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JEE Main 2026

JEE Main 6 Apr 2026, Shift 1

75 questions. Answers are hidden — tap “Show answer” under each one.

Physics

  1. The density ρ\rho of a uniform cylinder is determined by measuring its mass m, length ll and diameter d. The measured values of m, ll and d are 97.42±0.0297.42 \pm 0.02 g, 8.35±0.058.35 \pm 0.05 mm and 20.20±0.0220.20 \pm 0.02 mm, respectively. Calculated percentage fractional error in ρ\rho is .
    1. (1)0.63%
    2. (2)0.82%
    3. (3)0.72%
    4. (4)0.25%
  2. The potential energy of a particle changes with distance x from a fixed origin as V=Axx+BV = \dfrac{A\sqrt{x}}{x + B}, where A and B are constants with appropriate dimensions. The dimensions of AB are .
    1. (1)[M1L5/2T−2][\mathrm{M^1L^{5/2}T^{-2}}]
    2. (2)[M3/2L5/2T−2][\mathrm{M^{3/2}L^{5/2}T^{-2}}]
    3. (3)[M1L2T−2][\mathrm{M^1L^2T^{-2}}]
    4. (4)[M1L7/2T−2][\mathrm{M^1L^{7/2}T^{-2}}]
    We corrected a printing error in the original paper

    Source printed “A and B are constant with appropriate dimensions. The dimension of AB are”.

  3. The rain drop of mass 1 g, starts with zero velocity from a height of 1 km. It hits the ground with a speed of 5 m/s. The work done by the unknown resistive force is J. (take g=10 m/s2g = 10\ \mathrm{m/s^2})
    1. (1)−8.75-8.75
    2. (2)−8.35-8.35
    3. (3)−9.55-9.55
    4. (4)−9.98-9.98
  4. Two blocks (P and Q) with respectively masses 2 kg and 1.5 kg are joined by a massless thread. These blocks are mounted on a frictionless pulley which is fixed on the edge of a cube (S), as shown in the figure below. Block P is positioned on the top surface which has no friction and block Q is in contact with side-surface, having coefficient of friction μ\mu. The cube (S) moves towards the right with acceleration of g2\dfrac{g}{2}, where g is gravitational acceleration. During this movement the blocks P and Q remain stationary. The value of μ\mu is . (take g=10 m/s2g = 10\ \mathrm{m/s^2})
    1. (1)0.33
    2. (2)0.67
    3. (3)1
    4. (4)0.5
    We corrected a printing error in the original paper

    The figure printed the mass of Q as “15 kg” (with 15 kg no option fits); figure label changed to the stem's 1.5 kg (original kept as work/orig-P04-stem.png); source also printed “pully”; “coefficient friction”; “the block P and Q”.

