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JEE Main 2026

JEE Main 8 Apr 2026, Shift 2

75 questions. Answers are hidden — tap “Show answer” under each one.

Physics

  1. A new unit (α\alpha) of length is chosen such that it is equal to the distance travelled by light in vacuum in 1 s. What is the distance between Venus and Earth in terms of α\alpha units if light takes 6 min. 40 s to cover this distance?
    1. (1)200 α200\,\alpha
    2. (2)400 α400\,\alpha
    3. (3)300 α300\,\alpha
    4. (4)500 α500\,\alpha
    We corrected a printing error in the original paper

    Source printed “such that it is equal to the speed of light in vacuum” (a length cannot equal a speed); corrected to the intended “equal to the distance travelled by light in vacuum in 1 s”.

  2. Consider the equation H=xp ϵq ErtsH = \dfrac{x^{p}\,\epsilon^{q}\,E^{r}}{t^{s}}
    Where H=H = magnetic field intensity; E=E = electric field; ϵ=\epsilon = permittivity, x=x = distance, t=t = time. The values of pp, qq, rr and ss respectively are:
    1. (1)1, 1, 1, 1
    2. (2)−1-1, 1, 2, 1
    3. (3)1, −1-1, −2-2, 1
    4. (4)−1-1, −2-2, −2-2, 1
    We corrected a printing error in the original paper

    Source printed “H=H = magnetic field” (with H=BH = B in tesla no option fits); corrected to the intended “H=H = magnetic field intensity” (A/m).

  3. A car moving with a speed of 54 km/h takes a turn of radius 20 m. A simple pendulum is suspended from the ceiling of the car. Determine the angle made by the string of the pendulum with the vertical during the turning. (Take g=10 m/s2g = 10\ \mathrm{m/s^2})
    1. (1)tan⁡−1(0.5)\tan^{-1}(0.5)
    2. (2)tan⁡−1(0.75)\tan^{-1}(0.75)
    3. (3)tan⁡−1(1.125)\tan^{-1}(1.125)
    4. (4)tan⁡−1(0.25)\tan^{-1}(0.25)
  4. A gas balloon is going up with a constant velocity of 10 m/s. When this balloon reached a height of 75 m, a stone is dropped from it and balloon keeps moving up with the same velocity. The height of the balloon when the stone hits the ground is m. (Take g=10 m/s2g = 10\ \mathrm{m/s^2})
    1. (1)85
    2. (2)150
    3. (3)129
    4. (4)125
  5. Q5 · MCQ · Ray OpticsOpen
    A thin biconvex lens is prepared from the glass (μ=1.5\mu = 1.5) both curved surfaces of which have equal radii of 20 cm each. Left side surface of the lens is silvered from outside to make it reflecting. To have the position of image and object at the same place, the object should be placed, from the lens at a distance of cm.
    1. (1)10
    2. (2)12.5
    3. (3)13
    4. (4)13.5
  6. Two identical bodies, projected with the same speed at two different angles cover the same horizontal range RR. If the times of flight of these bodies are 5 s and 10 s, respectively, then the value of RR is m. (Take g=10 m/s2g = 10\ \mathrm{m/s^2})
    1. (1)250
    2. (2)25
    3. (3)500
    4. (4)125
    We corrected a printing error in the original paper

    Source printed “If the time of flight of these bodies are”.

  7. A solid cylinder having radius RR and length LL is slipping on a rough horizontal plane. At time t=0t = 0 the cylinder has a translational velocity v0=49v_0 = 49 m/s, perpendicular to its axis and a rotational velocity v0/4Rv_0/4R about the centre. The time taken by the cylinder to start rolling is seconds. (coefficient of kinetic friction μK=0.25\mu_K = 0.25 and g=9.8 m/s2g = 9.8\ \mathrm{m/s^2})
    1. (1)15
    2. (2)5
    3. (3)10
    4. (4)7.5
  8. A liquid of density 600 kg/m3600\ \mathrm{kg/m^3} is flowing steadily in a tube of varying cross-section. The cross-section at a point A is 1.0 cm21.0\ \mathrm{cm^2} and that at B is 20 mm220\ \mathrm{mm^2}. Both the points A and B are in same horizontal plane, the speed of the liquid at A is 10 cm/s. The difference in pressures at A and B points is Pa.
    1. (1)18
    2. (2)144
    3. (3)36
    4. (4)72
    We corrected a printing error in the original paper

    Source printed “A liquid of density 600 kg/m3^3 flowing steadily” (verb missing); “The difference is pressures”.

  9. A spherical liquid drop of radius RR acquires the terminal velocity v1v_1 when it falls through a gas of viscosity η\eta. Now the drop is broken into 64 identical droplets and each droplet acquires terminal velocity v2v_2 falling through the same gas. The ratio of terminal velocities v1/v2v_1/v_2 is .
    1. (1)4
    2. (2)0.25
    3. (3)32
    4. (4)16
    We corrected a printing error in the original paper

    Source printed “when falls through a gas”.

  10. Q10 · MCQ · ThermodynamicsOpen
    One mole of diatomic gas having rotational modes only is kept is a cylinder with a piston system. The cross-section area of the cylinder is 4 cm24\ \mathrm{cm^2}. The gas is heated slowly to raise the temperature by 1.2 ∘1.2\ ^\circC during which the piston moves by 25 mm. The amount of heat supplied to the gas is J. (Atmospheric pressure =100= 100 kPa, R=8.3R = 8.3 J/mol.K) (Neglect mass of the piston)
    1. (1)24.8
    2. (2)25
    3. (3)15.04
    4. (4)29.98

    Flawed question. The data are inconsistent: with a free piston at 100 kPa, PΔVP\Delta V must equal nRΔT=9.96nR\Delta T = 9.96 J, but a 25 mm travel gives 1.0 J; no option equals the consistent Q=34.9Q = 34.9 J, and the key 25 is only the option nearest to 24.9+1.0=25.924.9 + 1.0 = 25.9 J. It is shown for completeness and is left out of practice tests.

