Equilibrium · Buffer solution pH

The pH of a solution obtained by mixing 5 mL of 0.1 M $\ce{NH4OH}$ solution with 250 mL of 0.1 M $\ce{NH4Cl}$ solution is $\times\,10^{-2}$. (Nearest integer)

Given : p$K_\mathrm{b}$ ($\ce{NH4OH}$) $= 4.74$

$\log 2 = 0.30$

$\log 3 = 0.48$

$\log 5 = 0.70$