AktiraAktira JEE
Subscribe
MathsJEE Main 6 Apr 2026, Shift 2·Q2·MCQ·Moderate

Sequences & Series · Sum of geometric progression

Consider the quadratic equation (n2−2n+2)x2−3x+(n2−2n+2)2=0(n^2 - 2n + 2)x^2 - 3x + (n^2 - 2n + 2)^2 = 0, n∈Rn \in \mathbb{R}. Let α\alpha be the minimum value of the product of its roots and β\beta be the maximum value of the sum of its roots. Then the sum of the first six terms of the G.P., whose first term is α\alpha and the common ratio is αβ\dfrac{\alpha}{\beta}, is:
  1. (1)6137\dfrac{61}{37}
  2. (2)12181\dfrac{121}{81}
  3. (3)364243\dfrac{364}{243}
  4. (4)1093729\dfrac{1093}{729}

Video solution coming soon

We're animating every PYQ step by step. Subscribe to get them first.

Subscribe

See the full 6 Apr 2026, Shift 2 paper

More on Sum of geometric progression