  11. Q11 · MCQ · ThermodynamicsOpen
    Initial pressure and volume of a monoatomic ideal gas are PP and VV. The change in internal energy of this gas in adiabatic expansion to volume Vfinal=27 VV_{\text{final}} = 27\,V is J.
    1. (1)−2PV(33−1)-2PV\left(3\sqrt3 - 1\right)
    2. (2)43PV\dfrac43 PV
    3. (3)−43PV-\dfrac43 PV
    4. (4)34PV\dfrac34 PV
  12. Q12 · MCQ · OscillationsOpen
    The frequency of oscillation of a mass mm suspended by spring is ν1\nu_1. If the length of the spring is cut to half, the same mass oscillates with frequency ν2\nu_2. The value of ν2ν1\dfrac{\nu_2}{\nu_1} is .
    1. (1)1
    2. (2)2
    3. (3)2\sqrt2
    4. (4)3\sqrt3
    We corrected a printing error in the original paper

    Source printed the frequencies with a Latin vv (v1v_1, v2v_2) for ν\nu.

  13. A monochromatic source of light operating at 15 kW emits 2.5×10222.5\times10^{22} photons/s. The region of an electromagnetic spectrum to which the emitted electromagnetic radiation belongs is . (Take h=6.6×10−34h = 6.6\times10^{-34} J.s and c=3×108c = 3\times10^{8} m/s).
    1. (1)Microwave
    2. (2)Infrared
    3. (3)Visible
    4. (4)Ultraviolet
    We corrected a printing error in the original paper

    Source printed “to which the emitted electromagnetic radiation belongs to”.

  14. A current carrying circular loop of radius 2 cm with unit normal n^=k^+i^2\hat n = \dfrac{\hat k + \hat i}{\sqrt2} is placed in a magnetic field, B⃗=B0(3i^+2k^)\vec B = B_0(3\hat i + 2\hat k). If B0=4×10−3B_0 = 4\times10^{-3} T and current I=1002I = 100\sqrt2 A, the torque experienced by the loop is Wb.A. (π=3.14\pi = 3.14)
    1. (1)16×10−5 k^16\times10^{-5}\,\hat k
    2. (2)5024×10−7 k^5024\times10^{-7}\,\hat k
    3. (3)5024×10−7 i^5024\times10^{-7}\,\hat i
    4. (4)5024×10−7 j^5024\times10^{-7}\,\hat j
  15. A 30 cm long solenoid has 10 turns per cm and area of 5 cm25\ \mathrm{cm^2}. The current through the solenoid coil varies from 2 A to 4 A in 3.14 s. The e.m.f. induced in the coil is α×10−5\alpha\times10^{-5} V. The value of α\alpha is .
    1. (1)60
    2. (2)12
    3. (3)120
    4. (4)34
    We corrected a printing error in the original paper

    Source printed “varies from 2 A to 4 A is 3.14 s”; “The value α\alpha is”.

  16. Two point charges q1=3 μq_1 = 3\ \muC and q2=−4 μq_2 = -4\ \muC are placed at points (2i^+3j^+3k^)(2\hat i + 3\hat j + 3\hat k) and (i^+j^+k^)(\hat i + \hat j + \hat k) respectively. Force on charge q2q_2 is N. (Take 14πϵ0=9×109 SI Units)\left(\text{Take } \dfrac{1}{4\pi\epsilon_0} = 9\times10^{9}\ \text{SI Units}\right)
    1. (1)(12i^+24j^+24k^)×10−3(12\hat i + 24\hat j + 24\hat k)\times10^{-3}
    2. (2)(4i^+8j^+8k^)×10−3(4\hat i + 8\hat j + 8\hat k)\times10^{-3}
    3. (3)(3i^+6j^+6k^)×10−3(3\hat i + 6\hat j + 6\hat k)\times10^{-3}
    4. (4)(−4i^−8j^−8k^)×10−3(-4\hat i - 8\hat j - 8\hat k)\times10^{-3}
  17. Q17 · MCQ · Ray OpticsOpen
    Light ray incident along a vector AO→(AO→=2i^−3j^)\overrightarrow{AO}\left(\overrightarrow{AO} = 2\hat i - 3\hat j\right) emerges out along vector OB→(OB→=Ci^−4j^)\overrightarrow{OB}\left(\overrightarrow{OB} = C\hat i - 4\hat j\right) as shown in the figure below. The value of CC is .
    1. (1)1.6
    2. (2)0.16
    3. (3)11.6
    4. (4)16
  18. Let K1K_1 and K2K_2 be the maximum kinetic energies of photoelectrons emitted from a surface of a given material for the light of wavelength λ1\lambda_1 and λ2\lambda_2, respectively. If λ1=2λ2\lambda_1 = 2\lambda_2 then the work function of material is given by:
    1. (1)K2+2K1K_2 + 2K_1
    2. (2)2K2−K12K_2 - K_1
    3. (3)K1−2K2K_1 - 2K_2
    4. (4)K2−2K1K_2 - 2K_1
    We corrected a printing error in the original paper

    Source printed “K1K_1 and K2K_2 be the maximum kinetic energies” (“Let” missing).

