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Matrices & Determinants

33 JEE Main questions · Maths

  1. MathsJEE Main 21 Jan 2026, Shift 1·Q24·Numerical·Moderate
    Open

    Adjoint and determinant properties

    For some α,β∈R\alpha, \beta \in \mathbb{R}, let A=[α212]andB=[111β]A = \begin{bmatrix} \alpha & 2\\ 1 & 2\end{bmatrix} \quad\text{and}\quad B = \begin{bmatrix} 1 & 1\\ 1 & \beta\end{bmatrix} be such that A2−4A+2I=B2−3B+I=OA^2 - 4A + 2I = B^2 - 3B + I = O. Then (det⁡(adj⁡(A3−B3)))2(\det(\operatorname{adj}(A^3 - B^3)))^2 is equal to .
  2. MathsJEE Main 21 Jan 2026, Shift 2·Q14·MCQ·Moderate
    Open

    Powers of a matrix

    For the matrices A=[3−41−1]andB=[−2949−1318],A = \begin{bmatrix} 3 & -4\\ 1 & -1\end{bmatrix} \quad\text{and}\quad B = \begin{bmatrix} -29 & 49\\ -13 & 18\end{bmatrix}, if (A15+B)[xy]=[00](A^{15} + B)\begin{bmatrix} x\\ y\end{bmatrix} = \begin{bmatrix} 0\\ 0\end{bmatrix}, then among the following which one is true?
    1. (1)x=5x = 5, y=7y = 7
    2. (2)x=18x = 18, y=11y = 11
    3. (3)x=11x = 11, y=2y = 2
    4. (4)x=16x = 16, y=3y = 3
  3. MathsJEE Main 21 Jan 2026, Shift 2·Q18·MCQ·Easy–moderate
    Open

    Consistency of linear equations

    If the system of equations
    3x+y+4z=32x+αy−z=−3x+2y+z=4\begin{align*} 3x + y + 4z &= 3\\ 2x + \alpha y - z &= -3\\ x + 2y + z &= 4 \end{align*}
    has no solution, then the value of α\alpha is equal to:
    1. (1)19
    2. (2)4
    3. (3)13
    4. (4)23
    We corrected a printing error in the original paper

    Source printed the third equation as “X+2y+z=4X + 2y + z = 4” (capital XX for xx).

  4. MathsJEE Main 22 Jan 2026, Shift 1·Q13·MCQ·Easy–moderate
    Open

    Determinant of matrix polynomial

    If A=[2335]A = \begin{bmatrix} 2 & 3\\ 3 & 5\end{bmatrix}, then the determinant of the matrix (A2025−3A2024+A2023)(A^{2025} - 3A^{2024} + A^{2023}) is
    1. (1)28
    2. (2)12
    3. (3)24
    4. (4)16
  5. MathsJEE Main 22 Jan 2026, Shift 1·Q22·Numerical·Tough
    Open

    Adjoint and determinant properties

    Let AA be a 3×33 \times 3 matrix such that A+AT=OA + A^T = O. If A[1−10]=[332],A2[1−10]=[−319−24]A\begin{bmatrix} 1\\ -1\\ 0\end{bmatrix} = \begin{bmatrix} 3\\ 3\\ 2\end{bmatrix},\quad A^2\begin{bmatrix} 1\\ -1\\ 0\end{bmatrix} = \begin{bmatrix} -3\\ 19\\ -24\end{bmatrix} and det⁡(adj⁡(2adj⁡(A+I)))=(2)α⋅(3)β⋅(11)γ\det(\operatorname{adj}(2\operatorname{adj}(A + I))) = (2)^{\alpha}\cdot(3)^{\beta}\cdot(11)^{\gamma}, α,β,γ\alpha, \beta, \gamma are non-negative integers, then α+β+γ\alpha + \beta + \gamma is equal to .
  6. MathsJEE Main 22 Jan 2026, Shift 2·Q1·MCQ·Moderate
    Open

    Consistency of linear equations

    Let nn be the number obtained on rolling a fair die. If the probability that the system
    x−ny+z=6x+(n−2)y+(n+1)z=8(n−1)y+z=1\begin{align*} x - ny + z &= 6\\ x + (n-2)y + (n+1)z &= 8\\ (n-1)y + z &= 1 \end{align*}
    Has a unique solution is k6\dfrac{k}{6}, then the sum of kk and all possible values of nn is:
    1. (1)21
    2. (2)24
    3. (3)20
    4. (4)22
  7. MathsJEE Main 22 Jan 2026, Shift 2·Q9·MCQ·Moderate
    Open

