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MathsJEE Main 5 Apr 2026, Shift 1·Q5·MCQ·Easy–moderate

Sequences & Series · Telescoping series sum

∑n=110(528n(n+1)(n+2))\displaystyle\sum_{n=1}^{10}\left(\frac{528}{n(n+1)(n+2)}\right) is equal to:
  1. (1)65
  2. (2)130
  3. (3)220
  4. (4)440

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