  19. Q19 · MCQ · NucleiOpen
    Two radioactive substances A and B of mass numbers 200 and 212 respectively, show spontaneous α\alpha-decay with same Q value of 1 MeV. The ratio of energies of α\alpha-rays produced by A and B is .
    1. (1)25482650\dfrac{2548}{2650}
    2. (2)27062646\dfrac{2706}{2646}
    3. (3)25972600\dfrac{2597}{2600}
    4. (4)28622499\dfrac{2862}{2499}
    We corrected a printing error in the original paper

    Source printed “Two radioactive substances … shows”.

  20. The output YY for the given inputs AA and BB to the circuit is:
    1. (1)
    2. (2)
    3. (3)
    4. (4)
  21. A parallel plate capacitor is having separation between plates 0.885 mm. It has a capacitance of 1 μ1\ \muF when the space between the plates is filled with an insulating material of resistivity 1×1013 Ω1\times10^{13}\ \Omegam and resistance 17.7×1014 Ω17.7\times10^{14}\ \Omega. Relative permittivity of the insulating material is α×107\alpha\times10^{7}. The value of α\alpha is .
    (Take permittivity of free space =8.85×10−12= 8.85\times10^{-12} F/m)
  22. Q22 · Numerical · Wave OpticsOpen
    Some distant star is to be observed by some telescope of diameter of objective lens a, at an angular resolution of 3.0×10−73.0\times10^{-7} radian. If the wavelength of light from the star reaching the telescope is 500 nm, the minimum diameter of the objective lens of the telescope is cm. (Nearest integer)
    We corrected a printing error in the original paper

    Source printed “Some distance star”.

  23. A 5 mg particle carrying a charge of 5π×10−65\pi\times10^{-6} C is moving with velocity of (3i^+2k^)×10−2(3\hat i + 2\hat k)\times10^{-2} m/s in a region having magnetic field B⃗=0.1 k^ Wb/m2\vec B = 0.1\,\hat k\ \mathrm{Wb/m^2}. It moves a distance of α\alpha meter along k^\hat k when it completes 5 revolutions. The value of α\alpha is .
  24. Q24 · Numerical · Current ElectricityOpen
    The stored charge in the capacitor in steady state of the following circuit is μ\muC.
  25. Q25 · Numerical · Motion in a Straight LineOpen
    Two masses of 3.4 kg and 2.5 kg are accelerated from an initial speed of 5 m/s and 12 m/s, respectively. The distances traversed by the masses in the 5th5^{\text{th}} second are 104 m and 129 m, respectively. The ratio of their momenta after 10 s is x8\dfrac{x}{8}. The value of xx is .

Chemistry

  1. Match List-I with List-II.
    List-IList-II
    Mass of substanceNumber of atoms
    A.1.8 mg waterI.2×10−4×NA2\times10^{-4}\times N_\mathrm{A}
    B.9.8 mg sulphuric acidII.1.5×10−4×NA1.5\times10^{-4}\times N_\mathrm{A}
    C.1.8 mg carbonIII.3×10−4×NA3\times10^{-4}\times N_\mathrm{A}
    D.5.85 mg salt (NaCl)IV.7×10−4×NA7\times10^{-4}\times N_\mathrm{A}
    Choose the correct answer from the options given below :
    1. (1)A-IV, B-III, C-I, D-II
    2. (2)A-III, B-II, C-IV, D-I
    3. (3)A-III, B-IV, C-II, D-I
    4. (4)A-III, B-IV, C-I, D-II
  2. Q2 · MCQ · SolutionsOpen

    Given below are two statements :

    Given : Molar mass of C, H, O, Cl are 12, 1, 16 and 35.5 g mol−1^{-1}, respectively.

    Statement I : In 30%(w/w) solution of methanol in CClX4\ce{CCl4} (at T K), the mole fraction of CClX4\ce{CCl4} is equal to 0.33.

    Statement II : Mixture of methanol and CClX4\ce{CCl4} shows positive deviation from Raoult's law.

    In the light of the above statements, choose the correct answer from the option given below :

    1. (1)Both Statement I and Statement II are true
    2. (2)Both Statement I and Statement II are false
    3. (3)Statement I is true but Statement II are false
    4. (4)Statement I is false but Statement II are true
    We corrected a printing error in the original paper

    Source printed “shows positive deviation deviation from Raoult's law” and “are ture” in options (1) and (4).

  3. Bromine trifluoride autoionizes to form BrF2⊕\mathrm{BrF_2^{\oplus}} and BrF4⊖\mathrm{BrF_4^{\ominus}}. The shapes of the cation and anion are respectively , and .
    1. (1)bent, square planar
    2. (2)linear, square planar
    3. (3)bent, see-saw
    4. (4)linear, tetrahedral
  4. Q4 · MCQ · SolutionsOpen
    Which of the following are not correct ?
    • (A)For water, magnitude of KbK_\mathrm{b} is more than the magnitude of KfK_\mathrm{f}.
    • (B)The elevation in boiling point of water when a non-volatile solute is added to it is larger in magnitude than its depression in freezing point.
    • (C)Osmotic pressure measurement is preferred over any other colligative property to determine molar mass of proteins and polymers.
    • (D)The dimerised form of benzoic acid in benzene is
    Choose the correct answer from the options given below :
    1. (1)A and B only
    2. (2)A and D only
    3. (3)A, B and D only
    4. (4)A, C and D only
    We corrected a printing error in the original paper

    Source printed “non-volative solute”.

