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Physics chapters

Work, Energy and Power

13 JEE Main questions · Physics

Work and kinetic energy

  1. PhysicsJEE Main 21 Jan 2026, Shift 2·Q19·MCQ·Easy–moderate
    Open
    A body of mass 2 kg is moving along x-direction such that its displacement as function of time is given by x(t)=αt2+βt+γx(t) = \alpha t^2 + \beta t + \gamma, where α=1 m/s2\alpha = 1\ \mathrm{m/s^2}, β=1\beta = 1 m/s and γ=1\gamma = 1m. The work done on the body during the time interval t=2t = 2 s to t=3t = 3 s, is J.
    1. (1)49
    2. (2)42
    3. (3)24
    4. (4)12
    We corrected a printing error in the original paper

    Source printed “x(t)=αt2+βt+γ mx(t) = \alpha t^2 + \beta t + \gamma\,\mathrm{m}” (unit m doubled on γ=1\gamma = 1 m).

  2. PhysicsJEE Main 2 Apr 2026, Shift 2·Q11·MCQ·Easy–moderate
    Open
    A spherical ball of mass 2 kg falls from a height of 10 m and is brought to rest after penetrating 10 cm into sand. The average force exerted by sand on the ball is N. (Take g=10 m/s2g = 10\ \mathrm{m/s^2})
    1. (1)1980
    2. (2)2020
    3. (3)2000
    4. (4)1000
    We corrected a printing error in the original paper

    Assumption “(Take g=10 m/s2g = 10\ \mathrm{m/s^2})” added; the source leaves it unstated, and with g=9.8 m/s2g = 9.8\ \mathrm{m/s^2} option (1) would be correct.

  3. PhysicsJEE Main 4 Apr 2026, Shift 1·Q21·Numerical·Easy–moderate
    Open
    A 1 kg block subjected to two simultaneous forces (2i^+3j^+4k^)(2\hat i + 3\hat j + 4\hat k) N and (3i^−j^−2k^)(3\hat i - \hat j - 2\hat k) N is moved a distance of 25 m along (3i^−4j^)(3\hat i - 4\hat j) direction. The work done in this process is J.
  4. PhysicsJEE Main 5 Apr 2026, Shift 2·Q3·MCQ·Moderate
    Open
    A mass of 1 kg kept in an inclined plane with 30∘30^\circ inclination with respect to horizontal plane and it is at rest initially. Then the whole assembly is moved up with constant velocity of 4 m/s. The work done by the frictional force in time 2s is J.
    (Take g=10 m/s2g = 10\ \mathrm{m/s^2})
    1. (1)20
    2. (2)25
    3. (3)30
    4. (4)10
    We corrected a printing error in the original paper

    Source printed “kept in a inclined plane”.

  5. PhysicsJEE Main 5 Apr 2026, Shift 2·Q13·MCQ·Moderate
    Open
    A particle of charge qq and mass mm is projected from origin with an initial velocity v⃗=(v02x^+v02y^)\vec v = \left(\dfrac{v_0}{\sqrt2}\hat{\mathrm x} + \dfrac{v_0}{\sqrt2}\hat{\mathrm y}\right). There exists a uniform magnetic field B⃗=B0z^\vec B = B_0\hat{\mathrm z} and a space varying electric field E⃗=E0e−λxx^\vec E = E_0e^{-\lambda x}\hat{\mathrm x} within the region 0≤x≤L0 \le x \le L. After travelling a distance such that x-coordinate has changed from x=0x = 0 to x=Lx = L, the change in the kinetic energy is.
    1. (1)qE0λ[1−e−λL]\dfrac{qE_0}{\lambda}\left[1 - e^{-\lambda L}\right]
    2. (2)(v0qB02λ)[2−e−2λL]\left(\dfrac{v_0qB_0}{2\lambda}\right)\left[2 - e^{-2\lambda L}\right]
    3. (3)qE0λ[1+e−λL]\dfrac{qE_0}{\lambda}\left[1 + e^{-\lambda L}\right]
    4. (4)q[E0+v0B0λ][1−e−λL/2]q\left[\dfrac{E_0 + v_0B_0}{\lambda}\right]\left[1 - e^{-\lambda L/2}\right]
  6. PhysicsJEE Main 6 Apr 2026, Shift 1·Q3·MCQ·Easy–moderate
    Open
    The rain drop of mass 1 g, starts with zero velocity from a height of 1 km. It hits the ground with a speed of 5 m/s. The work done by the unknown resistive force is J. (take g=10 m/s2g = 10\ \mathrm{m/s^2})
    1. (1)−8.75-8.75
    2. (2)−8.35-8.35
    3. (3)−9.55-9.55
    4. (4)−9.98-9.98
  7. PhysicsJEE Main 6 Apr 2026, Shift 2·Q4·MCQ·Easy–moderate
    Open
    A body of mass 1 kg moves along a straight line with a velocity v=2x2v = 2x^2. The work done on the body during displacement from x=0x = 0 to 5 m is J.
    1. (1)0
    2. (2)250
    3. (3)1250
    4. (4)1000
    We corrected a printing error in the original paper

    Source printed “The work done by the body”; corrected to the intended “The work done on the body” (the key 1250 J is the gain in kinetic energy; the work done by the body would be −1250-1250 J).

