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JEE Main 2026

JEE Main 21 Jan 2026, Shift 1

75 questions. Answers are hidden — tap “Show answer” under each one.

Physics

  1. Potential energy (VV) versus distance (xx) is given by the graph, Rank various regions as per the magnitudes of the force (F) acting on a particle from high to low.
    1. (1)FBC>FCD>FDE>FABF_{BC} > F_{CD} > F_{DE} > F_{AB}
    2. (2)FCD>FAB>FBC>FDEF_{CD} > F_{AB} > F_{BC} > F_{DE}
    3. (3)FCD>FDE>FAB>FBCF_{CD} > F_{DE} > F_{AB} > F_{BC}
    4. (4)FBC>FAB>FDE>FCDF_{BC} > F_{AB} > F_{DE} > F_{CD}
  2. A gas based geyser heats water flowing at the rate of 5.0 litres per minute from 27∘27^\circC to 87∘87^\circC. The rate of consumption of the gas is g/s. (Take heat of combustion of gas =5.0×104= 5.0\times10^{4} J/g) specific heat capacity of water =4200= 4200 J/kg. ∘^\circC
    1. (1)2.1
    2. (2)4.2
    3. (3)0.42
    4. (4)0.21
  3. A conducting circular loop of area 1.0 m21.0\ \mathrm{m^2} is placed perpendicular to a magnetic field which varies as B=sin⁡(100 t)B = \sin(100\,t) Tesla. If the resistance of the loop is 100 Ω100\ \Omega, then the average thermal energy dissipated in the loop in one period is J.
    1. (1)π2\dfrac{\pi}{2}
    2. (2)2π2\pi
    3. (3)π\pi
    4. (4)π2\pi^2
  4. Water flows through a horizontal tube as shown in the figure. The difference in height between the water columns in vertical tubes is 5 cm and the areas of cross-sections at AA and BB are 6 cm26\ \mathrm{cm^2} and 3 cm23\ \mathrm{cm^2} respectively. The rate of flow will be cm3/s\mathrm{cm^3/s}. (take g=10 m/s2g = 10\ \mathrm{m/s^2})
    1. (1)2003\dfrac{200}{\sqrt3}
    2. (2)2006200\sqrt6
    3. (3)2003200\sqrt3
    4. (4)1003100\sqrt3
    We corrected a printing error in the original paper

    Source printed “the area of cross-sections at AA and BB are”.

  5. In an experiment the values of two spring constants were measured as k1=(10±0.2)k_1 = (10 \pm 0.2) N/m and k2=(20±0.3)k_2 = (20 \pm 0.3) N/m. If these springs are connected in parallel, then the percentage error in equivalent spring constant is:
    1. (1)2.67%
    2. (2)2.33%
    3. (3)1.33%
    4. (4)1.67%
  6. A 4 kg mass moves under the influence of a force F⃗=(4t3i^−3tj^)\vec F = (4t^3\hat i - 3t\hat j) N where tt is the time in second. If mass starts from rest at the origin at t=0t = 0, the velocity and position after t=2t = 2 s will be:
    1. (1)v⃗=3i^+32j^,r⃗=65i^+j^\vec v = 3\hat i + \dfrac32\hat j,\quad \vec r = \dfrac65\hat i + \hat j
    2. (2)v⃗=4i^−32j^,r⃗=85i^−j^\vec v = 4\hat i - \dfrac32\hat j,\quad \vec r = \dfrac85\hat i - \hat j
    3. (3)v⃗=4i^+52j^,r⃗=85i^+2j^\vec v = 4\hat i + \dfrac52\hat j,\quad \vec r = \dfrac85\hat i + 2\hat j
    4. (4)v⃗=4i^−32j^,r⃗=65i^−j^\vec v = 4\hat i - \dfrac32\hat j,\quad \vec r = \dfrac65\hat i - \hat j
    We corrected a printing error in the original paper

    Assumption “from rest” added; the source leaves it unstated (“starts from origin at t=0t = 0”).

  7. Consider a modified Bernoulli equation. (P+ABt2)+ρg(h+Bt)+12ρV2=constant\left(P + \frac{A}{Bt^2}\right) + \rho g(h + Bt) + \frac12\rho V^2 = \text{constant} If tt has the dimension of time then the dimensions of AA and BB are , respectively.
    1. (1)[ML0T−1][\mathrm{ML^0T^{-1}}] and [M0LT][\mathrm{M^0LT}]
    2. (2)[ML0T−1][\mathrm{ML^0T^{-1}}] and [M0LT−1][\mathrm{M^0LT^{-1}}]
    3. (3)[ML0T−2][\mathrm{ML^0T^{-2}}] and [M0LT−2][\mathrm{M^0LT^{-2}}]
    4. (4)[ML0T−2][\mathrm{ML^0T^{-2}}] and [M0LT−1][\mathrm{M^0LT^{-1}}]
  8. A current carrying solenoid is placed vertically and a particle of mass mm with charge QQ is released from rest. The particle moves along the axis of solenoid. If gg is acceleration due to gravity then the acceleration (aa) of the charged particle will satisfy:
    1. (1)a=ga = g
    2. (2)a>ga > g
    3. (3)a=0a = 0
    4. (4)0<a<g0 < a < g
    We corrected a printing error in the original paper

    Source printed “A current carrying is placed vertically” (“solenoid” missing).