  5. Q5 · MCQ · EquilibriumOpen

    Consider the following reactions in which all the reactants and products are present in gaseous state

    2xy⇌x2+y22\mathrm{xy} \rightleftharpoons \mathrm{x_2} + \mathrm{y_2}   K1=2.5×105K_1 = 2.5\times10^{5}

    xy+12z2⇌xyz\mathrm{xy} + \dfrac{1}{2}\mathrm{z_2} \rightleftharpoons \mathrm{xyz}   K2=5×10−3K_2 = 5\times10^{-3}

    The value of K3K_3 for the equilibrium

    12x2+12y2+12z2⇌xyz\dfrac{1}{2}\mathrm{x_2} + \dfrac{1}{2}\mathrm{y_2} + \dfrac{1}{2}\mathrm{z_2} \rightleftharpoons \mathrm{xyz} is :

    1. (1)2.5×10−32.5\times10^{-3}
    2. (2)2.5×1032.5\times10^{3}
    3. (3)1.0×10−51.0\times10^{-5}
    4. (4)5×10−35\times10^{-3}
    We corrected a printing error in the original paper

    Source printed “present in gasesous state”.

  6. Given at 298 K : EFe2+/Fe⊖=XE^{\ominus}_{\mathrm{Fe^{2+}/Fe}} = X Volt

     EFe3+/Fe⊖=YE^{\ominus}_{\mathrm{Fe^{3+}/Fe}} = Y Volt

    The EFe3+/Fe2+⊖E^{\ominus}_{\mathrm{Fe^{3+}/Fe^{2+}}} in Volt at 298 K is given by :

    1. (1)2X−3Y2X - 3Y
    2. (2)3Y−2X3Y - 2X
    3. (3)3Y+2X3Y + 2X
    4. (4)Y+XY + X
  7. Given below are two statements :

    R=8.314R = 8.314 J K−1^{-1} mol−1^{-1} and 1 cal =4.2= 4.2 J

    Statement I : When Ea =12.6= 12.6 kcal/mol, the room temperature rate constant is doubled by a 10∘^\circC increase in temperature (298 K to 308 K)

    Statement II : For a first order reaction A→B\ce{A -> B},

    Here [A]0[\mathrm{A}]_0 is the initial concentration of A and t1/2t_{1/2} is half-life of reaction.

    In the light of the above statements, choose the correct answer from the option given below :

    1. (1)Both Statement I and Statement II are true
    2. (2)Both Statement I and Statement II are false
    3. (3)Statement I is true but Statement II are false
    4. (4)Statement I is false but Statement II are true
  8. Match List-I with List-II.
    List-IList-II
    Electronic configuration of neutral atom (where n = 2)1st^\mathrm{st} Ionization Energy (kJ mol−1^{-1})
    A.ns2^2I.2080
    B.ns2^2np1^1II.899
    C.ns2^2np3^3III.800
    D.ns2^2np6^6IV.1402
    Choose the correct answer from the options given below :
    1. (1)A-II, B-III, C-IV, D-I
    2. (2)A-IV, B-III, C-II, D-I
    3. (3)A-III, B-II, C-IV, D-I
    4. (4)A-III, B-II, C-I, D-IV
  9. Find the correct statements related to group 15 hydrides.
    • (A)Reducing nature increases from NHX3\ce{NH3} to BiHX3\ce{BiH3}
    • (B)Tendency to donate lone pair of electrons decreases from NHX3\ce{NH3} to BiHX3\ce{BiH3}
    • (C)The stability of hydrides decreases from NHX3\ce{NH3} to BiHX3\ce{BiH3}
    • (D)HEH bond angle decreases from NHX3\ce{NH3} to SbHX3\ce{SbH3} (E = Elements of group 15)
    Choose the correct answer from the options given below :
    1. (1)A and B only
    2. (2)B and C only
    3. (3)A, B, C and D
    4. (4)A, C and D only
  10. Q10 · MCQ · d- and f-BlockOpen

    Given below are two statements :

    Statement I : The number of pairs among [TiX4+\ce{Ti^4+}, VX2+\ce{V^2+}], [VX2+\ce{V^2+}, MnX2+\ce{Mn^2+}], [MnX2+\ce{Mn^2+}, FeX3+\ce{Fe^3+}] and [VX2+\ce{V^2+}, CrX2+\ce{Cr^2+}] in which both ions are coloured is 3.

    Statement II : The number of pairs among [LaX3+\ce{La^3+}, YbX2+\ce{Yb^2+}], [LuX3+\ce{Lu^3+}, CeX4+\ce{Ce^4+}] and [AcX3+\ce{Ac^3+}, LrX3+\ce{Lr^3+}] ions in which both are diamagnetic is 3.

    In the light of the above statements, choose the correct answer from the option given below :

    1. (1)Both Statement I and Statement II are correct
    2. (2)Both Statement I and Statement II are incorrect
    3. (3)Statement I is correct but Statement II are incorrect
    4. (4)Statement I is incorrect but Statement II are correct
    We corrected a printing error in the original paper

    Source printed “The number pairs among” in Statement II.

  11. Q11 · MCQ · d- and f-BlockOpen

    Given below are two statements for catalytic properties of transition metals :

    Statement I : First row transition metals which act as catalyst utilise their 3d electrons only for formation of bonds between reactant molecules and atoms on the surface of catalyst.

    Statement II : There is increase in the concentration of reactants on the surface of catalyst which strengthens the bonds in reacting molecules.

    In the light of the above statements, choose the correct answer from the option given below :

    1. (1)Both Statement I and Statement II are correct
    2. (2)Both Statement I and Statement II are incorrect
    3. (3)Statement I is correct but Statement II are incorrect
    4. (4)Statement I is incorrect but Statement II are correct
  12. Given below are two statements :

    Statement I : Vapours of the liquid with higher boiling point condense before vapours of the liquid with lower boiling points in fractional distillation.

    Statement II : The vapours rising up in the fractionating column become richer in high boiling component of the mixture.

