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MathsJEE Main 5 Apr 2026, Shift 2·Q14·MCQ·Moderate

3D Geometry · Points on line at given distance

Let a triangle PQRPQR be such that PP and QQ lie on the line x+38=y−42=z+12\dfrac{x+3}{8} = \dfrac{y-4}{2} = \dfrac{z+1}{2} and are at a distance of 6 units from R(1,2,3)R(1, 2, 3). If (α,β,γ)(\alpha, \beta, \gamma) is the centroid of ΔPQR\Delta PQR, then α+β+γ\alpha + \beta + \gamma is equal to:
  1. (1)4
  2. (2)5
  3. (3)6
  4. (4)8

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