Potential energy and conservation

  1. PhysicsJEE Main 21 Jan 2026, Shift 1·Q1·MCQ·Easy–moderate
    Open
    Potential energy (VV) versus distance (xx) is given by the graph, Rank various regions as per the magnitudes of the force (F) acting on a particle from high to low.
    1. (1)FBC>FCD>FDE>FABF_{BC} > F_{CD} > F_{DE} > F_{AB}
    2. (2)FCD>FAB>FBC>FDEF_{CD} > F_{AB} > F_{BC} > F_{DE}
    3. (3)FCD>FDE>FAB>FBCF_{CD} > F_{DE} > F_{AB} > F_{BC}
    4. (4)FBC>FAB>FDE>FCDF_{BC} > F_{AB} > F_{DE} > F_{CD}
  2. PhysicsJEE Main 22 Jan 2026, Shift 2·Q16·MCQ·Easy
    Open

    Given below are two statements :

    Statement I : An object moves from position r1r_1 to position r2r_2 under a conservative force field F⃗\vec F. The work done by the force is W=−∫r1r2F⃗⋅dr⃗W = -\displaystyle\int_{r_1}^{r_2}\vec F\cdot\vec{dr}.

    Statement II : Any object moving from one location to another location can follow infinite number of paths. Therefore, the amount of work done by the object changes with the path it follows for a conservative force.

    In the light of the above statements, choose the correct answer from the options given below :

    1. (1)Both Statement I and Statement II are true
    2. (2)Statement I is false but Statement II is true
    3. (3)Statement I is true but Statement II is false
    4. (4)Both Statement I and Statement II are false
    We corrected a printing error in the original paper

    Answer corrected; the source key is (3) — the work done by a conservative force is +∫F⃗⋅dr⃗+\int\vec F\cdot\vec{dr}, so Statement I (with the minus sign) is false, and Statement II is false.

  3. PhysicsJEE Main 23 Jan 2026, Shift 1·Q2·MCQ·Moderate
    Open
    A small bob A of mass mm is attached to a massless rigid rod of length 1m pivoted at point P and kept at an angle of 60∘60^\circ with vertical as shown in figure. At distance of 1m below point P, an identical bob B is kept at rest on a smooth horizontal surface that extends to a circular track of radius R as shown in figure. If bob B just manages to complete the circular path of radius R upto a point Q after being hit elastically by bob A, then radius R is m.
    1. (1)35\dfrac35
    2. (2)15\dfrac15
    3. (3)2+35\dfrac{2+\sqrt3}{5}
    4. (4)2−35\dfrac{2-\sqrt3}{5}
    We corrected a printing error in the original paper

    Source printed “A small both A”.

  4. PhysicsJEE Main 23 Jan 2026, Shift 1·Q7·MCQ·Easy–moderate
    Open
    Two blocks with masses 100g and 200g are attached to the ends of springs A and B as shown in figure. The energy stored in A is E. The energy stored in B, when spring constants kAk_A, kBk_B of A and B, respectively satisfy the relation 4kA=3kB4k_A = 3k_B, is:
    1. (1)4E
    2. (2)2E
    3. (3)3E
    4. (4)43\dfrac43E
  5. PhysicsJEE Main 23 Jan 2026, Shift 2·Q8·MCQ·Moderate
    Open
    A bead PP is sliding on a frictionless semi-circular string (ACBACB) and it is at point SS at t=0t = 0 and at this instant the horizontal component of its velocity is vv. Another bead QQ of the same mass as PP is ejected from point AA at t=0t = 0 along the horizontal string ABAB, with the speed vv, friction between the beads and the respective strings may be neglected in both cases. Let tPt_P and tQt_Q be the respective times taken by beads PP and QQ to reach the point BB, then the relation between tPt_P and tQt_Q is
    1. (1)tP>tQt_P > t_Q
    2. (2)tP<tQt_P < t_Q
    3. (3)tP>1.25 tQt_P > 1.25\,t_Q
    4. (4)tP=tQt_P = t_Q
    We corrected a printing error in the original paper

    Source printed “A bead PP sliding on” (“is” missing); the subscript printed as “tpt_p” (bead PP) in the stem and in options (2)–(4).

Power

  1. PhysicsJEE Main 4 Apr 2026, Shift 1·Q24·Numerical·Moderate
    Open
    A body of mass 2 kg begins to move under the influence of time dependent force F⃗=(2ti^+6t2j^)\vec F = (2t\hat i + 6t^2\hat j) N, where i^\hat i and j^\hat j are unit vectors along x and y-axis respectively. The power produced by the force at t=2t = 2 s is W.