    In the light of the above statements, choose the correct answer from the option given below :

    1. (1)Both Statement I and Statement II are true
    2. (2)Both Statement I and Statement II are false
    3. (3)Statement I is true but Statement II are false
    4. (4)Statement I is false but Statement II are true
  13. The major product of which of the following reaction is not obtained by rearrangement reaction?
    1. (1)
    2. (2)
    3. (3)
    4. (4)
  14. The total number of aromatic compounds/species from the following is
    1. (1)6
    2. (2)4
    3. (3)3
    4. (4)5
  15. Q15 · MCQ · HydrocarbonsOpen

    n-Butane on monochlorination under photochemical conditions gives an optically active compound “P”. “P” on further chlorination gives dichloro compounds.

    The number of dichloro compounds obtained (ignore stereoisomers) is :

    1. (1)3
    2. (2)4
    3. (3)5
    4. (4)6
  16. Given below are two statements :

    Statement-I : Due to increase in van der Waals forces, the order of boiling points is CHX3CHX2CHX2I\ce{CH3CH2CH2I} >> CHX3CHX2I\ce{CH3CH2I} >> CHX3I\ce{CH3I}.

    Statement-II : As is more symmetric, its melting point is higher than , however its boiling point is lower than

    In the light of the above statements, choose the correct answer from the options given below :

    1. (1)Both Statement-I and Statement-II are true.
    2. (2)Both Statement-I and Statement-II are false.
    3. (3)Statement-I is true but Statement-II is false.
    4. (4)Statement-I is false but Statement-II is true.
  17. Consider the following reaction.
    The major product (P) formed is :
    1. (1)
    2. (2)
    3. (3)
    4. (4)
  18. Q18 · MCQ · AminesOpen
    Which statements are True?
    • (A)In Hoffmann bromamide degradation, 4 moles of NaOH and 2 moles of BrX2\ce{Br2} are consumed per mole of an amide
    • (B)Hoffmann bromamide reaction is not given by alkyl amides.
    • (C)Primary amines can be synthesized by Hoffmann bromamide degradation.
    • (D)Secondary amide on reaction with BrX2\ce{Br2} and NaOH will give secondary amine.
    • (E)The by-products of Hoffmann degradation are NaX2COX3\ce{Na2CO3}, NaBr and HX2O\ce{H2O}.
    Choose the correct answer from the options given below :
    1. (1)A, C and E only
    2. (2)B, C and D only
    3. (3)C and E only
    4. (4)C, D and E only
  19. Q19 · MCQ · BiomoleculesOpen
    The incorrect statement from the following with respect to carbohydrates is :
    1. (1)All monosaccharides are reducing sugars.
    2. (2)The monosaccharide units obtained from hydrolysis of oligosaccharides are always the same.
    3. (3)Starch and cellulose are typical examples of polysaccharides, which are very high molecular weight compounds of more than ten monosaccharide units.
    4. (4)Open chain and cyclic structures co-exist at equilibrium that are responsible for certain properties as in the case of D-(+)-glucose.
  20. Q20 · MCQ · BiomoleculesOpen
    Which of the following amino acid will give violet coloured complex with neutral ferric chloride solution?
    1. (1)Threonine
    2. (2)Serine
    3. (3)Tyrosine
    4. (4)Cysteine
  21. Q21 · Numerical · Coordination CompoundsOpen

    Number of paramagnetic complexes among the following is .

    [MnBrX4]X2−\ce{[MnBr4]^2-}, [NiClX4]X2−\ce{[NiCl4]^2-}, [Ni(CN)X4]X2−\ce{[Ni(CN)4]^2-}, [Ni(CO)X4]\ce{[Ni(CO)4]}, [CoFX6]X3−\ce{[CoF6]^3-}, [Fe(CN)X6]X4−\ce{[Fe(CN)6]^4-}, [Mn(CN)X6]X3−\ce{[Mn(CN)6]^3-}, [Ti(CN)X6]X3−\ce{[Ti(CN)6]^3-}, [Cu(HX2O)X6]X2+\ce{[Cu(H2O)6]^2+}, [Co(CX2OX4)X3]X3−\ce{[Co(C2O4)3]^3-}

  22. ‘x' is the product which is obtained from benzene by reacting it with carbon monoxide and hydrogen chloride in the presence of cuprous chloride. ‘y' is the major product obtained from the benzene by reacting it with ethanoyl chloride in the presence of anhydrous AlClX3\ce{AlCl3}. Product (major) obtained by heating x and y in the presence of alkali is z. Total number of π\pi (pi) electrons in z is .
  23. Q23 · Numerical · Structure of AtomOpen

    Consider two radiations of wavelengths :

     1. λ1=2000\lambda_1 = 2000 Å

     2. λ2=6000\lambda_2 = 6000 Å

    The ratio of the energies of these two radiations (E1E2)\left(\dfrac{E_1}{E_2}\right) is . (Nearest integer)

  24. Q24 · Numerical · ThermodynamicsOpen

    Consider the reaction :

    2 HX2S(g)+3 OX2(g)→2 HX2O(l)+2 SOX2(g)\ce{2H2S(g) + 3O2(g) -> 2H2O($l$) + 2SO2(g)}

    The magnitude of enthalpy change for the reaction in kJ mol−1^{-1} is . (Nearest integer)

    Given : ΔfH⊖\Delta_f H^{\ominus} (HX2S\ce{H2S}) =−20.1= -20.1 kJ mol−1^{-1}

     ΔfH⊖\Delta_f H^{\ominus} (HX2O\ce{H2O}) =−286.0= -286.0 kJ mol−1^{-1}

     ΔfH⊖\Delta_f H^{\ominus} (SOX2\ce{SO2}) =−297.0= -297.0 kJ mol−1^{-1}

  25. Q25 · Numerical · EquilibriumOpen

    Solid carbon, CaO and CaCOX3\ce{CaCO3} are mixed and allowed to attain equilibrium at T K.