  5. A lift of mass 1600 kg is supported by thick iron wire. If the maximum stress which the wire can withstand is 4×108 N/m24\times10^{8}\ \mathrm{N/m^2} and its radius is 4 mm, then maximum acceleration the lift can take is m/s2\mathrm{m/s^2}. (take g=10 m/s2g = 10\ \mathrm{m/s^2} and π=3.14\pi = 3.14)
    1. (1)2.56
    2. (2)3.89
    3. (3)4.32
    4. (4)5.16
  6. A solid sphere of radius 4 cm and mass 5 kg is rotating (rotation axis is passing through the centre of the sphere) with an angular velocity of 1200 rpm. It is brought to rest in 10 s by applying a constant torque. The torque applied and the number of rotations it made before it comes to rest are and respectively.
    1. (1)0.128 π0.128\,\pi Nm, 100
    2. (2)0.0128 π0.0128\,\pi Nm, 50
    3. (3)0.128 π0.128\,\pi Nm, 50
    4. (4)0.0128 π0.0128\,\pi Nm, 100
  7. A smooth inclined plane ends in a vertical circular loop, as shown in the figure. A small body is released from height h as shown. If the body exerts a force of three times its weight on the plane at the highest point of circle then the height h=αRh = \alpha R. The value of α\alpha is
    1. (1)2
    2. (2)4
    3. (3)3
    4. (4)6
  8. The position of center of mass of three masses 2 kg, 3 kg and 15 kg placed with respect to mid point (p) of normal bisector, as shown in the figure is .
    1. (1)(34,1.25)\left(\dfrac{\sqrt3}{4}, 1.25\right)
    2. (2)(34,1.0)\left(\dfrac{\sqrt3}{4}, 1.0\right)
    3. (3)(0,0)(0, 0)
    4. (4)(1.25,0)(1.25, 0)
  9. The two wires A and B of equal cross-section but of different materials are joined together. The ratio of Young's modulus of wire A and wire B is 20/11. When the joined wire is kept under certain tension the elongations in the wires A and B are equal. If the length of wire A is 2.2 m, then the length of wire B is m.
    1. (1)1.1
    2. (2)2.22
    3. (3)1.21
    4. (4)4.44
  10. Two closed vessels of same volume are joined through a narrow tube and both vessels are filled with air of pressure 90 kPa and temperature 400 K. Keeping the temperature of one vessel constant at 400 K the second vessel temperature is raised to 500 K. The final pressure in the vessels is kPa.
    1. (1)100
    2. (2)120
    3. (3)90
    4. (4)105
  11. Q11 · MCQ · Wave OpticsOpen
    In interference experiment the path difference between two interfering waves at a point A on the screen is λ/3\lambda/3, where λ\lambda is the wavelength of these waves, and at another point B the path difference is λ/6\lambda/6. The ratio of intensities at points A and B is .
    1. (1)3
    2. (2)4
    3. (3)1/3
    4. (4)1/4
  12. Q12 · MCQ · OscillationsOpen
    A particle is executing simple harmonic motion. Its amplitude is A and time period is 5 sec. the time required by it to move from x=Ax = A to x=A2x = \dfrac{A}{\sqrt2} is sec.
    1. (1)1/4
    2. (2)5/4
    3. (3)5/8
    4. (4)3/8
  13. A thin half ring of radius 35 cm is uniformly charged with a total charge of Q coulomb. If the magnitude of the electric field at centre of the half ring is 100 V/m, then the value of Q is nC. (ϵ0=8.85×10−12 C2/Nm2\epsilon_0 = 8.85\times10^{-12}\ \mathrm{C^2/Nm^2} and π=3.14\pi = 3.14)
    1. (1)2.14
    2. (2)2.44
    3. (3)3.25
    4. (4)0.7
  14. The maximum rated power of the LED is 2 mW and it is used in the circuit with input voltage of 5 V as shown in the figure below. The current through resistance RSR_S is 0.5 mA.
    The minimum value of the resistance of RSR_S, to ensure that the LED is not damaged is kΩ\Omega.
    1. (1)6
    2. (2)2
    3. (3)4
    4. (4)5
  15. A point light source emits E.M. waves in free space. A detector, placed at a distance of L m, measures the intensity as I0I_0. The detector is now shifted to another location on the same spherical surface ensuring the angle between original location and new location as 45∘45^\circ. The measured intensity at new location will be .
    1. (1)I04\dfrac{I_0}{4}
    2. (2)I0I_0
    3. (3)I02\dfrac{I_0}{\sqrt2}
    4. (4)I02\dfrac{I_0}{2}
  16. Q16 · MCQ · Ray OpticsOpen
    A spherical interface lens of radius R separates two media of refractive indices 1 and 1.4 respectively as shown in the figure below. A point source is placed at a distance of 4R in front of spherical interface. The magnitude of the magnification of point source image is .
    1. (1)1.66
    2. (2)2.33
    3. (3)2.66
    4. (4)1.33
  17. A small cube of side 1 mm is placed at the centre of a circular loop of radius 10 cm carrying a current of 2 A. The magnetic energy stored inside the cube is α×10−14\alpha\times10^{-14} J. The value of α\alpha is . (μ0=4π×10−7\mu_0 = 4\pi\times10^{-7} Tm/A, π=3.14\pi = 3.14)
    1. (1)6.28
    2. (2)6.28×10−66.28\times10^{-6}
    3. (3)628
    4. (4)6.28×10−46.28\times10^{-4}
  18. An inductor of inductance 10 mH having resistance of 100 Ω100\ \Omega is connected to battery of E.M.F. 1.0 V through a switch as shown in the figure below. After switch is closed, the ratio of instantaneous induced emfs across the inductor when the current passing through it is 2 mA and 4 mA is .
    1. (1)4/3
    2. (2)3/4
    3. (3)5/3
    4. (4)3/5
    We corrected a printing error in the original paper

    Source printed “the ratio of instantaneous voltages across the inductor” (the terminal voltage of the resistive inductor equals the 1.0 V emf at all times, ratio 1); corrected to the intended “induced emfs” (L di/dtL\,di/dt: 0.8 V and 0.6 V).

