MathsJEE Main 6 Apr 2026, Shift 2·Q24·Numerical·Moderate

3D Geometry · Image of point in line

Let the image of the point

P(0, -5, 0)

in the line

\dfrac{x-1}{2} = \dfrac{y}{1} = \dfrac{z+1}{-2}

be the point

R

and the image of the point

Q\left(0, \dfrac{-1}{2}, 0\right)

in the line

\dfrac{x-1}{-1} = \dfrac{y+9}{4} = \dfrac{z+1}{1}

be the point

S

. Then the square of the area of the parallelogram

PQRS

is .

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