PhysicsJEE Main 6 Apr 2026, Shift 1·Q23·Numerical·Moderate

Nuclei · Radioactivity and nuclear energy

The energy released when

\dfrac{7}{17.13}

kg of

{}^{7}_{3}\mathrm{Li}

is converted into

{}^{4}_{2}\mathrm{He}

by proton bombardment is

\alpha\times10^{32}

eV. The value of

\alpha

is . (Nearest integer)
(Mass of

{}^{7}_{3}\mathrm{Li} = 7.0183

u, mass of

{}^{4}_{2}\mathrm{He} = 4.004

u, mass of proton

= 1.008

u and 1 u

= 931\ \mathrm{MeV/c^2}

and Avogadro number

= 6.0\times10^{23}

)

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