  19. Q19 · MCQ · AtomsOpen
    The ratio of momentum of the photons of the 1st1^{\text{st}} and 2nd2^{\text{nd}} line of Balmer series of Hydrogen atoms is α/β\alpha/\beta. The possible values of α\alpha and β\beta are :-
    1. (1)27 and 20
    2. (2)3 and 16
    3. (3)5 and 36
    4. (4)20 and 27
  20. A LCR series circuit driven with Erms=90E_{\mathrm{rms}} = 90 V at frequency fd=30f_d = 30 Hz has resistance R=80 ΩR = 80\ \Omega, an inductance with inductive reactance XL=20.0 ΩX_L = 20.0\ \Omega and capacitance with capacitive reactance XC=80.0 ΩX_C = 80.0\ \Omega. The power factor of the circuit is .
    1. (1)0.8
    2. (2)0.64
    3. (3)0.9
    4. (4)0.5
  21. Q21 · Numerical · Current ElectricityOpen
    Refer to the circuit diagram given below. The heat generated across the 6 Ω6\ \Omega resistance in 100 second is α100\dfrac{\alpha}{100} J. The value of α\alpha is . (Nearest integer)
  22. Q22 · Numerical · Wave OpticsOpen
    An unpolarized light of intensity I0I_0 passes through polarizer and then through a certain optically active solution and finally it goes to analyser. If the angle between analyser and polariser is 0∘0^\circ and intensity of light emerged from analyser is 38I0\dfrac38 I_0, the angle of rotation of the light by the solution with respect to analyser is degrees.
  23. Q23 · Numerical · NucleiOpen
    The energy released when 717.13\dfrac{7}{17.13} kg of 37Li{}^{7}_{3}\mathrm{Li} is converted into 24He{}^{4}_{2}\mathrm{He} by proton bombardment is α×1032\alpha\times10^{32} eV. The value of α\alpha is . (Nearest integer)
    (Mass of 37Li=7.0183{}^{7}_{3}\mathrm{Li} = 7.0183 u, mass of 24He=4.004{}^{4}_{2}\mathrm{He} = 4.004 u, mass of proton =1.008= 1.008 u and 1 u =931 MeV/c2= 931\ \mathrm{MeV/c^2} and Avogadro number =6.0×1023= 6.0\times10^{23})
  24. A three coulomb charge moves from the point (0,−2,−5)(0, -2, -5) to the point (5,1,2)(5, 1, 2) in an electric field expressed as E⃗=2xi^+3y2j^+4k^\vec E = 2x\hat i + 3y^2\hat j + 4\hat k N/C. The work done in moving the charge is J.
  25. Q25 · Numerical · ThermodynamicsOpen
    A certain gas is isothermally compressed to (13)rd\left(\dfrac13\right)^{\text{rd}} of its initial volume (V0=3V_0 = 3 litre) by applying required pressure. If the bulk modulus of the gas is 3×105 N/m23\times10^{5}\ \mathrm{N/m^2}, the magnitude of work done on the gas is J.

Chemistry

  1. An oxide of iron contains 69.9% iron, its empirical formula, is :

    (Given : Molar mass of Fe and O are 56 and 16 g mol−1^{-1} respectively.)

    1. (1)FeO\ce{FeO}
    2. (2)FeX2OX3\ce{Fe2O3}
    3. (3)FeX3OX4\ce{Fe3O4}
    4. (4)FeOX3\ce{FeO3}
  2. If shortest wavelength of hydrogen atom in Lyman series is x, then longest wavelength in Balmer series of HeX+\ce{He+} is :
    1. (1)9x5\dfrac{9x}{5}
    2. (2)36x5\dfrac{36x}{5}
    3. (3)x4\dfrac{x}{4}
    4. (4)5x9\dfrac{5x}{9}
  3. Match the List-I with List-II :
    List-IList-II
    OrbitalRadial nodes and nodal plane
    A.2sI.1 Radial node + two nodal planes
    B.3sII.1 Radial node + one nodal plane
    C.3pIII.2 Radial nodes + No nodal plane
    D.4dIV.1 Radial node + No nodal plane.
    Choose the correct answer from the options given below :
    1. (1)A-IV, B-I, C-III, D-II
    2. (2)A-IV, B-II, C-III, D-I
    3. (3)A-III, B-I, C-IV, D-II
    4. (4)A-IV, B-III, C-II, D-I
  4. The pairs among

    A = [SOX3X2−\ce{SO3^2-}, COX3X2−\ce{CO3^2-}], B = [OX2X2−\ce{O2^2-}, FX2\ce{F2}], C = [CNX−\ce{CN-}, CO\ce{CO}], D = [NHX3\ce{NH3}, HX3OX+\ce{H3O+}] and E = [MnOX4X2−\ce{MnO4^2-}, CrOX4X2−\ce{CrO4^2-}] that do not have similar Lewis dot structure are :

    1. (1)A, B and E
    2. (2)A and E
    3. (3)B, C and D
    4. (4)C and D
  5. Q5 · MCQ · ThermodynamicsOpen
    Arrange the following isothermal processes in order of the magnitude of the work (pp – VV) involved between states 1 and 2.
    • (A)Expansion in single stage wAw_\mathrm{A}
    • (B)Expansion in multi stages wBw_\mathrm{B}
    • (C)Compression in single stage wCw_\mathrm{C}
    • (D)Compression in multi stages wDw_\mathrm{D}
    1. (1)∣wB∣>∣wA∣>∣wC∣>∣wD∣\lvert w_\mathrm{B}\rvert > \lvert w_\mathrm{A}\rvert > \lvert w_\mathrm{C}\rvert > \lvert w_\mathrm{D}\rvert
    2. (2)∣wC∣>∣wD∣>∣wA∣>∣wB∣\lvert w_\mathrm{C}\rvert > \lvert w_\mathrm{D}\rvert > \lvert w_\mathrm{A}\rvert > \lvert w_\mathrm{B}\rvert
    3. (3)∣wC∣>∣wD∣>∣wB∣>∣wA∣\lvert w_\mathrm{C}\rvert > \lvert w_\mathrm{D}\rvert > \lvert w_\mathrm{B}\rvert > \lvert w_\mathrm{A}\rvert
    4. (4)∣wB∣>∣wA∣>∣wD∣>∣wC∣\lvert w_\mathrm{B}\rvert > \lvert w_\mathrm{A}\rvert > \lvert w_\mathrm{D}\rvert > \lvert w_\mathrm{C}\rvert
  6. Q6 · MCQ · SolutionsOpen
    When 0.25 moles of a non-volatile, non-ionizable solute was dissolved in 1 mole of a solvent the vapor pressure of solution was x% of vapor pressure of pure solvent. What is x% ?
    1. (1)50%
    2. (2)60%
    3. (3)70%
    4. (4)80%
  7. Q7 · MCQ · EquilibriumOpen

    One mole each of He and A(g) are taken in a 10 L closed flask and heated to 400 K to establish the following equilibrium.