    CaCOX3⇌CaO(s)+COX2(g)\ce{CaCO3 <=> CaO(s) + CO2(g)}   Kp1=0.08_1 = 0.08 atm

    C(s)+COX2(g)⇌2 CO(g)\ce{C(s) + CO2(g) <=> 2CO(g)}   Kp2=2_2 = 2 atm

    The partial pressure of CO is ×10−1\times 10^{-1} atm.

Maths

  1. Consider the relation RR on the set {−2,−1,0,1,2}\{-2, -1, 0, 1, 2\} defined by (a,b)∈R(a, b) \in R if and only if 1+ab>01 + ab > 0. Then among the statements:

    I. The number of elements in RR is 17

    II. RR is an equivalence relation

    1. (1)Only I is true
    2. (2)Only II is true
    3. (3)Both I and II are true
    4. (4)Neither I nor II is true
  2. The number of values of z∈Cz \in \mathbb{C}, satisfying the equations ∣z−(4+8i)∣=10\lvert z - (4 + 8i)\rvert = \sqrt{10} and ∣z−(3+5i)∣+∣z−(5+11i)∣=45\lvert z - (3 + 5i)\rvert + \lvert z - (5 + 11i)\rvert = 4\sqrt5, is:
    1. (1)0
    2. (2)2
    3. (3)1
    4. (4)4
  3. If the system of linear equations:
    x+y+z=6,x+2y+5z=10,2x+3y+λz=μ\begin{align*} x + y + z &= 6,\\ x + 2y + 5z &= 10,\\ 2x + 3y + \lambda z &= \mu \end{align*}
    has infinitely many solutions, then the value of λ+μ\lambda + \mu equals.
    1. (1)12
    2. (2)16
    3. (3)22
    4. (4)28
  4. Let A=[α12230045]andB=[1000−5α004α−2α]+adj⁡(A).A = \begin{bmatrix} \alpha & 1 & 2\\ 2 & 3 & 0\\ 0 & 4 & 5\end{bmatrix} \quad\text{and}\quad B = \begin{bmatrix} 1 & 0 & 0\\ 0 & -5\alpha & 0\\ 0 & 4\alpha & -2\alpha\end{bmatrix} + \operatorname{adj}(A). If det⁡(B)=66\det(B) = 66, then det⁡(adj⁡(A))\det(\operatorname{adj}(A)) equals:
    1. (1)289
    2. (2)361
    3. (3)441
    4. (4)529
  5. Let α=3+4+8+9+13+14+…\alpha = 3 + 4 + 8 + 9 + 13 + 14 + \ldots upto 40 terms. If (tan⁡β)α1020(\tan\beta)^{\frac{\alpha}{1020}} is a root of the equation x2+x−2=0x^2 + x - 2 = 0, β∈(0,π2)\beta \in \left(0, \dfrac{\pi}{2}\right), then sin⁡2β+3cos⁡2β\sin^2\beta + 3\cos^2\beta is equal to:
    1. (1)2
    2. (2)74\dfrac74
    3. (3)52\dfrac52
    4. (4)32\dfrac32
  6. Q6 · MCQ · ProbabilityOpen
    A candidate has to go to the examination centre to appear in an examination. The candidate uses only one means of transportation for the entire distance out of bus, scooter and car. The probabilities of the candidate going by bus, scooter and car, respectively, are 25\dfrac25, 15\dfrac15 and 25\dfrac25. The probabilities that the candidate reaches late at the examination centre are 15\dfrac15, 13\dfrac13 and 14\dfrac14 if the candidate uses bus, scooter and car, respectively. Given that the candidate reached late at the examination centre, the probability that the candidate travelled by bus is:
    1. (1)1137\dfrac{11}{37}
    2. (2)1237\dfrac{12}{37}
    3. (3)1337\dfrac{13}{37}
    4. (4)1437\dfrac{14}{37}
  7. Q7 · MCQ · StatisticsOpen
    A set of four observations has mean 1 and variance 13. Another set of six observations has mean 2 and variance 1. Then, the variance of all these 10 observations is equal to:
    1. (1)5.96
    2. (2)6.14
    3. (3)6.04
    4. (4)6.24
  8. If 26(233(12C2)+255(12C4)+277(12C6)+…+21313(12C12))=313−α,26\left(\frac{2^3}{3}\left({}^{12}C_2\right) + \frac{2^5}{5}\left({}^{12}C_4\right) + \frac{2^7}{7}\left({}^{12}C_6\right) + \ldots + \frac{2^{13}}{13}\left({}^{12}C_{12}\right)\right) = 3^{13} - \alpha, then α\alpha is equal to:
    1. (1)45
    2. (2)48
    3. (3)51
    4. (4)54
    We corrected a printing error in the original paper

    Source printed the first term as “233(13C2)\frac{2^3}{3}({}^{13}C_2)”; corrected to the intended 12C2{}^{12}C_2 (all other terms are 12Ck{}^{12}C_k; with 13C2{}^{13}C_2 the value is α=−781\alpha = -781, no option).

  9. A person has three different bags and four different books. The number of ways, in which he can put these books in the bags so that no bag is empty, is
    1. (1)18
    2. (2)36
    3. (3)39
    4. (4)72
  10. Q10 · MCQ · Straight LinesOpen
    If a straight line drawn through the point of intersection of the lines 4x+3y−1=04x + 3y - 1 = 0 and 3x+4y−1=03x + 4y - 1 = 0, meets the co-ordinate axes at the points PP and QQ, then the locus of the mid point of PQPQ is:
    1. (1)x+y−7=0x + y - 7 = 0
    2. (2)x+y−14xy=0x + y - 14xy = 0
    3. (3)2x+y+14xy=02x + y + 14xy = 0
    4. (4)x+2y−14xy=0x + 2y - 14xy = 0
    We corrected a printing error in the original paper

    Source printed “a straight line … meet the co-ordinate axes” (subject-verb agreement).