    Adjoint and inverse of matrix

    If X=[xyz]X = \begin{bmatrix} x\\ y\\ z\end{bmatrix} is a solution of the system of equations AX=BAX = B, where adj⁡A=[422−5051−23]andB=[402],\operatorname{adj} A = \begin{bmatrix} 4 & 2 & 2\\ -5 & 0 & 5\\ 1 & -2 & 3\end{bmatrix} \quad\text{and}\quad B = \begin{bmatrix} 4\\ 0\\ 2\end{bmatrix}, then ∣x+y+z∣\lvert x + y + z\rvert is equal to:
    1. (1)3
    2. (2)32\dfrac32
    3. (3)1
    4. (4)2
  8. MathsJEE Main 23 Jan 2026, Shift 1·Q11·MCQ·Moderate
    Open

    Evaluation of determinants

    Among the statements:

    I: If ∣1cos⁡αcos⁡βcos⁡α1cos⁡γcos⁡βcos⁡γ1∣=∣0cos⁡αcos⁡βcos⁡α0cos⁡γcos⁡βcos⁡γ0∣\begin{vmatrix} 1 & \cos\alpha & \cos\beta\\ \cos\alpha & 1 & \cos\gamma\\ \cos\beta & \cos\gamma & 1\end{vmatrix} = \begin{vmatrix} 0 & \cos\alpha & \cos\beta\\ \cos\alpha & 0 & \cos\gamma\\ \cos\beta & \cos\gamma & 0\end{vmatrix}, then cos⁡2α+cos⁡2β+cos⁡2γ=32\cos^2\alpha + \cos^2\beta + \cos^2\gamma = \dfrac32, and

    II: If ∣x2+xx+1x−22x2+3x−13x3x−3x2+2x+32x−12x−1∣=px+q\begin{vmatrix} x^2 + x & x + 1 & x - 2\\ 2x^2 + 3x - 1 & 3x & 3x - 3\\ x^2 + 2x + 3 & 2x - 1 & 2x - 1\end{vmatrix} = px + q, then p2=196q2p^2 = 196q^2,

    1. (1)both are false
    2. (2)only II is true
    3. (3)both are true
    4. (4)only I is true
  9. MathsJEE Main 23 Jan 2026, Shift 1·Q21·Numerical·Moderate
    Open

    Adjoint and determinant properties

    Let ∣A∣=6\lvert A\rvert = 6, where AA is a 3×33\times3 matrix. If ∣adj⁡(3adj⁡(A2⋅adj⁡(2A)))∣=2m⋅3n\lvert\operatorname{adj}(3\operatorname{adj}(A^2\cdot\operatorname{adj}(2A)))\rvert = 2^m\cdot3^n, m,n∈Nm, n \in \mathbb{N}, then m+nm + n is equal to .
  10. MathsJEE Main 23 Jan 2026, Shift 2·Q6·MCQ·Easy–moderate
    Open

    Consistency of linear equations

    The system of linear equations
    x+y+z=62x+5y+az=36x+2y+3z=b\begin{align*} x + y + z &= 6\\ 2x + 5y + az &= 36\\ x + 2y + 3z &= b \end{align*}
    has
    1. (1)unique solution for a=8a = 8 and b=16b = 16
    2. (2)infinitely many solutions for a=8a = 8 and b=14b = 14
    3. (3)infinitely many solutions for a=8a = 8 and b=16b = 16
    4. (4)unique solution for a=8a = 8 and b=14b = 14
  11. MathsJEE Main 23 Jan 2026, Shift 2·Q24·Numerical·Moderate
    Open

    Orthogonal and skew-symmetric matrices

    Let A=[02−3−2013−10]A = \begin{bmatrix} 0 & 2 & -3\\ -2 & 0 & 1\\ 3 & -1 & 0\end{bmatrix} and BB be a matrix such that B(I−A)=I+AB(I - A) = I + A. Then the sum of the diagonal elements of BTBB^{T}B is equal to .
  12. MathsJEE Main 24 Jan 2026, Shift 1·Q25·Numerical·Moderate
    Open