  9. A parallel plate capacitor has capacitance CC, when there is vacuum within the parallel plates. A sheet having thickness (13)rd\left(\frac13\right)^{\text{rd}} of the separation between the plates and relative permittivity KK is introduced between the plates. The new capacitance of the system is:
    1. (1)3KC2K+1\dfrac{3KC}{2K+1}
    2. (2)CK2+K\dfrac{CK}{2+K}
    3. (3)3CK2(2K+1)2\dfrac{3CK^2}{(2K+1)^2}
    4. (4)4KC3K−1\dfrac{4KC}{3K-1}
  10. The electric field of a plane electromagnetic wave is given by: Ey=69sin⁡[0.6×103x−1.8×1011t] V/m.E_y = 69\sin[0.6\times10^{3}x - 1.8\times10^{11}t]\ \mathrm{V/m}. The expression for magnetic field associated with this electromagnetic wave is T.
    1. (1)Bz=2.3×10−7sin⁡[0.6×103x−1.8×1011t]B_z = 2.3\times10^{-7}\sin[0.6\times10^{3}x - 1.8\times10^{11}t]
    2. (2)Bz=2.3×10−7sin⁡[0.6×103x+1.8×1011t]B_z = 2.3\times10^{-7}\sin[0.6\times10^{3}x + 1.8\times10^{11}t]
    3. (3)By=69sin⁡[0.6×103x+1.8×1011t]B_y = 69\sin[0.6\times10^{3}x + 1.8\times10^{11}t]
    4. (4)By=2.3×10−7sin⁡[0.6×103x−1.8×1011t]B_y = 2.3\times10^{-7}\sin[0.6\times10^{3}x - 1.8\times10^{11}t]
    We corrected a printing error in the original paper

    Source printed “The electric field a plane electromagnetic wave”.

  11. Q11 · MCQ · Wave OpticsOpen
    In a double slit experiment the distance between the slits is 0.1 cm and the screen is placed at 50 cm from the slits plane. When one slit is covered with a transparent sheet having thickness tt and refractive index n (=1.5)n\,(=1.5), the central fringe shifts by 0.2 cm. The value of tt is cm.
    1. (1)8×10−48\times10^{-4}
    2. (2)6.0×10−36.0\times10^{-3}
    3. (3)5.6×10−45.6\times10^{-4}
    4. (4)5.0×10−35.0\times10^{-3}
  12. A light wave described by E=60[sin⁡(3×1015t)+sin⁡(12×1015t)]E = 60[\sin(3\times10^{15}t) + \sin(12\times10^{15}t)] (in SI units) falls on a metal surface of work function 2.8 eV. The maximum kinetic energy of ejected photoelectron is (approximately) eV. (h=6.6×10−34h = 6.6\times10^{-34} J-s. and e=1.6×10−19e = 1.6\times10^{-19} C)
    1. (1)5.1
    2. (2)3.8
    3. (3)6.0
    4. (4)7.8
    We corrected a printing error in the original paper

    Source printed “E=60sin⁡(3×1015)t+sin⁡(12×1015)t]E = 60\sin(3\times10^{15})t + \sin(12\times10^{15})t]”.

  13. Q13 · MCQ · AtomsOpen
    If an alpha particle with energy 7.7 MeV is bombarded on a thin gold foil, the closest distance from nucleus it can reach is m. (Atomic number of gold =79= 79 and 14πϵ0=9×109\dfrac{1}{4\pi\epsilon_0} = 9\times10^{9} in SI units)
    1. (1)2.95×10−142.95\times10^{-14}
    2. (2)2.95×10−162.95\times10^{-16}
    3. (3)3.85×10−163.85\times10^{-16}
    4. (4)3.85×10−143.85\times10^{-14}
  14. A uniform rod of mass mm and length ll is suspended by means of two identical inextensible light strings as shown in figure. Tension in one string immediately after the other string is cut, is . (gg acceleration due to gravity)
    1. (1)mg/2mg/2
    2. (2)mg/4mg/4
    3. (3)mg/3mg/3
    4. (4)mgmg
    We corrected a printing error in the original paper

    Source printed “length ll suspended by means of”.

  15. Aluminium and steel rods having same lengths and cross-sections are joined to make total length of 120 cm at 30∘30^\circC. The coefficients of linear expansion of aluminium and steel are 24×10−6/∘24\times10^{-6}/^\circC and 1.2×10−5/∘1.2\times10^{-5}/^\circC, respectively. The length of this composite rod when its temperature is raised to 100∘100^\circC, is cm.
    1. (1)120.20
    2. (2)120.15
    3. (3)120.03
    4. (4)120.06
    We corrected a printing error in the original paper

    Source printed “An aluminium and steel rods” and “The coefficient of linear expansion … are”.

