\right), f(a)f(a), (3a+3−a)\left(3^{a} + 3^{-a}\right) be a A.P. and α\alpha be the minimum value of f(a)f(a). Then the value of the integral ∫log⁡e(α−1)log⁡e(α)dx(e2x−e−2x)\int_{\log_e(\alpha-1)}^{\log_e(\alpha)} \frac{dx}{\left(e^{2x} - e^{-2x}\right)} is:
    1. (1)12log⁡e(43)\dfrac12\log_e\left(\dfrac43\right)
    2. (2)14log⁡e(43)\dfrac14\log_e\left(\dfrac43\right)
    3. (3)12log⁡e(85)\dfrac12\log_e\left(\dfrac85\right)
    4. (4)14log⁡e(85)\dfrac14\log_e\left(\dfrac85\right)
  19. Let f:[1,∞)→Rf : [1, \infty) \to \mathbb{R} be a differentiable function defined as f(x)=∫1xf(t) dt+(1−x)(log⁡ex−1)+e.f(x) = \int_1^x f(t)\,dt + (1 - x)(\log_e x - 1) + e. Then the value of f(f(1))f(f(1)) is:
    1. (1)(1+ee)(1 + e^{e})
    2. (2)(1+e)(1 + e)
    3. (3)(1+e+ee)(1 + e + e^{e})
    4. (4)1+2e1 + 2e
    We corrected a printing error in the original paper

    Source printed “Then the value fo f(f(1))f(f(1))”.

  20. Let f(x)f(x) and g(x)g(x) be twice differentiable functions satisfying f′′(x)=g′′(x)f''(x) = g''(x) for all x∈Rx \in \mathbb{R}, f′(1)=2g′(1)=4f'(1) = 2g'(1) = 4 and g(2)=3f(2)=9g(2) = 3f(2) = 9. Then f(25)−g(25)f(25) - g(25) is equal to:
    1. (1)20
    2. (2)40
    3. (3)−20-20
    4. (4)−40-40
  21. Let A={1,4,7}A = \{1, 4, 7\} and B={2,3,8}B = \{2, 3, 8\}. Then the number of elements, in the relation R={((a1,b1),(a2,b2))∈((A×B)×(A×B)):a1+b2 divides a2+b1}R = \{((a_1, b_1), (a_2, b_2)) \in ((A \times B) \times (A \times B)) : a_1 + b_2 \text{ divides } a_2 + b_1\} is .
  22. Q22 · Numerical · Straight LinesOpen
    From the point (−1,−1)(-1, -1), two rays are sent making angles of 45∘45^\circ with the line x+y=0x + y = 0. These rays get reflected from the mirror x+2y=1x + 2y = 1. If the equations of the reflected rays are ax+by=9ax + by = 9 and cx+dy=7cx + dy = 7, a,b,c,d∈Za, b, c, d \in \mathbb{Z}, then the value of ad+bcad + bc is .
  23. Q23 · Numerical · TrigonometryOpen
    If S={θ∈[−π,π]:cos⁡θcos⁡5θ2=cos⁡7θcos⁡7θ2}S = \left\{\theta \in [-\pi, \pi] : \cos\theta\cos\dfrac{5\theta}{2} = \cos7\theta\cos\dfrac{7\theta}{2}\right\}, then n(S)n(S) is equal to .
  24. Q24 · Numerical · Area under CurvesOpen
    Let f:R→Rf : \mathbb{R} \to \mathbb{R} be a function such that f(x)+3f(π2−x)=sin⁡xf(x) + 3f\left(\dfrac{\pi}{2} - x\right) = \sin x, x∈Rx \in \mathbb{R}. Let maximum value of ff on R\mathbb{R} be α\alpha. If the area of the region bounded by the curves g(x)=x2g(x) = x^2 and h(x)=βx3h(x) = \beta x^3, β>0\beta > 0, is α2\alpha^2, then 30β330\beta^3 is equal to .
  25. Q25 · Numerical · Differential EquationsOpen
    Let y=y(x)y = y(x) be the solution of the differential equation (tan⁡x)1/2 dy=(sec⁡3x−(tan⁡x)3/2y)dx,(\tan x)^{1/2}\,dy = \left(\sec^3x - (\tan x)^{3/2}y\right)dx, 0<x<π20 < x < \dfrac{\pi}{2}, y(π4)=625y\left(\dfrac{\pi}{4}\right) = \dfrac{6\sqrt2}{5}. If y(π3)=45αy\left(\dfrac{\pi}{3}\right) = \dfrac45\alpha, then α4\alpha^4 equals .