    Trace of transpose product

    The number of 3×23 \times 2 matrices AA, which can be formed using the elements of the set {−2,−1,0,1,2}\{-2, -1, 0,\allowbreak 1, 2\} such that the sum of all the diagonal elements of ATAA^{T}A is 5, is .
  13. MathsJEE Main 24 Jan 2026, Shift 2·Q1·MCQ·Moderate
    Open

    Adjoint and determinant properties

    Let f(x)=∫7x10+9x8(1+x2+2x9)2 dxf(x) = \displaystyle\int\dfrac{7x^{10} + 9x^8}{(1 + x^2 + 2x^9)^2}\,dx, x>0x > 0, lim⁡x→0f(x)=0\displaystyle\lim_{x\to0} f(x) = 0 and f(1)=14f(1) = \dfrac14. If A=[00114f′(1)1α241]A = \begin{bmatrix} 0 & 0 & 1\\[2pt] \dfrac14 & f'(1) & 1\\[2pt] \alpha^2 & 4 & 1\end{bmatrix} and B=adj⁡(adj⁡A)B = \operatorname{adj}(\operatorname{adj} A) be such that ∣B∣=81\lvert B\rvert = 81, then α2\alpha^2 is equal to
    1. (1)2
    2. (2)3
    3. (3)1
    4. (4)4
  14. MathsJEE Main 24 Jan 2026, Shift 2·Q8·MCQ·Moderate
    Open

    Determinant and adjoint properties

    Let P=[pij]P = [p_{ij}] and Q=[qij]Q = [q_{ij}] be two square matrices of order 3 such that qij=2(i+j−1)pijq_{ij} = 2^{(i + j - 1)}p_{ij} and det⁡(Q)=210\det(Q) = 2^{10}. Then the value of det⁡(adj⁡(adj⁡P))\det(\operatorname{adj}(\operatorname{adj} P)) is:
    1. (1)32
    2. (2)16
    3. (3)81
    4. (4)124
  15. MathsJEE Main 28 Jan 2026, Shift 1·Q16·MCQ·Moderate
    Open

    Inverse of a matrix

    Let AA, BB and CC be three 2×22\times2 matrices with real entries such that B=(I+A)−1B = (I + A)^{-1} and A+C=IA + C = I. If BC=[1−5−12]andCB[x1x2]=[12−6],BC = \begin{bmatrix} 1 & -5\\ -1 & 2\end{bmatrix} \quad\text{and}\quad CB\begin{bmatrix} x_1\\ x_2\end{bmatrix} = \begin{bmatrix} 12\\ -6\end{bmatrix}, then x1+x2x_1 + x_2 is
    1. (1)2
    2. (2)0
    3. (3)−2-2
    4. (4)4
  16. MathsJEE Main 28 Jan 2026, Shift 2·Q25·Numerical·Moderate
    Open

    Powers of a nilpotent matrix

    Let A=[3−41−1]A = \begin{bmatrix} 3 & -4\\ 1 & -1\end{bmatrix} and BB be two matrices such that A100=100B+IA^{100} = 100B + I. Then the sum of all the elements of B100B^{100} is .
  17. MathsJEE Main 2 Apr 2026, Shift 1·Q3·MCQ·Easy–moderate
    Open

    Consistency of linear systems

    Let α,β∈R\alpha, \beta \in \mathbb{R} be such that the system of linear equations
    x+2y+z=52x+y+αz=58x+4y+βz=18\begin{align*} x + 2y + z &= 5\\ 2x + y + \alpha z &= 5\\ 8x + 4y + \beta z &= 18 \end{align*}
    has no solution. Then βα\dfrac{\beta}{\alpha} is equal to:
    1. (1)−4-4
    2. (2)4
    3. (3)8
    4. (4)−8-8
  18. MathsJEE Main 2 Apr 2026, Shift 1·Q4·MCQ·Moderate
    Open