  16. A 1 m long metal rod AB completes the circuit as shown in figure. The area of circuit is perpendicular to the magnetic field of 0.10 T. If the resistance of the total circuit is 2 Ω2\ \Omega then the force needed to move the rod towards right with constant speed (vv) of 1.5 m/s is N.
    1. (1)7.5×10−27.5\times10^{-2}
    2. (2)5.7×10−35.7\times10^{-3}
    3. (3)5.7×10−25.7\times10^{-2}
    4. (4)7.5×10−37.5\times10^{-3}
  17. The given circuit works as:
    1. (1)AND gate
    2. (2)NOR gate
    3. (3)NAND gate
    4. (4)OR gate
  18. Q18 · MCQ · WavesOpen
    Two strings (A, B) having linear densities μA=2×10−4\mu_A = 2\times10^{-4} kg/m and μB=4×10−4\mu_B = 4\times10^{-4} kg/m and lengths LA=2.5L_A = 2.5 m and LB=1.5L_B = 1.5 m respectively are joined. Free ends of A and B are tied to two rigid supports C and D, respectively creating a tension of 500 N in the wire. Two identical pulses, sent from C and D ends, take time t1t_1 and t2t_2, respectively, to reach the joint. The ratio t1/t2t_1/t_2 is:
    1. (1)1.08
    2. (2)1.90
    3. (3)1.67
    4. (4)1.18
  19. Q19 · MCQ · GravitationOpen
    Initially a satellite of 100 kg is in a circular orbit of radius 1.5RE1.5R_E. This satellite can be moved to a circular orbit of radius 3RE3R_E by supplying α×106\alpha\times10^{6} J of energy. The value of α\alpha is . (Take Radius of Earth RE=6×106R_E = 6\times10^{6} m and g=10 m/s2g = 10\ \mathrm{m/s^2})
    1. (1)150
    2. (2)500
    3. (3)100
    4. (4)1000
  20. A point charge of 10−810^{-8} C is placed at origin. The work done in moving a point charge 2 μ2\ \muC from point A(4, 4, 2) m to B(2, 2, 1) m is J. (14πϵ0=9×109\dfrac{1}{4\pi\epsilon_0} = 9\times10^{9} in SI units)
    1. (1)45×10−645\times10^{-6}
    2. (2)0
    3. (3)30×10−630\times10^{-6}
    4. (4)15×10−615\times10^{-6}
  21. Q21 · Numerical · Ray OpticsOpen
    A collimated beam of light of diameter 2 mm is propagating along x-axis. The beam is required to be expanded in a collimated beam of diameter 14 mm using a system of two convex lenses. If first lens has focal length 40 mm, then the focal length of second lens is mm.
  22. Q22 · Numerical · Current ElectricityOpen
    The heat generated in 1 minute between points A and B in the given circuit, when a battery of 9 V with internal resistance of 1 Ω1\ \Omega is connected across these points is J.
  23. Q23 · Numerical · Rotational MotionOpen
    Two identical thin rods of mass MM kg and length LL m are connected as shown in figure. Moment of inertia of the combined rod system about an axis passing through point P and perpendicular to the plane of the rods is x12ML2 kg m2\dfrac{x}{12}ML^2\ \mathrm{kg\,m^2}. The value of xx is .
    We corrected a printing error in the original paper

    Source printed “x2ML2\dfrac{x}{2}ML^2” (which gives x=17/6x = 17/6); corrected to the intended “x12ML2\dfrac{x}{12}ML^2” (I=17ML2/12I = 17ML^2/12, source key 17).

  24. Q24 · Numerical · ThermodynamicsOpen
    10 mole of oxygen is heated at constant volume from 30∘30^\circC to 40∘40^\circC. The change in the internal energy of the gas is cal. (The molecular specific heat of oxygen at constant pressure, Cp=7C_p = 7 cal./mol ∘^\circC and R=2R = 2 cal./mol ∘^\circC.)
  25. Q25 · Numerical · Ray OpticsOpen
    In a microscope the objective is having focal length f0=2f_0 = 2 cm and eye-piece is having focal length fe=4f_e = 4 cm. The tube length is 32 cm. The magnification produced by this microscope for normal adjustment is .

Chemistry

  1. Consider the following reactions.

    PbClX2+KX2CrOX4→A+2 KCl\ce{PbCl2 + K2CrO4 -> A + 2KCl}

    (Hot solution)

    A+NaOH⇌B+NaX2CrOX4\ce{A + NaOH <=> B + Na2CrO4}

    PbSOX4+4 CHX3COONHX4→(NHX4)X2SOX4+X\ce{PbSO4 + 4CH3COONH4 -> (NH4)2SO4 + X}

    In the above reactions, A, B and X are respectively.

    1. (1)NaX2[Pb(OH)X2]\ce{Na2[Pb(OH)2]}, PbCrOX4\ce{PbCrO4} and (NHX4)X2[Pb(CHX3COO)X4]\ce{(NH4)2[Pb(CH3COO)4]}
    2. (2)PbCrOX4\ce{PbCrO4}, NaX2[Pb(OH)X4]\ce{Na2[Pb(OH)4]} and [Pb(NHX3)X4]SOX4\ce{[Pb(NH3)4]SO4}
    3. (3)NaX2[Pb(OH)X2]\ce{Na2[Pb(OH)2]}, PbCrOX4\ce{PbCrO4} and [Pb(NHX3)X4]SOX4\ce{[Pb(NH3)4]SO4}
    4. (4)PbCrOX4\ce{PbCrO4}, NaX2[Pb(OH)X4]\ce{Na2[Pb(OH)4]} and (NHX4)X2[Pb(CHX3COO)X4]\ce{(NH4)2[Pb(CH3COO)4]}
  2. Which of the following represents the correct trend for the mentioned property ?
    • (A)F >> P >> S >> B – First Ionization Energy
    • (B)Cl >> F >> S >> P – Electron Affinity
    • (C)K >> Al >> Mg >> B – Metallic character
    • (D)KX2O\ce{K2O} >> NaX2O\ce{Na2O} >> MgO\ce{MgO} >> AlX2OX3\ce{Al2O3} – Basic character
    Choose the correct answer from the option given below.
    1. (1)A, B and D only
    2. (2)A, B, C and D
    3. (3)A and B only
    4. (4)B and C only
    We corrected a printing error in the original paper

    Source printed “Frist Ionization Energy”.

  3. Q3 · MCQ · HydrocarbonsOpen
    Identify A in the following reaction.
    1. (1)
    2. (2)
    3. (3)
    4. (4)
  4. Q4 · MCQ · HydrocarbonsOpen
    A hydrocarbon ‘P' (CX4HX8\ce{C4H8}) on reaction with HCl gives an optically active compound ‘Q' (CX4HX9Cl\ce{C4H9Cl}) which on reaction with one mole of ammonia gives compound ‘R' (CX4HX11N\ce{C4H11N}). ‘R' on diazotization followed by hydrolysis gives ‘S'. Identify P, Q, R and S.
    1. (1)
    2. (2)
    3. (3)
    4. (4)
    We corrected a printing error in the original paper

    Option (3): source printed R as “CH3_3–CH2_2=CH(NH2_2)–CH3_3” (a pentavalent carbon); the “=” in the figure is corrected to the intended single bond “CH3_3–CH2_2–CH(NH2_2)–CH3_3” (butan-2-amine).

