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PhysicsJEE Main 23 Jan 2026, Shift 2·Q21·Numerical·Easy–moderate

Nuclei · Radioactivity and nuclear energy

The average energy released per fission for the nucleus of 92235U{}^{235}_{92}\mathrm{U} is 190 MeV. When all the atoms of 47 g pure 92235U{}^{235}_{92}\mathrm{U} undergo fission process, the energy released is α×1023\alpha\times10^{23} MeV. The value of α\alpha is .
(Avogadro Number =6×1023= 6\times10^{23} per mole)

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