  11. Q11 · MCQ · Conic SectionsOpen
    Let OO be the vertex of the parabola y2=4xy^2 = 4x and its chords OPOP and OQOQ are perpendicular to each other. If the locus of the mid-point of the line segment PQPQ is a conic CC, then the length of its latus rectum is:
    1. (1)1
    2. (2)2
    3. (3)4
    4. (4)8
  12. Let α=3sin⁡−1(611)\alpha = 3\sin^{-1}\left(\dfrac{6}{11}\right) and β=3cos⁡−1(49)\beta = 3\cos^{-1}\left(\dfrac49\right), where inverse trigonometric functions take only the principal values.

    Given below are two statements:

    Statement I: cos⁡(α+β)>0\cos(\alpha + \beta) > 0

    Statement II: cos⁡(α)<0\cos(\alpha) < 0

    In the light of the above statements, choose the correct answer from the options given below:

    1. (1)Both Statement I and Statement II are true
    2. (2)Both Statement I and Statement II are false
    3. (3)Statement I is true but Statement II is false
    4. (4)Statement I is false but Statement II is true
  13. For the function f(x)=esin⁡∣x∣−∣x∣f(x) = e^{\sin\lvert x\rvert} - \lvert x\rvert, x∈Rx \in \mathbb{R}, consider the following statements:

    Statement I: ff is differentiable for all x∈Rx \in \mathbb{R}.

    Statement II: ff is increasing in (−π,−π2)\left(-\pi, -\dfrac{\pi}{2}\right).

    In the light of the above statements, choose the correct answer from the options given below:

    1. (1)Both Statement I and Statement II are true
    2. (2)Both Statement I and Statement II are false
    3. (3)Statement I is true but Statement II is false
    4. (4)Statement I is false but Statement II is true
    We corrected a printing error in the original paper

    Answer corrected; the source key is (4) — for f(x)=esin⁡∣x∣−∣x∣f(x) = e^{\sin\lvert x\rvert} - \lvert x\rvert both one-sided derivatives at x=0x = 0 are 00 and ff is smooth elsewhere, so Statement I is true, and f′(x)=1−cos⁡x e−sin⁡x>0f'(x) = 1 - \cos x\, e^{-\sin x} > 0 on (−π,−π/2)(-\pi, -\pi/2), so Statement II is true; the source's solution works with e∣sin⁡x∣e^{\lvert\sin x\rvert} instead.

  14. Q14 · MCQ · VectorsOpen
    Let a⃗=4i^−j^+3k^\vec a = 4\hat i - \hat j + 3\hat k, b⃗=10i^+2j^−k^\vec b = 10\hat i + 2\hat j - \hat k and a vector c⃗\vec c be such that 2(a⃗×b⃗)+3(b⃗×c⃗)=0⃗2(\vec a\times\vec b) + 3(\vec b\times\vec c) = \vec 0. If a⃗⋅c⃗=15\vec a\cdot\vec c = 15, then c⃗⋅(i^+j^−3k^)\vec c\cdot(\hat i + \hat j - 3\hat k) is equal to:
    1. (1)−6-6
    2. (2)−5-5
    3. (3)−4-4
    4. (4)−3-3
  15. Q15 · MCQ · 3D GeometryOpen
    Let the foot of perpendicular from the point (λ,2,3)(\lambda, 2, 3) on the line x−41=y−92=z−51\dfrac{x-4}{1} = \dfrac{y-9}{2} = \dfrac{z-5}{1} be the point (1,μ,2)(1, \mu, 2). Then the distance between the lines x−12=y−23=z+46\dfrac{x-1}{2} = \dfrac{y-2}{3} = \dfrac{z+4}{6} and x−λ2=y−μ3=z+56\dfrac{x-\lambda}{2} = \dfrac{y-\mu}{3} = \dfrac{z+5}{6} is equal to
    1. (1)127\dfrac{12}{7}
    2. (2)1457\dfrac{\sqrt{145}}{7}
    3. (3)1467\dfrac{\sqrt{146}}{7}
    4. (4)1437\dfrac{\sqrt{143}}{7}
  16. The value of the integral ∫02x(x2+x+1)(x+1)(x4+x2+1) dx\int_0^2 \frac{\sqrt{x(x^2 + x + 1)}}{\left(\sqrt{x+1}\right)\left(\sqrt{x^4 + x^2 + 1}\right)}\,dx is equal to:
    1. (1)13log⁡e(3−22)\dfrac13\log_e\left(3 - 2\sqrt2\right)
    2. (2)23log⁡e(4+2)\dfrac23\log_e\left(4 + \sqrt2\right)
    3. (3)23log⁡e(3+22)\dfrac23\log_e\left(3 + 2\sqrt2\right)
    4. (4)13log⁡e(1+62)\dfrac13\log_e\left(1 + 6\sqrt2\right)
  17. Let y=y(x)y = y(x) be the solution of the differential equation x1−x2 dy+(y1−x2−xcos⁡−1x)dx=0,x\sqrt{1-x^2}\,dy + \left(y\sqrt{1-x^2} - x\cos^{-1}x\right)dx = 0, x∈(0,1)x \in (0, 1), lim⁡x→1−y(x)=1\displaystyle\lim_{x\to1^-} y(x) = 1. Then y(12)y\left(\dfrac12\right) equals:
    1. (1)3−π33 - \dfrac{\pi}{\sqrt3}
    2. (2)4−3 π4 - \sqrt3\,\pi
    3. (3)4−2π34 - \dfrac{2\pi}{\sqrt3}
    4. (4)3−π233 - \dfrac{\pi}{2\sqrt3}
  18. Let f:(1,∞)→Rf : (1, \infty) \to \mathbb{R} be function defined as f(x)=x−1x+1f(x) = \dfrac{x-1}{x+1}. Let fi+1(x)=f(fi(x))f^{i+1}(x) = f\left(f^{i}(x)\right), i=1,2,…,25i = 1, 2, \ldots, 25, where f1(x)=f(x)f^{1}(x) = f(x). If g(x)+f26(x)=0g(x) + f^{26}(x) = 0, x∈(1,∞)x \in (1, \infty), then the area of the region bounded by the curves y=g(x)y = g(x), 2y=2x−32y = 2x - 3, y=0y = 0 and x=4x = 4 is:
    1. (1)18+log⁡e2\dfrac18 + \log_e 2
    2. (2)14+log⁡e2\dfrac14 + \log_e 2
    3. (3)56+3log⁡e2\dfrac56 + 3\log_e 2
    4. (4)56+log⁡e2\dfrac56 + \log_e 2
    We corrected a printing error in the original paper

