MathsJEE Main 4 Apr 2026, Shift 2·Q14·MCQ·Moderate

3D Geometry · Image of point in line

If

\left(2\alpha + 1, \alpha^2 - 3\alpha, \dfrac{\alpha - 1}{2}\right)

is the image of

(\alpha, 2\alpha, 1)

in the line

\dfrac{x-2}{3} = \dfrac{y-1}{2} = \dfrac{z}{1}

, then the possible value(s) of

\alpha

is(are):

(1)Only 3
(2)Only 3 and $-1$
(3)Only 3, $\dfrac14$ and $-1$
(4)Only 3 and $\dfrac14$

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