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MathsJEE Main 5 Apr 2026, Shift 2·Q13·MCQ·Easy–moderate

Conic Sections · Hyperbola latus rectum

Let the eccentricity ee of a hyperbola satisfy the equation 6e2−11e+3=06e^2 - 11e + 3 = 0. If the foci of the hyperbola are (3,5)(3, 5) (3,−4)(3, -4), then the length of its latus rectum is:
  1. (1)113\dfrac{11}{3}
  2. (2)173\dfrac{17}{3}
  3. (3)152\dfrac{15}{2}
  4. (4)172\dfrac{17}{2}

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