    A(g)⇌B(g)\ce{A(g) <=> B(g)}

    KCK_\mathrm{C} for this reaction at 400 K is 4.0. The partial pressures (in atm) of He and B(g) are respectively (at equilibrium).

    (Assume He, A(g) and B(g) behave as ideal gases)

    (Given : R=0.082R = 0.082 L atm K−1^{-1} mol−1^{-1})

    1. (1)3.28, 2.624
    2. (2)2.624, 3.28
    3. (3)3.28, 0.656
    4. (4)0.656, 6.56
  8. Consider the following data :
    ElectrolyteΛm∘\boldsymbol{\Lambda^\circ_\mathrm{m}} (S cm2^{\mathbf{2}} mol−1^{\mathbf{-1}})
    BaClX2\ce{BaCl2}x1x_1
    HX2SOX4\ce{H2SO4}x2x_2
    HClx3x_3

    BaSOX4\ce{BaSO4} is sparingly soluble in water. If the conductivity of the saturated BaSOX4\ce{BaSO4} solution is xx S cm−1^{-1} then the solubility product of BaSOX4\ce{BaSO4} can be given as.

    (Here Λm=Λm∘\Lambda_\mathrm{m} = \Lambda^\circ_\mathrm{m})

    1. (1)106x2α2(x1+x2−2x3)2\dfrac{10^{6}x^{2}}{\alpha^{2}(x_1+x_2-2x_3)^{2}}
    2. (2)x2(x1+x2−2x3)2\dfrac{x^{2}}{(x_1+x_2-2x_3)^{2}}
    3. (3)α2(x1+x2−2x3)2106x2\dfrac{\alpha^{2}(x_1+x_2-2x_3)^{2}}{10^{6}x^{2}}
    4. (4)x2(x1+x2+2x3)2\dfrac{x^{2}}{(x_1+x_2+2x_3)^{2}}
    We corrected a printing error in the original paper

    Source printed “(Here ∧m=∧m∘\wedge_\mathrm{m} = \wedge^\circ_\mathrm{m})” (logical-and sign for the Greek Λ\Lambda of the table).

  9. Given below are two statements :

    Statement-I : Aluminium is more electropositive than thallium as the standard electrode potential value of EAl3+/Al∘E^\circ_{\mathrm{Al^{3+}/Al}} is negative and ETl3+/Tl∘E^\circ_{\mathrm{Tl^{3+}/Tl}} is positive.

    Statement-II : The sum of first three ionization enthalpies of boron is very high when compared to that of aluminium. Due to this reason boron forms covalent compounds only and aluminium forms AlX3+\ce{Al^3+} ion.

    In the light of the above statements, choose the correct answer from the options given below.

    1. (1)Both Statement-I and Statement-II are true.
    2. (2)Both Statement-I and Statement-II are false.
    3. (3)Statement-I is true but Statement-II is false.
    4. (4)Statement-I is false but Statement-II is true.
  10. Q10 · MCQ · d- and f-BlockOpen
    The correct statements among the following are :
    • (A)Basic vanadium oxide is used in the manufacture of HX2SOX4\ce{H2SO4}.
    • (B)The spin-only magnetic moment value of the transition metal halide employed in Ziegler-Natta polymerization is 2.84 BM.
    • (C)The p-block metal compound employed in Ziegler-Natta polymerization has the metal in +3 oxidation state.
    • (D)The number of electrons present in the outer most ‘d' orbital of metal halide employed in Wacker process is 8.
    Choose the correct answer from the options given below :
    1. (1)A and B only
    2. (2)A, C and D only
    3. (3)C and D only
    4. (4)B, C and D only
  11. Match the List-I with List-II
    List-IList-II
    Electronic configuration ofCrystal Field
    tetrahedral metal ionStabilization Energy (Δt\boldsymbol{\Delta_\mathrm{t}})
    A.d2^2I.−0.6-0.6
    B.d4^4II.−0.8-0.8
    C.d6^6III.−1.2-1.2
    D.d8^8IV.−0.4-0.4
    Choose the correct answer from the options given below :
    1. (1)A-III, B-IV, C-II, D-I
    2. (2)A-III, B-I, C-IV, D-II
    3. (3)A-III, B-IV, C-I, D-II
    4. (4)A-II, B-I, C-IV, D-III
  12. Which of the following are true about the energy of the given d-orbitals of a tetrahedral complex ?
    • (A)dxy=dxz>dx2−y2\mathrm{d}_{xy} = \mathrm{d}_{xz} > \mathrm{d}_{x^2-y^2}
    • (B)dxy=dyz>dz2\mathrm{d}_{xy} = \mathrm{d}_{yz} > \mathrm{d}_{z^2}
    • (C)dx2−y2>dz2>dxz\mathrm{d}_{x^2-y^2} > \mathrm{d}_{z^2} > \mathrm{d}_{xz}
    • (D)dx2−y2=dz2<dxz\mathrm{d}_{x^2-y^2} = \mathrm{d}_{z^2} < \mathrm{d}_{xz}
    Choose the correct answer from the options given below :
    1. (1)A, B and D only
    2. (2)A and B only
    3. (3)B and D only
    4. (4)B, C and D only
  13. RfR_\mathrm{f} value for 2-methylpropene in a solvent system (Ethyl acetate + ether) is 0.42. 2-methylpropene is treated with dilute HX2SOX4\ce{H2SO4} to give major organic product (X). RfR_\mathrm{f} value for (X) in the same solvent system under identical condition will be :
    1. (1)0.42
    2. (2)0.82
    3. (3)0.62
    4. (4)0.12
  14. Given below are two statements :