  5. Given below are two statements :

    Statement I : The number of pairs among [SiOX2\ce{SiO2}, COX2\ce{CO2}], [SnO\ce{SnO}, SnOX2\ce{SnO2}], [PbO\ce{PbO}, PbOX2\ce{PbO2}] and [GeO\ce{GeO}, GeOX2\ce{GeO2}], which contain oxides that are both amphoteric is 2.

    Statement II : BFX3\ce{BF3} is an electron deficient molecule that can act as a lewis acid, forms adduct with NHX3\ce{NH3} and has a trigonal planar geometry.

    In the light of the above statement, choose the correct answer from the option given below.

    1. (1)Both Statement I and Statement II are true.
    2. (2)Both Statement I and Statement II are false.
    3. (3)Statement I is true but Statement II is false.
    4. (4)Statement I is false but Statement II is true.
    We corrected a printing error in the original paper

    Source printed “an electron deficient molecule can act as a lewis acid” and, in option (4), “Statement I is false Statement II is true”.

  6. 80 mL of a hydrocarbon on mixing with 264 mL of oxygen in a closed U-tube undergoes complete combustion. The residual gases after cooling to 273 K occupy 224 mL. When the system is treated with KOH solution, the volume decreases to 64 mL. The formula of the hydrocarbon is :
    1. (1)CX2HX4\ce{C2H4}
    2. (2)CX4HX10\ce{C4H10}
    3. (3)CX2HX2\ce{C2H2}
    4. (4)CX2HX6\ce{C2H6}
  7. 14.0 g of calcium metal is allowed to react with excess HCl at 1.0 atm pressure and 273 K.

    Which of the following statements is incorrect ?

    [Given : Molar mass in g mol−1^{-1} of Ca–40, Cl–35.5, H–1]

    1. (1)0.35 mol of HX2\ce{H2} gas is evolved.
    2. (2)7.84 L of HX2\ce{H2} gas is evolved.
    3. (3)33.3 g of CaClX2\ce{CaCl2} is produced.
    4. (4)The limiting reagent is calcium metal.
    We corrected a printing error in the original paper

    Source printed “33.3 of CaClX2\ce{CaCl2} is produced” (unit missing).

  8. In Carius method, 0.75 g of an organic compound gave 1.2 g of barium sulphate, find percentage of sulphur (molar mass 32 g mol−1^{-1}). Molar mass of barium sulphate is 233 g mol−1^{-1}.
    1. (1)4.55%
    2. (2)10.30%
    3. (3)21.97%
    4. (4)16.48%
  9. Q9 · MCQ · SolutionsOpen
    Elements P and Q form two types of non-volatile, non-ionizable compounds PQ and PQX2\ce{PQ2}. When 1 g of PQ is dissolved in 50 g of solvent ‘A'. ΔTb\Delta T_\mathrm{b} was 1.176 K while when 1 g of PQX2\ce{PQ2} is dissolved in 50 g of solvent ‘A', ΔTb\Delta T_\mathrm{b} was 0.689 K. (KbK_\mathrm{b} of ‘A' =5= 5 K kg mol−1^{-1}). The molar masses of elements P and Q (in g mol−1^{-1}) respectively, are :
    1. (1)70, 110
    2. (2)65, 145
    3. (3)60, 25
    4. (4)25, 60
  10. Q10 · MCQ · AminesOpen
    An organic compound (P) on treatment with aqueous ammonia under hot condition forms compound (Q) which on heating with BrX2\ce{Br2} and KOH forms compound (R) having molecular formula CX6HX7N\ce{C6H7N}. Names of P, Q and R respectively are.
    1. (1)Benzoic acid, benzamide, aniline
    2. (2)Toluic acid, methylbenzamide, 2-methylaniline
    3. (3)Benzoic acid, 4-methylbenzamide, 4-methylaniline.
    4. (4)Phenylethanoic acid, phenylethanamide, benzamine
    We corrected a printing error in the original paper

    Source printed “molecular formula CX9HX7N\ce{C9H7N}” (fits no option); corrected to the intended “CX6HX7N\ce{C6H7N}” (aniline, source key (1)).

  11. An organic compound “P” of molecular formula CX6HX12OX3\ce{C6H12O3} gives positive Iodoform test but negative Tollen's test. When “P” is treated with dilute acid, it produces “Q”. “Q” gives positive Tollen's test and also iodoform test. The structure of “P” is :
    1. (1)
    2. (2)
    3. (3)
    4. (4)
  12. From the following, the least stable structure is :
    1. (1)
    2. (2)
    3. (3)
    4. (4)
  13. Q13 · MCQ · d- and f-BlockOpen
    MnOX4X2−\ce{MnO4^2-}, in acidic medium, disproportionates to :
    1. (1)MnX2OX7\ce{Mn2O7} and MnOX2\ce{MnO2}
    2. (2)MnOX4X−\ce{MnO4-} and MnO\ce{MnO}
    3. (3)MnOX4X−\ce{MnO4-} and MnOX2\ce{MnO2}
    4. (4)MnX2OX7\ce{Mn2O7} and MnO\ce{MnO}
  14. Q14 · MCQ · Chemical BondingOpen

    Given below are two statements:

    Statement I: The number of species among SFX4\ce{SF4}, NHX4X+\ce{NH4+}, [NiClX4]X2−\ce{[NiCl4]^2-}, XeFX4\ce{XeF4}, [PtClX4]X2−\ce{[PtCl4]^2-}, SeFX4\ce{SeF4} and [Ni(CN)X4]X2−\ce{[Ni(CN)4]^2-}, that have tetrahedral geometry is 3.

    Statement II: In the set [NOX2\ce{NO2}, BeHX2\ce{BeH2}, BFX3\ce{BF3}, AlClX3\ce{AlCl3}], all the molecules have incomplete octet around central atom.

