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MathsJEE Main 5 Apr 2026, Shift 2·Q2·MCQ·Easy–moderate

Complex Numbers · Quadratic with complex coefficients

Let z1,z2∈Cz_1, z_2 \in \mathbb{C} be the distinct solutions of the equation z2+4z−(1+12i)=0z^2 + 4z - (1 + 12i) = 0. Then ∣z1∣2+∣z2∣2\lvert z_1\rvert^2 + \lvert z_2\rvert^2 is equal to:
  1. (1)18
  2. (2)22
  3. (3)29
  4. (4)34

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