    Statement-I : 2, 6-diethylcyclohexanone and 6-methyl-2-n-propylcyclohexanone are metamers.

    Statement-II : 2, 2, 6, 6-tetramethylcyclohexanone exhibits keto-enol tautomerism.

    In the light of the above statements, choose the correct answer from the options given below.

    1. (1)Both Statement-I and Statement-II are true.
    2. (2)Both Statement-I and Statement-II are false.
    3. (3)Statement-I is true but Statement-II is false.
    4. (4)Statement-I is false but Statement-II is true.
  15. Q15 · MCQ · HydrocarbonsOpen

    Given below are two statements :

    Statement-I : Methane can be prepared by decarboxylation of sodium ethanoate, Kolbe's electrolysis of sodium acetate and reaction of CHX3MgBr\ce{CH3MgBr} with water.

    Statement-II : Methane cannot be prepared from unsaturated hydrocarbons and by Wurtz reaction.

    In the light of the above statements, choose the correct answer from the options given below.

    1. (1)Both Statement-I and Statement-II are true.
    2. (2)Both Statement-I and Statement-II are false.
    3. (3)Statement-I is true but Statement-II is false.
    4. (4)Statement-I is false but Statement-II is true.
  16. Given below are two statements :

    Statement-I : 3-phenylpropene reacts with HBr and gives secondary alkyl bromide having a chiral carbon atom as the major product.

    Statement-II : Aryl chlorides and aryl cyanides can be prepared by Sandmeyer reaction as well as Gattermann reaction.

    In the light of the above statements, choose the correct answer from the options given below.

    1. (1)Both Statement-I and Statement-II are true.
    2. (2)Both Statement-I and Statement-II are false.
    3. (3)Statement-I is true but Statement-II is false.
    4. (4)Statement-I is false but Statement-II is true.
  17. Consider the following sequence of reactions
    The major product P is :
    1. (1)
    2. (2)
    3. (3)
    4. (4)
  18. Q18 · MCQ · AminesOpen

    Arrange the following compounds according to increasing order of boiling points.

    n-CX4HX9OH\ce{C4H9OH} (A), n-CX4HX9NHX2\ce{C4H9NH2} (B), n-CX4HX10\ce{C4H10} (C) and CX2HX5NHCX2HX5\ce{C2H5NHC2H5}(D).

    1. (1)C << B << A << D
    2. (2)D << C << B << A
    3. (3)C << D << B << A
    4. (4)D << B << A << C
  19. Q19 · MCQ · BiomoleculesOpen
    Match the List-I with List-II :
    List-IList-II
    Deficiency DiseaseVitamin
    A.ScurvyI.Pyridoxine
    B.ConvulsionsII.Vitamin A
    C.CheilosisIII.Ascorbic Acid
    D.XerophthalmiaIV.Riboflavin
    Choose the correct answer from the options given below :
    1. (1)A-I, B-III, C-II, D-IV
    2. (2)A-I, B-III, C-IV, D-II
    3. (3)A-III, B-I, C-IV, D-II
    4. (4)A-III, B-I, C-II, D-IV
  20. Q20 · MCQ · BiomoleculesOpen
    Match the List-I with List-II
    List-IList-II
    Amino acidPositive reaction/Test for
    functional group present in
    side chain of amino acid
    A.GlutamineI.Hinsberg's test
    B.LysineII.Neutral FeClX3\ce{FeCl3} test
    C.TyrosineIII.Ceric ammonium nitrate test
    D.SerineIV.Hoffman bromamide degradation
    Choose the correct answer from the options given below :
    1. (1)A-IV, B-II, C-I, D-III
    2. (2)A-IV, B-I, C-II, D-III
    3. (3)A-III, B-II, C-I, D-IV
    4. (4)A-IV, B-I, C-III, D-II
  21. First and second ionization enthalpies of lithium are 520 kJ mol−1^{-1} and 7297 kJ mol−1^{-1} respectively. Energy required to convert 3.5 mg lithium (g) into LiX2+\ce{Li^2+}(g) [Li(g)→LiX2+(g)\ce{Li(g) -> Li^2+(g)}] is kJ. (nearest integer)

    [Molar mass of Li = 7 g mol−1^{-1}]

    We corrected a printing error in the original paper

    Source printed the unit of the answer as “kJ mol−1^{-1}”; the energy for 3.5 mg of lithium is in kJ.