    In the light of the above statements, choose the correct answer from the options given below:

    1. (1)Statement I is true but Statement II is false
    2. (2)Both Statement I and Statement II are false
    3. (3)Statement I is false but Statement II is true
    4. (4)Both Statement I and Statement II are true
    We corrected a printing error in the original paper

    Source printed “[NiCl4_4]” (charge missing), “[PtC14_4]2−^{2-}” and “AIC13_3” (digit 1 and capital I for l).

  15. Given below are two statements:

    Statement I: Among [Cu(NHX3)X4]X2+\ce{[Cu(NH3)4]^2+}, [Ni(en)X3]X2+\ce{[Ni(en)3]^2+}, [Ni(NHX3)X6]X2+\ce{[Ni(NH3)6]^2+} and [Mn(HX2O)X6]X2+\ce{[Mn(H2O)6]^2+}, [Mn(HX2O)X6]X2+\ce{[Mn(H2O)6]^2+}, has the maximum number of unpaired electrons.

    Statement II: The number of pairs among {[NiClX4]X2−\ce{[NiCl4]^2-}, [Ni(CO)X4]\ce{[Ni(CO)4]}}, {[NiClX4]X2−\ce{[NiCl4]^2-}, [Ni(CN)X4]X2−\ce{[Ni(CN)4]^2-}} and {[Ni(CO)X4]\ce{[Ni(CO)4]}, [Ni(CN)X4]X2−\ce{[Ni(CN)4]^2-}} that contain only diamagnetic species is two.

    In the light of the above statements, choose the correct answer from the options given below:

    1. (1)Statement I is false but Statement II is true
    2. (2)Both Statement I and Statement II are true
    3. (3)Both Statement I and Statement II are false
    4. (4)Statement I is true but Statement II is false
    We corrected a printing error in the original paper

    Source printed “[Cu(NH3_3)2+^{2+}” (subscript 4 and closing bracket missing), “[Ni(en)3_3)]2+^{2+}” and the second pair “[NiCl4_4]2−^{2-}, [Ni(CN)4_4]2−^{2-}” without its closing brace.

  16. Identify correct statement from the following :
    • (A)Propanal and propanone are functional isomers.
    • (B)Ethoxyethane and methoxypropane are metamers.
    • (C)But-2-ene shows optical isomerism.
    • (D)But-1-ene and but-2-ene are functional isomers.
    • (E)Pentane and 2, 2-dimethyl propane are chain isomers.
    Choose the correct answer from the options given below :
    1. (1)B, C and D only
    2. (2)A, B and C only
    3. (3)A, B and E only
    4. (4)C, D and E only
  17. Q17 · MCQ · BiomoleculesOpen
    Identify the correct statements.
    • (A)Arginine and Tryptophan are essential amino acids.
    • (B)Histidine does not contain heterocyclic ring in its structure.
    • (C)Proline is a six membered cyclic ring amino acid.
    • (D)Glycine does not have chiral centre.
    • (E)Cysteine has characteristic feature of side chain as MeS−CHX2−CHX2X−\ce{MeS-CH2-CH2-}.

    Choose the correct answer from the options given below:

    Option

    1. (1)C and E Only
    2. (2)B and E Only
    3. (3)C and D Only
    4. (4)A and D Only
  18. Q18 · MCQ · ThermodynamicsOpen
    Which of the following graphs between pressure ‘P' versus volume ‘V' represent the maximum work done ?
    1. (1)
    2. (2)
    3. (3)
    4. (4)
  19. Q19 · MCQ · ThermodynamicsOpen
    For the reaction, NX2OX4⇌2 NOX2\ce{N2O4 <=> 2NO2}, graph is plotted as shown below. Identify correct statements.
    • (A)Standard free energy change for the reaction is −5.40-5.40 kJ mol−1^{-1}.
    • (B)As ΔG⊖\Delta G^\ominus in graph is positive, NX2OX4\ce{N2O4} will not dissociate into NOX2\ce{NO2} at all.
    • (C)Reverse reaction will go to completion.
    • (D)When 1 mole of NX2OX4\ce{N2O4} changes into equilibrium mixture, value of ΔG⊖=−0.84\Delta G^\ominus = -0.84 kJ mol−1^{-1}
    • (E)When 2 mole of NOX2\ce{NO2}, changes into equilibrium mixture, ΔG⊖\Delta G^\ominus for equilibrium mixture is −6.24-6.24 kJ mol−1^{-1}.
    Choose the correct answer from the options given below :
    1. (1)D and E only
    2. (2)C and E only
    3. (3)A and D only
    4. (4)B and C only
    We corrected a printing error in the original paper

    Source printed “As AG⊖^\ominus in graph is positive” and printed statement E twice.

  20. Given below are two statements:

    Statement I: When an electric discharge is passed through gaseous hydrogen, the hydrogen molecules dissociate and the energetically excited hydrogen atoms produce electromagnetic radiation of discrete frequencies.

    Statement II: The frequency of second line of Balmer series obtained from HeX+\ce{He+} is equal to that of first line of Lyman series obtained from hydrogen atom.

    In the light of the above statements, choose the correct answer from the options given below:

    1. (1)Both Statement I and Statement II are true
    2. (2)Both Statement I and Statement II are false
    3. (3)Statement I is false but Statement II is true
    4. (4)Statement I is true but Statement II is false
  21. Q21 · Numerical · Chemical KineticsOpen
    Pre-exponential factors of two different reactions of same order are identical. Let activation energy of first reaction exceed the activation energy of second reaction by 20 kJ mol−1^{-1}. If k1k_1 and k2k_2 are the rate constants of first and second reaction respectively at 300 K, then ln⁡k2k1\ln\dfrac{k_2}{k_1} will be . (nearest integer) [R=8.3R = 8.3 J K−1^{-1} mol−1^{-1}]
    We corrected a printing error in the original paper

    Source printed “Let activation energy of first reaction exceeds” and “In k2k1\dfrac{k_2}{k_1}” (capital I for the natural logarithm ln).