    Adjoint and determinant properties

    Let A=[121α]A = \begin{bmatrix} 1 & 2\\ 1 & \alpha\end{bmatrix} and B=[33β2]B = \begin{bmatrix} 3 & 3\\ \beta & 2\end{bmatrix}. If A2−4A+I=OA^2 - 4A + I = O and B2−5B−6I=OB^2 - 5B - 6I = O, then among the two statements:
    • (S1):[(B−A)(B+A)]T=[1315710][(B - A)(B + A)]^{T} = \begin{bmatrix} 13 & 15\\ 7 & 10\end{bmatrix}
    and
    • (S2):det⁡(adj⁡(A+B))=−5\det(\operatorname{adj}(A + B)) = -5,
    1. (1)only (S1) is correct
    2. (2)only (S2) is correct
    3. (3)both (S1) and (S2) are correct
    4. (4)both (S1) and (S2) are wrong
  19. MathsJEE Main 2 Apr 2026, Shift 2·Q3·MCQ·Moderate
    Open

    Consistency of linear equations

    If the system of equations
    x+5y+6z=4,2x+3y+4z=7,x+6y+az=b\begin{align*} x + 5y + 6z &= 4,\\ 2x + 3y + 4z &= 7,\\ x + 6y + az &= b \end{align*}
    has infinitely many solutions, then the point (a,b)(a, b) lies on the line
    1. (1)y−x=3y - x = 3
    2. (2)x−y=3x - y = 3
    3. (3)x+y=11x + y = 11
    4. (4)x+y=12x + y = 12
  20. MathsJEE Main 2 Apr 2026, Shift 2·Q22·Numerical·Easy–moderate
    Open

    Inverse of a matrix

    Consider the matrices A=[2−24−2]andB=[3913].A = \begin{bmatrix} 2 & -2\\ 4 & -2\end{bmatrix} \quad\text{and}\quad B = \begin{bmatrix} 3 & 9\\ 1 & 3\end{bmatrix}. If matrices PP and QQ are such that PA=BPA = B and AQ=BAQ = B, then the absolute value of the sum of the diagonal elements of 2(P+Q)2(P + Q) is .
    We corrected a printing error in the original paper

    Source printed “B” directly followed by the matrix, without the “=” sign.

  21. MathsJEE Main 4 Apr 2026, Shift 1·Q5·MCQ·Moderate
    Open

    Matrix equation with integer entries

    Let S={A=[abcd]:a,b,c,d∈{0,1,2,3,4} and A2−4A+3I=0}S = \left\{A = \begin{bmatrix} a & b\\ c & d\end{bmatrix} : a, b, c, d \in \{0, 1, 2, 3, 4\} \text{ and } A^2 - 4A + 3I = 0\right\} be a set of 2×22 \times 2 matrices. Then the number of matrices in SS, for which the sum of the diagonal elements is equal to 4, is:
    1. (1)20
    2. (2)17
    3. (3)21
    4. (4)19
  22. MathsJEE Main 4 Apr 2026, Shift 1·Q6·MCQ·Moderate
    Open

    Adjoint and inverse properties

    Let A=[112−201135].A = \begin{bmatrix} 1 & 1 & 2\\ -2 & 0 & 1\\ 1 & 3 & 5\end{bmatrix}. Then the sum of all elements of the matrix adj⁡(adj⁡(2(adj⁡A)−1))\operatorname{adj}(\operatorname{adj}(2(\operatorname{adj}A)^{-1})) is equal to:
    1. (1)3
    2. (2)4
    3. (3)−4-4
    4. (4)−3-3
  23. MathsJEE Main 4 Apr 2026, Shift 2·Q3·MCQ·Easy–moderate
    Open

    System of linear equations

    If the system of equations: x+y+z=5x+2y+3z=9x+3y+λz=μ\begin{aligned} x + y + z &= 5\\ x + 2y + 3z &= 9\\ x + 3y + \lambda z &= \mu\end{aligned} has infinitely many solutions, then the value of λ+μ\lambda + \mu is:
    1. (1)16
    2. (2)18
    3. (3)19
    4. (4)21
  24. MathsJEE Main 4 Apr 2026, Shift 2·Q6·MCQ·Moderate
    Open

