PhysicsJEE Main 2 Apr 2026, Shift 1·Q24·Numerical·Easy–moderate

Mechanical Properties of Solids · Elasticity

A uniform wire of length

l

of weight

w

is suspended from the roof with a weight of

W

at the other end. The stress in the wire at

\dfrac{l}{3}

distance from the top is

\left(\dfrac{W}{A} + \dfrac{2}{\gamma}\dfrac{w}{A}\right)

, where,

A

is the cross sectional area of the wire. The value of

\gamma

is .

We corrected a printing error in the original paper

Answer corrected; the source key is (6) — it takes the weight of the wire below the point as $w/3$ , but at $l/3$ from the top the wire below weighs $2w/3$ , so the stress is $W/A + \frac{2}{3}\,w/A$ and $\gamma = 3$ .

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Mechanical Properties of Solids · Elasticity

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