PhysicsJEE Main 21 Jan 2026, Shift 2·Q19·MCQ·Easy–moderate

Work, Energy and Power · Work and kinetic energy

A body of mass 2 kg is moving along x-direction such that its displacement as function of time is given by

x(t) = \alpha t^2 + \beta t + \gamma

, where

\alpha = 1\ \mathrm{m/s^2}

\beta = 1

m/s and

\gamma = 1

m. The work done on the body during the time interval

t = 2

s to

t = 3

s, is J.

We corrected a printing error in the original paper

Source printed “ $x(t) = \alpha t^2 + \beta t + \gamma\,\mathrm{m}$ ” (unit m doubled on $\gamma = 1$ m).

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