    Characteristic equation of a matrix

    Let A=[1274−2838−7]A = \begin{bmatrix} 1 & 2 & 7\\ 4 & -2 & 8\\ 3 & 8 & -7\end{bmatrix} and det⁡(A−αI)=0\det(A - \alpha I) = 0, where α\alpha is a real number. If the largest possible value of α\alpha is pp, then the circle (x−p)2+(y−2p)2=320(x-p)^2 + (y-2p)^2 = 320, intersects the co-ordinate axes at
    1. (1)1 point
    2. (2)2 points
    3. (3)3 points
    4. (4)4 points
  25. MathsJEE Main 5 Apr 2026, Shift 1·Q3·MCQ·Moderate
    Open

    Determinant of adjoint

    Let AA be a 3×33 \times 3 matrix such that AT[101]=[522],AT[001]=[311],A[101]=[344]andA[001]=[131]A^{T}\begin{bmatrix} 1\\ 0\\ 1\end{bmatrix} = \begin{bmatrix} 5\\ 2\\ 2\end{bmatrix},\quad A^{T}\begin{bmatrix} 0\\ 0\\ 1\end{bmatrix} = \begin{bmatrix} 3\\ 1\\ 1\end{bmatrix},\quad A\begin{bmatrix} 1\\ 0\\ 1\end{bmatrix} = \begin{bmatrix} 3\\ 4\\ 4\end{bmatrix}\quad\text{and}\quad A\begin{bmatrix} 0\\ 0\\ 1\end{bmatrix} = \begin{bmatrix} 1\\ 3\\ 1\end{bmatrix} If det⁡(A)=1\det(A) = 1, then det⁡(adj⁡(A2+A))\det(\operatorname{adj}(A^2 + A)) is equal to:
    1. (1)16
    2. (2)25
    3. (3)49
    4. (4)64
  26. MathsJEE Main 5 Apr 2026, Shift 1·Q4·MCQ·Moderate
    Open

    Homogeneous system infinitely many solutions

    Consider the system of linear equations in x,y,zx, y, z: x+2y+tz=0,6x+y+5tz=0,3x+t2y+f(t)z=0,\begin{aligned} &x + 2y + tz = 0,\\ &6x + y + 5tz = 0,\\ &3x + t^2y + f(t)z = 0, \end{aligned} Where f:R→Rf : \mathbb{R} \to \mathbb{R} is a differentiable function. If this system has infinitely many solutions for all t∈Rt \in \mathbb{R}, then ff
    1. (1)is a constant function
    2. (2)is strictly increasing on R\mathbb{R}
    3. (3)is strictly decreasing on R\mathbb{R}
    4. (4)has two critical points
  27. MathsJEE Main 5 Apr 2026, Shift 2·Q3·MCQ·Moderate
    Open

    Determinant with summation of terms

    If f:N→Zf : \mathbb{N} \to \mathbb{Z} is defined by f(n)=∣n−1−5−2n23(2k+1)2k+1−3n33k(2k+1)3k(k+2)+1∣, k∈N, andf(n) = \begin{vmatrix} n & -1 & -5\\ -2n^2 & 3(2k+1) & 2k+1\\ -3n^3 & 3k(2k+1) & 3k(k+2)+1 \end{vmatrix},\ k \in \mathbb{N}, \text{ and} ∑n=1kf(n)=98\displaystyle\sum_{n=1}^{k} f(n) = 98, then kk is equal to:
    1. (1)3
    2. (2)4
    3. (3)5
    4. (4)6
  28. MathsJEE Main 5 Apr 2026, Shift 2·Q4·MCQ·Easy–moderate
    Open

    Matrix from images of basis vectors

    Let MM be a 3×33 \times 3 matrix such that M(100)=(123),M(010)=(012)andM(001)=(−111).M\begin{pmatrix}1\\0\\0\end{pmatrix} = \begin{pmatrix}1\\2\\3\end{pmatrix},\quad M\begin{pmatrix}0\\1\\0\end{pmatrix} = \begin{pmatrix}0\\1\\2\end{pmatrix} \quad\text{and}\quad M\begin{pmatrix}0\\0\\1\end{pmatrix} = \begin{pmatrix}-1\\1\\1\end{pmatrix}. If M(xyz)=(1711)M\begin{pmatrix}x\\y\\z\end{pmatrix} = \begin{pmatrix}1\\7\\11\end{pmatrix}, then x+y+zx + y + z equals:
    1. (1)4
    2. (2)5
    3. (3)7
    4. (4)11
    We corrected a printing error in the original paper

    Answer corrected; the source key is (3) — the columns of MM are (1,2,3)(1,2,3), (0,1,2)(0,1,2), (−1,1,1)(-1,1,1), so x−z=1x - z = 1, 2x+y+z=72x + y + z = 7, 3x+2y+z=113x + 2y + z = 11 give (x,y,z)=(2,2,1)(x,y,z) = (2,2,1) and x+y+z=5x + y + z = 5, option (2).