  22. Q22 · Numerical · AminesOpen
    Consider the following sequence of reactions.

    The percentage of nitrogen in the yellow product (X) formed is %.

    (Nearest Integer)

    (Given Molar mass in g mol−1^{-1} H : 1, C : 12, N : 14)

  23. 4.7 g of phenol is heated with Zn to give product X. If this reaction goes to 60% completion then the number of moles of compound X formed will be × 10−2\times\,10^{-2} (Nearest Integer)

    (Given molar mass in g mol−1^{-1} : H : 1, C : 12, O : 16)

  24. Q24 · Numerical · Chemical KineticsOpen

    Sucrose hydrolyses in acidic medium into glucose and fructose by first order rate law with t1/2=3t_{1/2} = 3 hour. The percentage of sucrose remaining after 6 hours is . (Nearest integer)

    (Given : log⁡2=0.3010\log 2 = 0.3010 and log⁡3=0.4771\log 3 = 0.4771)

  25. Q25 · Numerical · ThermodynamicsOpen
    Consider the reaction X⇌Y\ce{X <=> Y} at 300 K. If ΔHθ\Delta H^{\theta} and K are 28.40 kJ mol−1^{-1} and 1.8×10−71.8\times10^{-7} at the same temperature, then the magnitude of ΔSθ\Delta S^{\theta} for the reaction in J K−1^{-1} mol−1^{-1} is .(Nearest Integer). (Given : R=8.3R = 8.3 J K−1^{-1} mol−1^{-1}, ln⁡10=2.3\ln 10 = 2.3, log⁡3=0.48\log 3 = 0.48, log⁡2=0.30\log 2 = 0.30

