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MathsJEE Main 2 Apr 2026, Shift 1·Q3·MCQ·Easy–moderate

Matrices & Determinants · Consistency of linear systems

Let α,β∈R\alpha, \beta \in \mathbb{R} be such that the system of linear equations
x+2y+z=52x+y+αz=58x+4y+βz=18\begin{align*} x + 2y + z &= 5\\ 2x + y + \alpha z &= 5\\ 8x + 4y + \beta z &= 18 \end{align*}
has no solution. Then βα\dfrac{\beta}{\alpha} is equal to:
  1. (1)−4-4
  2. (2)4
  3. (3)8
  4. (4)−8-8

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