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MathsJEE Main 6 Apr 2026, Shift 1·Q17·MCQ·Easy–moderate

Limits, Continuity & Differentiability · Limits by series expansion

The value of lim⁡x→0(x2sin⁡2xx2−sin⁡2x)\displaystyle\lim_{x\to0}\left(\frac{x^2\sin^2x}{x^2 - \sin^2x}\right) is:
  1. (1)2
  2. (2)3
  3. (3)4
  4. (4)6

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