Maths

  1. Let [⋅][\cdot] denote the greatest integer function. If the domain of the function f(x)=sin⁡−1(x+[x]3)f(x) = \sin^{-1}\left(\dfrac{x + [x]}{3}\right) is [α,β)[\alpha, \beta), then α2+β2\alpha^2 + \beta^2 is equal to:
    1. (1)2
    2. (2)5
    3. (3)10
    4. (4)13
  2. Let one root of the quadratic equation in xx: (k2−15k+27)x2+9(k−1)x+18=0(k^2 - 15k + 27)x^2 + 9(k - 1)x + 18 = 0 be twice the other. Then the length of the latus rectum of the parabola y2=6kxy^2 = 6kx is equal to:
    1. (1)4
    2. (2)6
    3. (3)8
    4. (4)12
  3. Q3 · MCQ · Conic SectionsOpen
    Let e1e_1 and e2e_2 be two distinct roots of the equation x2−ax+2=0x^2 - ax + 2 = 0. Let the sets {a∈R:e1\{a \in \mathbb{R} : e_1 and e2e_2 are the eccentricities of hyperbolas}=(α,β)\} = (\alpha, \beta), and {a∈R:e1\{a \in \mathbb{R} : e_1 and e2e_2 are the eccentricities of an ellipse and a hyperbola, respectively}=(γ,∞)\} = (\gamma, \infty). The α2+β2+γ2\alpha^2 + \beta^2 + \gamma^2 is equal to:
    1. (1)18
    2. (2)22
    3. (3)26
    4. (4)34
  4. Let the set of all values of k∈Rk \in \mathbb{R} such that the equation z(zˉ+2+i)+k(2+3i)=0z(\bar{z} + 2 + i) + k(2 + 3i) = 0, z∈Cz \in \mathbb{C}, has at least one solution, be the interval [α,β][\alpha, \beta]. Then 9(α+β)9(\alpha + \beta) is equal to:
    1. (1)−10-10
    2. (2)−8-8
    3. (3)101310\sqrt{13}
    4. (4)8138\sqrt{13}
  5. The value of 13−23+33−…+1531^3 - 2^3 + 3^3 - \ldots + 15^3 is:
    1. (1)1706
    2. (2)1856
    3. (3)1982
    4. (4)2403
  6. The sum of the first ten terms of an A.P. is 160 and the sum of the first two terms of a G.P. is 8. If the first term of the A.P. is equal to the common ratio of the G.P. and the first term of the G.P. is equal to common difference of the A.P., then the sum of all possible values of the first term of the G.P. is:
    1. (1)349\dfrac{34}{9}
    2. (2)3413\dfrac{34}{13}
    3. (3)329\dfrac{32}{9}
    4. (4)3213\dfrac{32}{13}
  7. The number of 4-letter words, with or without meaning, each consisting of two vowels and two consonants that can be formed from the letters of the word INCONSEQUENTIAL, without repeating any letter, is:
    1. (1)2670
    2. (2)2840
    3. (3)2920
    4. (4)3600
  8. If the coefficients of the middle terms in the binomial expansions of (1+αx)26(1 + \alpha x)^{26} and (1−αx)28(1 - \alpha x)^{28}, α≠0\alpha \neq 0, are equal, then the value of α\alpha is:
    1. (1)1
    2. (2)1413\dfrac{14}{13}
    3. (3)277\dfrac{27}{7}
    4. (4)727\dfrac{7}{27}
  9. Q9 · MCQ · StatisticsOpen
    A data consists of 20 observations x1,x2,…,x20x_1, x_2, \ldots, x_{20}. If ∑i=120(xi+5)2=2500\displaystyle\sum_{i=1}^{20}(x_i + 5)^2 = 2500 and ∑i=120(xi−5)2=100\displaystyle\sum_{i=1}^{20}(x_i - 5)^2 = 100, then the ratio of mean to standard deviation of this data is:
    1. (1)2:12:1
    2. (2)3:13:1
    3. (3)3:23:2
    4. (4)4:14:1
  10. Q10 · MCQ · ProbabilityOpen
    A bag contains (N+1)(N + 1) coins – NN fair coins, and one coin with ‘Head' on both sides. A coin is selected at random and tossed. If the probability of getting ‘Head' is 916\dfrac{9}{16}, then NN is equal to:
    1. (1)5
    2. (2)7
    3. (3)8
    4. (4)9
  11. Q11 · MCQ · Conic SectionsOpen
    If the eccentricity ee of the hyperbola x2a2−y2b2=1\dfrac{x^2}{a^2} - \dfrac{y^2}{b^2} = 1, passing through (6,43)\left(6, 4\sqrt3\right), satisfies 15(e2+1)=34e15(e^2 + 1) = 34e, then the length of the latus rectum of the hyperbola x2b2−y22(a2+1)=1\dfrac{x^2}{b^2} - \dfrac{y^2}{2(a^2 + 1)} = 1 is:
    1. (1)10
    2. (2)20
    3. (3)25
    4. (4)30
  12. Q12 · MCQ · Conic SectionsOpen
    Let chord PQPQ of length 3133\sqrt{13} of the parabola y2=12xy^2 = 12x be such that the ordinates of points PP and QQ are in the ratio 1:21:2. If the chord PQPQ subtends an angle α\alpha at the focus of the parabola, then sin⁡α\sin\alpha is equal to:
    1. (1)35\dfrac35
    2. (2)45\dfrac45
    3. (3)513\dfrac{5}{13}
    4. (4)1213\dfrac{12}{13}
  13. Let 0<α<10 < \alpha < 1, β=13α\beta = \dfrac{1}{3\alpha} and tan⁡−1(1−α)+tan⁡−1(1−β)=π4\tan^{-1}(1 - \alpha) + \tan^{-1}(1 - \beta) = \dfrac{\pi}{4}. Then 6(α+β)6(\alpha + \beta) is equal to:
    1. (1)6
    2. (2)7
    3. (3)8
    4. (4)9
  14. Q14 · MCQ · TrigonometryOpen
    Let S={θ∈(−2π,2π):cos⁡θ+1=3sin⁡θ}S = \left\{\theta \in (-2\pi, 2\pi) : \cos\theta + 1 = \sqrt3\sin\theta\right\}. Then ∑θ∈Sθ\displaystyle\sum_{\theta\in S}\theta is equal to:
    1. (1)−2π3-\dfrac{2\pi}{3}
    2. (2)−4π3-\dfrac{4\pi}{3}
    3. (3)2π3\dfrac{2\pi}{3}
