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MathsJEE Main 5 Apr 2026, Shift 2·Q5·MCQ·Moderate

Sequences & Series · Telescoping series sum

If the sum of the first 10 terms of the series 11+14×4+21+24×4+31+34×4+41+44×4+…\frac{1}{1 + 1^4\times4} + \frac{2}{1 + 2^4\times4} + \frac{3}{1 + 3^4\times4} + \frac{4}{1 + 4^4\times4} + \ldots is mn\dfrac{m}{n}, gcd⁡(m,n)=1\gcd(m, n) = 1, then m+nm + n is equal to:
  1. (1)256
  2. (2)264
  3. (3)276
  4. (4)284

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