    Source printed “where f1(x)=(x)f^{1}(x) = (x)” (the ff is missing).

  19. Let f(x)={13,x≤π2b(1−sin⁡x)(π−2x)2,x>π2,f(x) = \begin{cases} \dfrac13, & x \le \dfrac{\pi}{2}\\[2ex] \dfrac{b(1 - \sin x)}{(\pi - 2x)^2}, & x > \dfrac{\pi}{2}\end{cases}, If ff is continuous at x=π/2x = \pi/2, then the value of ∫03b−6∣x2+2x−3∣dx\displaystyle\int_0^{3b-6}\left\lvert x^2 + 2x - 3\right\rvert dx is:
    1. (1)5
    2. (2)2
    3. (3)3
    4. (4)4
  20. Q20 · MCQ · Conic SectionsOpen
    Let x2f(a2+7a+3)+y2f(3a+15)=1\dfrac{x^2}{f(a^2 + 7a + 3)} + \dfrac{y^2}{f(3a + 15)} = 1 represent an ellipse with major axis along yy-axis, where ff is a strictly decreasing positive function on R\mathbb{R}. If the set of all possible values of aa is R−[α,β]\mathbb{R} - [\alpha, \beta], then α2+β2\alpha^2 + \beta^2 is equal to:
    1. (1)28
    2. (2)40
    3. (3)61
    4. (4)24
  21. Q21 · Numerical · Quadratic EquationsOpen
    The sum of squares of all real solutions of the equation log⁡(x+1)(2x2+5x+3)=4−log⁡(2x+3)(x2+2x+1)\log_{(x+1)}(2x^2 + 5x + 3) = 4 - \log_{(2x+3)}(x^2 + 2x + 1) is equal to .
    We corrected a printing error in the original paper

    Source printed “all real solution” (singular).

  22. Q22 · Numerical · Definite IntegrationOpen
    If ∫π/6π/4(cot⁡(x−π3)cot⁡(x+π3)+1)dx=αlog⁡e(3−1),\int_{\pi/6}^{\pi/4}\left(\cot\left(x - \frac{\pi}{3}\right)\cot\left(x + \frac{\pi}{3}\right) + 1\right)dx = \alpha\log_e\left(\sqrt3 - 1\right), then 9α29\alpha^2 is equal to .
  23. Q23 · Numerical · 3D GeometryOpen
    Let a line L1L_1 pass through the origin and be perpendicular to the lines
    L2:r⃗=(3+t)i^+(2t−1)j^+(2t+4)k^andL3:r⃗=(3+2s)i^+(3+2s)j^+(2+s)k^,\begin{align*} L_2 &: \vec r = (3 + t)\hat i + (2t - 1)\hat j + (2t + 4)\hat k \quad\text{and}\\ L_3 &: \vec r = (3 + 2s)\hat i + (3 + 2s)\hat j + (2 + s)\hat k, \end{align*}
    t,s∈Rt, s \in \mathbb{R}. If (a,b,c)(a, b, c), a∈Za \in \mathbb{Z}, is the point on L3L_3 at a distance of 17\sqrt{17} from the point of intersection of L1L_1 and L2L_2, then (a+b+c)2(a + b + c)^2 is equal to .
  24. Q24 · Numerical · CirclesOpen
    Consider the circle C:x2+y2−6x−8y−11=0C : x^2 + y^2 - 6x - 8y - 11 = 0. Let a variable chord ABAB of the circle CC subtend a right angle at the origin. If the locus of the foot of the perpendicular drawn from the origin on the chord ABAB is the circle x2+y2−αx−βy−γ=0x^2 + y^2 - \alpha x - \beta y - \gamma = 0, then α+β+2γ\alpha + \beta + 2\gamma is equal to .
  25. Let ff be a polynomial function such that log⁡2(f(x))=(log⁡2(2+23+29+…∞))⋅log⁡3(1+f(x)f(1x)),\log_2(f(x)) = \left(\log_2\left(2 + \frac23 + \frac29 + \ldots\infty\right)\right)\cdot\log_3\left(1 + \frac{f(x)}{f\left(\frac1x\right)}\right), x>0x > 0 and f(6)=37f(6) = 37. Then ∑n=110f(n)\displaystyle\sum_{n=1}^{10} f(n) is equal to .