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MathsJEE Main 21 Jan 2026, Shift 1·Q11·MCQ·Easy–moderate

Conic Sections · Hyperbola latus rectum

Let the foci of hyperbola coincide with the foci of the ellipse x236+y216=1\dfrac{x^2}{36} + \dfrac{y^2}{16} = 1. If the eccentricity of the hyperbola is 5, then the length of its latus rectum is:
  1. (1)12
  2. (2)16
  3. (3)965\dfrac{96}{\sqrt5}
  4. (4)24524\sqrt5

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