MathsJEE Main 8 Apr 2026, Shift 2·Q22·Numerical·Moderate

Definite Integration · Trigonometric definite integrals

\int_{\pi/6}^{\pi/4}\left(\cot\left(x - \frac{\pi}{3}\right)\cot\left(x + \frac{\pi}{3}\right) + 1\right)dx = \alpha\log_e\left(\sqrt3 - 1\right),

then

9\alpha^2

is equal to .

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