MathsJEE Main 6 Apr 2026, Shift 2·Q23·Numerical·Moderate

Circles · Points on circle equidistant

Let the line

x - y = 4

intersect the circle

C : (x - 4)^2 + (y + 3)^2 = 9

at the points

Q

and

R

. If

P(\alpha, \beta)

is a point on

C

such that

PQ = PR

, then

(6\alpha + 8\beta)^2

is equal to .

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