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MathsJEE Main 6 Apr 2026, Shift 1·Q11·MCQ·Moderate

Conic Sections · Hyperbola eccentricity and latus rectum

If the eccentricity ee of the hyperbola x2a2−y2b2=1\dfrac{x^2}{a^2} - \dfrac{y^2}{b^2} = 1, passing through (6,43)\left(6, 4\sqrt3\right), satisfies 15(e2+1)=34e15(e^2 + 1) = 34e, then the length of the latus rectum of the hyperbola x2b2−y22(a2+1)=1\dfrac{x^2}{b^2} - \dfrac{y^2}{2(a^2 + 1)} = 1 is:
  1. (1)10
  2. (2)20
  3. (3)25
  4. (4)30

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