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MathsJEE Main 5 Apr 2026, Shift 2·Q21·Numerical·Moderate

Sets, Relations & Functions · Counting elements of a relation

Let A={1,4,7}A = \{1, 4, 7\} and B={2,3,8}B = \{2, 3, 8\}. Then the number of elements, in the relation R={((a1,b1),(a2,b2))∈((A×B)×(A×B)):a1+b2 divides a2+b1}R = \{((a_1, b_1), (a_2, b_2)) \in ((A \times B) \times (A \times B)) : a_1 + b_2 \text{ divides } a_2 + b_1\} is .

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