  22. Q22 · Numerical · ElectrochemistryOpen

    The pH and conductance of a weak acid (HX) were found to be 5 and 4×10−54\times10^{-5} S, respectively. The conductance was measured under standard condition using a cell where the electrode plates having a surface area of 1 cm2^2 were at a distance of 15 cm apart. The value of the limiting molar conductivity is S m2^2 mol−1^{-1}. (nearest integer)

    (Given: degree of dissociation of the weak acid (α\alpha) ≪1\ll 1)

    We corrected a printing error in the original paper

    Source printed “The pH and conductance of a weak acid (HX) was found” and “the weak acid (a) ≪\ll 1”.

  23. Q23 · Numerical · ThermodynamicsOpen
    Use the following data :
    SubstanceΔfH⊖(500 K)kJ mol−1\dfrac{\Delta_\mathrm{f}H^\ominus(500\,\mathrm{K})}{\mathrm{kJ\,mol^{-1}}}S⊖(500 K)J K−1 mol−1\dfrac{S^\ominus(500\,\mathrm{K})}{\mathrm{J\,K^{-1}\,mol^{-1}}}
    AB(g)32222
    AX2\ce{A2}(g)6146
    BX2\ce{B2}(g)X280

    One mole each of AX2\ce{A2}(g) and BX2\ce{B2}(g) are taken in a 1L closed flask and allowed to establish the equilibrium at 500K.

    AX2(g)+BX2(g)⇌2 AB(g)\ce{A2(g) + B2(g) <=> 2AB(g)}

    The value of X (in kJ mol−1^{-1}) is . (Nearest integer)

    (Given: log⁡K=2.2\log K = 2.2, R=8.3R = 8.3 J K−1^{-1} mol−1^{-1})

    We corrected a printing error in the original paper

    Source printed “The value of x” (the table names the quantity X).

  24. Q24 · Numerical · AminesOpen
    Consider the following reaction sequence

    The percentage of nitrogen in product ‘T' formed is %. (Nearest integer)

    (Given molar mass in g mol−1^{-1} H:1, C:12, N:14, O:16)

    We corrected a printing error in the original paper

    Source printed the reagent over the third arrow as “(CH3_3CO)2_2”; corrected in the figure to acetic anhydride “(CH3_3CO)2_2O”.

  25. Q25 · Numerical · d- and f-BlockOpen

    Consider the following reactions:

    NaCl+KX2CrX2OX7+HX2SOX4→A+KHSOX4+NaHSOX4+HX2O\ce{NaCl + K2Cr2O7 + H2SO4 -> A + KHSO4 + NaHSO4 + H2O}

    A+NaOH→B+NaCl+HX2O\ce{A + NaOH -> B + NaCl + H2O}

    B+HX2SOX4+HX2OX2→C+NaX2SOX4+HX2O\ce{B + H2SO4 + H2O2 -> C + Na2SO4 + H2O}

    In the product ‘C', ‘X' is the number of OX2X2−\ce{O2^2-} units, ‘Y' is the total number of oxygen atoms present and ‘Z' is the oxidation state of Cr. The value of X + Y + Z is .

    We corrected a printing error in the original paper

    Source printed “the total number oxygen atoms”.

Maths

  1. If the domain of the function f(x)=cos⁡−1(2x−511−3x)+sin⁡−1(2x2−3x+1)f(x) = \cos^{-1}\left(\dfrac{2x-5}{11-3x}\right) + \sin^{-1}(2x^2 - 3x + 1) is the interval [α,β][\alpha, \beta], then α+2β\alpha + 2\beta is equal to:
    1. (1)1
    2. (2)3
    3. (3)5
    4. (4)2
  2. The area of the region, inside the ellipse x2+4y2=4x^2 + 4y^2 = 4 and outside the region bounded by the curves y=∣x∣−1y = \lvert x\rvert - 1 and y=1−∣x∣y = 1 - \lvert x\rvert, is:
    1. (1)2(π−1)2(\pi - 1)
    2. (2)2π−122\pi - \dfrac12
    3. (3)3(π−1)3(\pi - 1)
    4. (4)2π−12\pi - 1
  3. The number of relations, defined on the set {a,b,c,d}\{a, b, c, d\}, which are both reflexive and symmetric, is equal to:
    1. (1)256
    2. (2)16
    3. (3)1024
    4. (4)64
  4. Q4 · MCQ · Straight LinesOpen
    Let a point AA lie between the parallel lines L1L_1 and L2L_2 such that its distances from L1L_1 and L2L_2 are 6 and 3 units, respectively. Then the area (in sq. units) of the equilateral triangle ABCABC, where the points BB and CC lie on the lines L1L_1 and L2L_2 respectively, is:
    1. (1)15615\sqrt6
    2. (2)27
    3. (3)21321\sqrt3
    4. (4)12212\sqrt2
  5. Q5 · MCQ · VectorsOpen
    Let a⃗=−i^+2j^+2k^\vec a = -\hat i + 2\hat j + 2\hat k, b⃗=8i^+7j^−3k^\vec b = 8\hat i + 7\hat j - 3\hat k and c⃗\vec c be a vector such that a⃗×c⃗=b⃗\vec a\times\vec c = \vec b. If c⃗⋅(i^+j^+k^)=4\vec c\cdot(\hat i + \hat j + \hat k) = 4, then ∣a⃗+c⃗∣2\lvert\vec a + \vec c\rvert^2 is equal to:
    1. (1)33
    2. (2)30
    3. (3)35
    4. (4)27
  6. Let a1,a2,a3,…a_1, a_2, a_3, \ldots be a G.P. of increasing positive terms such that a2⋅a3⋅a4=64a_2\cdot a_3\cdot a_4 = 64 and a1+a3+a5=8137a_1 + a_3 + a_5 = \dfrac{813}{7}. Then a3+a5+a7a_3 + a_5 + a_7 is equal to:
    1. (1)3256
    2. (2)3252
    3. (3)3244
    4. (4)3248
  7. Q7 · MCQ · VectorsOpen
    Let c⃗\vec c and d⃗\vec d be vectors such that ∣c⃗+d⃗∣=29\lvert\vec c + \vec d\rvert = \sqrt{29} and c⃗×(2i^+3j^+4k^)=(2i^+3j^+4k^)×d⃗\vec c\times(2\hat i + 3\hat j + 4\hat k) = (2\hat i + 3\hat j + 4\hat k)\times\vec d. If λ1,λ2 (λ1>λ2)\lambda_1, \lambda_2\ (\lambda_1 > \lambda_2) are the possible values of (c⃗+d⃗)⋅(−7i^+2j^+3k^)(\vec c + \vec d)\cdot(-7\hat i + 2\hat j + 3\hat k), then the equation K2x2+(K2−5K+λ1)xy+(3K+λ22)y2−8x+12y+λ2=0K^2x^2 + (K^2 - 5K + \lambda_1)xy + \left(3K + \dfrac{\lambda_2}{2}\right)y^2 - 8x + 12y + \lambda_2 = 0 represents a circle, for KK equal to:
    1. (1)4
    2. (2)1
    3. (3)−1-1
    4. (4)2
    We corrected a printing error in the original paper