  29. MathsJEE Main 6 Apr 2026, Shift 1·Q21·Numerical·Moderate
    Open

    Properties of adjoint matrix

    Let A=[−11−1101001]A = \begin{bmatrix} -1 & 1 & -1\\ 1 & 0 & 1\\ 0 & 0 & 1\end{bmatrix} satisfy A2+α(adj⁡(adj⁡(A)))+β(adj⁡(A)(adj⁡(adj⁡(A))))=[2−22−20−100−1]A^2 + \alpha(\operatorname{adj}(\operatorname{adj}(A))) + \beta(\operatorname{adj}(A)(\operatorname{adj}(\operatorname{adj}(A)))) = \begin{bmatrix} 2 & -2 & 2\\ -2 & 0 & -1\\ 0 & 0 & -1\end{bmatrix} for Some α,β∈R\alpha, \beta \in \mathbb{R}. Then (α−β)2(\alpha - \beta)^2 is equal to .
  30. MathsJEE Main 6 Apr 2026, Shift 2·Q4·MCQ·Moderate
    Open

    Homogeneous system non-trivial solution

    The sum of all possible values of θ∈[0,2π]\theta \in [0, 2\pi], for which the system of equations:
    xcos⁡3θ−8y−12z=0xcos⁡2θ+3y+3z=0x+y+3z=0\begin{align*} x\cos3\theta - 8y - 12z &= 0\\ x\cos2\theta + 3y + 3z &= 0\\ x + y + 3z &= 0 \end{align*}
    has a non-trivial solution, is equal to:
    1. (1)π\pi
    2. (2)2π2\pi
    3. (3)3π3\pi
    4. (4)4π4\pi
  31. MathsJEE Main 6 Apr 2026, Shift 2·Q5·MCQ·Moderate
    Open

    Powers of a matrix

    Let A=[100310931]andB=[bij], 1≤i,j≤3.A = \begin{bmatrix} 1 & 0 & 0\\ 3 & 1 & 0\\ 9 & 3 & 1\end{bmatrix} \quad\text{and}\quad B = [b_{ij}],\ 1 \le i, j \le 3. If B=A99−IB = A^{99} - I, then the value of b31−b21b32\dfrac{b_{31} - b_{21}}{b_{32}} is:
    1. (1)99
    2. (2)199
    3. (3)149
    4. (4)159
    We corrected a printing error in the original paper

    Source printed “B=[bij]B = [b_{ij}], l≤i,j≤3l \le i, j \le 3” (letter l for the digit 1).

  32. MathsJEE Main 8 Apr 2026, Shift 2·Q3·MCQ·Easy–moderate
    Open

    Consistency of linear equations

    If the system of linear equations:
    x+y+z=6,x+2y+5z=10,2x+3y+λz=μ\begin{align*} x + y + z &= 6,\\ x + 2y + 5z &= 10,\\ 2x + 3y + \lambda z &= \mu \end{align*}
    has infinitely many solutions, then the value of λ+μ\lambda + \mu equals.
    1. (1)12
    2. (2)16
    3. (3)22
    4. (4)28
  33. MathsJEE Main 8 Apr 2026, Shift 2·Q4·MCQ·Moderate
    Open

    Adjoint and determinant properties

    Let A=[α12230045]andB=[1000−5α004α−2α]+adj⁡(A).A = \begin{bmatrix} \alpha & 1 & 2\\ 2 & 3 & 0\\ 0 & 4 & 5\end{bmatrix} \quad\text{and}\quad B = \begin{bmatrix} 1 & 0 & 0\\ 0 & -5\alpha & 0\\ 0 & 4\alpha & -2\alpha\end{bmatrix} + \operatorname{adj}(A). If det⁡(B)=66\det(B) = 66, then det⁡(adj⁡(A))\det(\operatorname{adj}(A)) equals:
    1. (1)289
    2. (2)361
    3. (3)441
    4. (4)529