    4. (4)4π3\dfrac{4\pi}{3}
  15. Q15 · MCQ · 3D GeometryOpen
    Let the image of the point P(1,6,a)P(1, 6, a) in the line L:x1=y−12=z−a+1bL : \dfrac{x}{1} = \dfrac{y - 1}{2} = \dfrac{z - a + 1}{b}, b>0b > 0, be (a3,0,a+c)\left(\dfrac{a}{3}, 0, a + c\right). If S(α,β,γ)S(\alpha, \beta, \gamma), α>0\alpha > 0, is the point on LL such that the distance of SS from the foot of perpendicular from the point PP on LL is 2142\sqrt{14}, then α+β+γ\alpha + \beta + \gamma is equal to:
    1. (1)19
    2. (2)20
    3. (3)21
    4. (4)22
  16. Q16 · MCQ · 3D GeometryOpen
    Let a line LL be perpendicular to both the lines L1:x+13=y+35=z+57andL2:x−21=y−44=z−67.L_1 : \dfrac{x + 1}{3} = \dfrac{y + 3}{5} = \dfrac{z + 5}{7} \quad\text{and}\quad L_2 : \dfrac{x - 2}{1} = \dfrac{y - 4}{4} = \dfrac{z - 6}{7}. If θ\theta is the acute angle between the lines LL and L3:x−872=y−471=z2,L_3 : \dfrac{x - \frac87}{2} = \dfrac{y - \frac47}{1} = \dfrac{z}{2}, then tan⁡θ\tan\theta is equal to:
    1. (1)322\dfrac32\sqrt2
    2. (2)522\dfrac52\sqrt2
    3. (3)532\dfrac53\sqrt2
    4. (4)432\dfrac43\sqrt2
  17. The value of lim⁡x→0(x2sin⁡2xx2−sin⁡2x)\displaystyle\lim_{x\to0}\left(\frac{x^2\sin^2x}{x^2 - \sin^2x}\right) is:
    1. (1)2
    2. (2)3
    3. (3)4
    4. (4)6
  18. The value of the integral ∫−π4π4(32cos⁡4x1+esin⁡x)dx\displaystyle\int_{-\frac{\pi}{4}}^{\frac{\pi}{4}}\left(\frac{32\cos^4x}{1 + e^{\sin x}}\right)dx is:
    1. (1)4π+24\pi + 2
    2. (2)3π+83\pi + 8
    3. (3)3π+43\pi + 4
    4. (4)4π+34\pi + 3
  19. The area of the region {(x,y):0≤y≤6−x, y2≥4x−3, x≥0}\{(x, y) : 0 \le y \le 6 - x,\ y^2 \ge 4x - 3,\ x \ge 0\} is:
    1. (1)8
    2. (2)9
    3. (3)12
    4. (4)15
  20. Let ee be the base of natural logarithm and let f:{1,2,3,4}→{1,e,e2,e3}andg:{1,e,e2,e3}→{1,12,13,14}f : \{1, 2, 3, 4\} \to \{1, e, e^2, e^3\} \quad\text{and}\quad g : \{1, e, e^2, e^3\} \to \left\{1, \dfrac12, \dfrac13, \dfrac14\right\} be two bijective functions such that ff is strictly decreasing and gg is strictly increasing. If ϕ(x)=[f−1{g−1(12)}]x,\phi(x) = \left[f^{-1}\left\{g^{-1}\left(\dfrac12\right)\right\}\right]^x, then the area of the region R={(x,y):x2≤y≤ϕ(x), 0≤x≤1}R = \{(x, y) : x^2 \le y \le \phi(x),\ 0 \le x \le 1\} is:
    1. (1)3−log⁡e(2)3log⁡e(2)\dfrac{3 - \log_e(2)}{3\log_e(2)}
    2. (2)13log⁡e(2)\dfrac{1}{3\log_e(2)}
    3. (3)3+log⁡e(2)3 + \log_e(2)
    4. (4)3+log⁡e(2)2+log⁡e(3)\dfrac{3 + \log_e(2)}{2 + \log_e(3)}
  21. Q21 · Numerical · Matrices & DeterminantsOpen
    Let A=[−11−1101001]A = \begin{bmatrix} -1 & 1 & -1\\ 1 & 0 & 1\\ 0 & 0 & 1\end{bmatrix} satisfy A2+α(adj⁡(adj⁡(A)))+β(adj⁡(A)(adj⁡(adj⁡(A))))=[2−22−20−100−1]A^2 + \alpha(\operatorname{adj}(\operatorname{adj}(A))) + \beta(\operatorname{adj}(A)(\operatorname{adj}(\operatorname{adj}(A)))) = \begin{bmatrix} 2 & -2 & 2\\ -2 & 0 & -1\\ 0 & 0 & -1\end{bmatrix} for Some α,β∈R\alpha, \beta \in \mathbb{R}. Then (α−β)2(\alpha - \beta)^2 is equal to .
  22. Q22 · Numerical · CirclesOpen
    Let the centre of the circle x2+y2+2gx+2fy+25=0x^2 + y^2 + 2gx + 2fy + 25 = 0 be in the first quadrant and lie on the line 2x−y=42x - y = 4. Let the area of an equilateral triangle inscribed in the circle be 27327\sqrt3. Then the square of the length of the chord of the circle on the line x=1x = 1 is .
  23. Q23 · Numerical · VectorsOpen
    If a⃗=i^+j^+k^\vec a = \hat i + \hat j + \hat k, b⃗=j^−k^\vec b = \hat j - \hat k and c⃗\vec c be three vectors such that a⃗×c⃗=b⃗\vec a\times\vec c = \vec b and a⃗⋅c⃗=3\vec a\cdot\vec c = 3, then c⃗⋅(a⃗−2b⃗)\vec c\cdot(\vec a - 2\vec b) is equal to .
  24. Q24 · Numerical · TrigonometryOpen
    For the functions f(θ)=αtan⁡2θ+βcot⁡2θf(\theta) = \alpha\tan^2\theta + \beta\cot^2\theta, and g(θ)=αsin⁡2θ+βcos⁡2θg(\theta) = \alpha\sin^2\theta + \beta\cos^2\theta, α>β>0\alpha > \beta > 0, let min⁡0<θ<π2f(θ)=max⁡0<θ<πg(θ)\displaystyle\min_{0<\theta<\frac{\pi}{2}} f(\theta) = \max_{0<\theta<\pi} g(\theta). If the first term of a G.P. is (α2β)\left(\dfrac{\alpha}{2\beta}\right), its common ratio is (2βα)\left(\dfrac{2\beta}{\alpha}\right) and the sum of its first 10 terms is mn\dfrac{m}{n}, gcd⁡(m,n)=1\gcd(m, n) = 1, then m+nm + n is equal to .
  25. Q25 · Numerical · Differential EquationsOpen
    Let y=y(x)y = y(x) be the solution of the differential equation (x2−xx2−1)dy+(y(x−x2−1)−x)dx=0,\left(x^2 - x\sqrt{x^2 - 1}\right)dy + \left(y\left(x - \sqrt{x^2 - 1}\right) - x\right)dx = 0, x≥1x \ge 1. If y(1)=1y(1) = 1, then the greatest integer less than y(5)y\left(\sqrt5\right) is .