MathsJEE Main 5 Apr 2026, Shift 2·Q7·MCQ·Easy–moderate

Binomial Theorem · Coefficient of a term

The coefficient of

x^2

in the expansion of

\left(2x^2 + \dfrac{1}{x}\right)^{10}

x \neq 0

, is:

(1)3240
(2)3360
(3)3480
(4)3600

We corrected a printing error in the original paper

Answer corrected; the source key is (3) — the general term is $\binom{10}{r}2^{10-r}x^{20-3r}$ , so $r = 6$ and the coefficient is $\binom{10}{6}2^4 = 3360$ , option (2).

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Binomial Theorem · Coefficient of a term

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