    Source printed “represents a circle, for kk equal to” (lower-case kk; the equation uses KK).

  8. Let y=y(x)y = y(x) be the solution curve of the differential equation (1+x2) dy+(y−tan⁡−1x) dx=0(1 + x^2)\,dy + (y - \tan^{-1}x)\,dx = 0, y(0)=1y(0) = 1. Then the value of y(1)y(1) is:
    1. (1)2eπ4+π4−1\dfrac{2}{e^{\frac{\pi}{4}}} + \dfrac{\pi}{4} - 1
    2. (2)2eπ4−π4−1\dfrac{2}{e^{\frac{\pi}{4}}} - \dfrac{\pi}{4} - 1
    3. (3)4eπ4+π2−1\dfrac{4}{e^{\frac{\pi}{4}}} + \dfrac{\pi}{2} - 1
    4. (4)4eπ4−π2−1\dfrac{4}{e^{\frac{\pi}{4}}} - \dfrac{\pi}{2} - 1
  9. The number of strictly increasing functions ff from the set {1,2,3,4,5,6}\{1, 2, 3, 4, 5, 6\} to the set {1,2,3,…,9}\{1, 2, 3, \ldots, 9\} such that f(i)≠if(i) \neq i for 1≤i≤61 \le i \le 6, is equal to:
    1. (1)21
    2. (2)27
    3. (3)22
    4. (4)28
    We corrected a printing error in the original paper

    Source printed the second set as “(1,2,3,…,9)(1, 2, 3, \ldots, 9)” (parentheses instead of set braces).

  10. Let f:R→(0,∞)f : \mathbb{R} \to (0, \infty) be a twice differentiable function such that f(3)=18f(3) = 18, f′(3)=0f'(3) = 0 and f′′(3)=4f''(3) = 4. Then lim⁡x→1(log⁡e(f(2+x)f(3))18(x−1)2)\lim_{x\to1}\left(\log_e\left(\dfrac{f(2+x)}{f(3)}\right)^{\frac{18}{(x-1)^2}}\right) is equal to:
    1. (1)1
    2. (2)9
    3. (3)2
    4. (4)18
  11. Q11 · MCQ · Conic SectionsOpen
    Let the foci of hyperbola coincide with the foci of the ellipse x236+y216=1\dfrac{x^2}{36} + \dfrac{y^2}{16} = 1. If the eccentricity of the hyperbola is 5, then the length of its latus rectum is:
    1. (1)12
    2. (2)16
    3. (3)965\dfrac{96}{\sqrt5}
    4. (4)24524\sqrt5
  12. The value of ∫−π/6π/6(π+4x111−sin⁡(∣x∣+π/6))dx\displaystyle\int_{-\pi/6}^{\pi/6}\left(\frac{\pi + 4x^{11}}{1 - \sin(\lvert x\rvert + \pi/6)}\right)dx is equal to
    1. (1)2π2\pi
    2. (2)4π4\pi
    3. (3)8π8\pi
    4. (4)6π6\pi
  13. Q13 · MCQ · StatisticsOpen
    Let the mean and variance of 7 observations 2, 4, 10, xx, 12, 14, yy, x>yx > y, be 8 and 16 respectively. Two numbers are chosen from {1,2,3,x−4,y,5}\{1, 2, 3, x-4, y, 5\} one after another without replacement, then the probability, that the smaller number among the two chosen numbers is less than 4, is:
    1. (1)35\dfrac35
    2. (2)45\dfrac45
    3. (3)25\dfrac25
    4. (4)13\dfrac13
  14. Q14 · MCQ · 3D GeometryOpen
    Let (α,β,γ)(\alpha, \beta, \gamma) be the co-ordinates of the foot of the perpendicular drawn from the point (5,4,2)(5, 4, 2) on the line r⃗=(−i^+3j^+k^)+λ(2i^+3j^−k^)\vec r = (-\hat i + 3\hat j + \hat k) + \lambda(2\hat i + 3\hat j - \hat k). Then the length of the projection of the vector αi^+βj^+γk^\alpha\hat i + \beta\hat j + \gamma\hat k on the vector 6i^+2j^+3k^6\hat i + 2\hat j + 3\hat k is:
    1. (1)157\dfrac{15}{7}
    2. (2)4
    3. (3)187\dfrac{18}{7}
    4. (4)3
  15. Q15 · MCQ · CirclesOpen
    Let PQPQ and MNMN be two straight lines touching the circle x2+y2−4x−6y−3=0x^2 + y^2 - 4x - 6y - 3 = 0 at the points AA and BB respectively. Let OO be the centre of the circle and ∠AOB=π/3\angle AOB = \pi/3. Then the locus of the point of intersection of the lines PQPQ and MNMN is:
    1. (1)3(x2+y2)−18x−12y+25=03(x^2 + y^2) - 18x - 12y + 25 = 0
    2. (2)x2+y2−12x−18y−25=0x^2 + y^2 - 12x - 18y - 25 = 0
    3. (3)x2+y2−18x−12y−25=0x^2 + y^2 - 18x - 12y - 25 = 0
    4. (4)3(x2+y2)−12x−18y−25=03(x^2 + y^2) - 12x - 18y - 25 = 0
  16. Q16 · MCQ · Binomial TheoremOpen
    If the coefficient of xx in the expansion of (ax2+bx+c)(1−2x)26(ax^2 + bx + c)(1 - 2x)^{26} is −56-56 and the coefficients of x2x^2 and x3x^3 are both zero, then a+b+ca + b + c is equal to
    1. (1)1300
    2. (2)1500
    3. (3)1403
    4. (4)1483
  17. Q17 · MCQ · Complex NumbersOpen
    If x2+x+1=0x^2 + x + 1 = 0, then the value of (x+1x)4+(x2+1x2)4+(x3+1x3)4+…+(x25+1x25)4\left(x + \frac1x\right)^4 + \left(x^2 + \frac{1}{x^2}\right)^4 + \left(x^3 + \frac{1}{x^3}\right)^4 + \ldots + \left(x^{25} + \frac{1}{x^{25}}\right)^4 is:
    1. (1)128
    2. (2)162
    3. (3)175
    4. (4)145
  18. Q18 · MCQ · TrigonometryOpen
    The value of cosec⁡10∘−3 sec⁡10∘\operatorname{cosec}10^\circ - \sqrt3\,\sec10^\circ is equal to:
    1. (1)4
    2. (2)2
    3. (3)8
    4. (4)6
  19. The sum of all the roots of the equation (x−1)2−5∣x−1∣+6=0(x-1)^2 - 5\lvert x - 1\rvert + 6 = 0, is:
    1. (1)4
    2. (2)3
    3. (3)1
    4. (4)5
  20. Q20 · MCQ · Conic SectionsOpen
    Let OO be the vertex of the parabola x2=4yx^2 = 4y and QQ be any point on it. Let the locus of the point PP, which divides the line segment OQOQ internally in the ratio 2:32:3 be the conic CC. Then the equation of the chord of CC, which is bisected at the point (1,2)(1, 2), is:
    1. (1)5x−y−3=05x - y - 3 = 0
    2. (2)4x−5y+6=04x - 5y + 6 = 0
    3. (3)x−2y+3=0x - 2y + 3 = 0
    4. (4)5x−4y+3=05x - 4y + 3 = 0
    We corrected a printing error in the original paper

    Source labels the options “(1), (2), (4), (4)”; the third option (x−2y+3=0x - 2y + 3 = 0) is printed as “(4)”, the key (4) is the last option.

  21. Q21 · Numerical · Differential EquationsOpen
    Let f:R→Rf : \mathbb{R} \to \mathbb{R} be a twice differentiable function such that the quadratic equation f(x)m2−2f′(x)m+f′′(x)=0f(x)m^2 - 2f'(x)m + f''(x) = 0 in mm, has two equal roots for every x∈Rx \in \mathbb{R}. If f(0)=1f(0) = 1, f′(0)=2f'(0) = 2 and (α,β)(\alpha, \beta) is the largest interval in which the function f(log⁡ex−x)f(\log_e x - x) is increasing, then α+β\alpha + \beta is equal to .
  22. Q22 · Numerical · Sequences & SeriesOpen
    Let a1=1a_1 = 1 and for n≥1n \ge 1, an+1=12an+n2−2n−1n2(n+1)2a_{n+1} = \dfrac12 a_n + \dfrac{n^2 - 2n - 1}{n^2(n+1)^2}. Then ∣∑n=1∞(an−2n2)∣\left\lvert\displaystyle\sum_{n=1}^{\infty}\left(a_n - \frac{2}{n^2}\right)\right\rvert is equal to .
  23. Let S={(m,n):m,n∈{1,2,3,…,50}}S = \{(m, n) : m, n \in \{1, 2, 3, \ldots, 50\}\}. If the number of elements (m,n)(m, n) in SS such that 6m+9n6^m + 9^n is a multiple of 5 is pp and the number of elements (m,n)(m, n) in SS such that m+nm + n is a square of a prime number is qq, then p+qp + q is equal to .
  24. Q24 · Numerical · Matrices & DeterminantsOpen
    For some α,β∈R\alpha, \beta \in \mathbb{R}, let A=[α212]andB=[111β]A = \begin{bmatrix} \alpha & 2\\ 1 & 2\end{bmatrix} \quad\text{and}\quad B = \begin{bmatrix} 1 & 1\\ 1 & \beta\end{bmatrix} be such that A2−4A+2I=B2−3B+I=OA^2 - 4A + 2I = B^2 - 3B + I = O. Then (det⁡(adj⁡(A3−B3)))2(\det(\operatorname{adj}(A^3 - B^3)))^2 is equal to .
  25. Q25 · Numerical · Definite IntegrationOpen
    6∫0π∣(sin⁡3x+sin⁡2x+sin⁡x)∣dx6\displaystyle\int_0^{\pi}\left\lvert(\sin 3x + \sin 2x + \sin x)\right\rvert dx is equal to .