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Sets, Relations & Functions

27 JEE Main questions · Maths

  1. MathsJEE Main 21 Jan 2026, Shift 1·Q3·MCQ·Easy–moderate
    Open

    Reflexive and symmetric relations

    The number of relations, defined on the set {a,b,c,d}\{a, b, c, d\}, which are both reflexive and symmetric, is equal to:
    1. (1)256
    2. (2)16
    3. (3)1024
    4. (4)64
  2. MathsJEE Main 21 Jan 2026, Shift 2·Q13·MCQ·Easy–moderate
    Open

    Set operations on intervals

    Let A={x:∣x2−10∣≤6}A = \{x : \lvert x^2 - 10\rvert \le 6\} and B={x:∣x−2∣>1}B = \{x : \lvert x - 2\rvert > 1\}. Then
    1. (1)A∪B=(−∞,1]∪(2,∞)A \cup B = (-\infty, 1] \cup (2, \infty)
    2. (2)A−B=[2,3)A - B = [2, 3)
    3. (3)A∩B=[−4,−2]∪[3,4]A \cap B = [-4, -2] \cup [3, 4]
    4. (4)B−A=(−∞,−4)∪(−2,1)∪(4,∞)B - A = (-\infty, -4) \cup (-2, 1) \cup (4, \infty)
  3. MathsJEE Main 21 Jan 2026, Shift 2·Q17·MCQ·Easy–moderate
    Open

    Symmetric relations

    Let A={2,3,5,7,9}A = \{2, 3, 5, 7, 9\}. Let RR be the relation on AA defined by x R yx\,R\,y if and only if 2x≤3y2x \le 3y. Let ℓ\ell be the number of elements in RR, and mm be the minimum number of elements required to be added in RR to make it a symmetric relation. Then ℓ+m\ell + m is equal to:
    1. (1)23
    2. (2)25
    3. (3)21
    4. (4)27
  4. MathsJEE Main 22 Jan 2026, Shift 1·Q2·MCQ·Easy–moderate
    Open

    Symmetric relations

    Let the relation RR on the set M={1,2,3,…,16}M = \{1, 2, 3, \ldots, 16\} be given by R={(x,y):4y=5x−3, x,y∈M}.R = \{(x, y) : 4y = 5x - 3,\ x, y \in M\}. Then the minimum number of elements required to be added in RR, in order to make the relation symmetric, is equal to
    1. (1)1
    2. (2)2
    3. (3)4
    4. (4)3
  5. MathsJEE Main 22 Jan 2026, Shift 2·Q3·MCQ·Easy–moderate
    Open

    Counting elements of a relation

    The number of elements in the relation R={(x,y):4x2+y2<52, x,y∈Z}R = \{(x, y) : 4x^2 + y^2 < 52,\ x, y \in \mathbb{Z}\} is
    1. (1)77
    2. (2)89
    3. (3)67
    4. (4)86
  6. MathsJEE Main 22 Jan 2026, Shift 2·Q14·MCQ·Moderate
    Open

    Domain of a function

    Let the domain of the function f(x)=log⁡3log⁡5(7−log⁡2(x2−10x+85))+sin⁡−1(∣3x−717−x∣)f(x) = \log_3\log_5\left(7 - \log_2(x^2 - 10x + 85)\right) + \sin^{-1}\left(\left\lvert\dfrac{3x - 7}{17 - x}\right\rvert\right) be (α,β](\alpha, \beta]. Then α+β\alpha + \beta is equal to:
    1. (1)10
    2. (2)12
    3. (3)9
    4. (4)8
  7. MathsJEE Main 22 Jan 2026, Shift 2·Q18·MCQ·Moderate
    Open

    Greatest integer function

    Let f(x)=[x]2−[x+3]−3f(x) = [x]^2 - [x + 3] - 3, x∈Rx \in \mathbb{R} where [ ∙ ][\,\bullet\,] is the greatest integer function. Then
    1. (1)f(x)>0f(x) > 0 only for x∈[4,∞)x \in [4, \infty)
    2. (2)f(x)<0f(x) < 0 only for x∈[−1,3)x \in [-1, 3)
    3. (3)∫02f(x) dx=−6\displaystyle\int_0^2 f(x)\,dx = -6
    4. (4)f(x)=0f(x) = 0 for finitely many values of xx.
  8. MathsJEE Main 22 Jan 2026, Shift 2·Q19·MCQ·Easy–moderate
    Open

    Functional equations

    Let ff and gg be functions satisfying f(x+y)=f(x)f(y)f(x+y) = f(x)f(y), f(1)=7f(1) = 7 and g(x+y)=g(xy)g(x+y) = g(xy), g(1)=1g(1) = 1, for all x,y∈Nx, y \in \mathbb{N}. If ∑x=1n(f(x)g(x))=19607\displaystyle\sum_{x=1}^{n}\left(\frac{f(x)}{g(x)}\right) = 19607, then nn is equal to:
    1. (1)7
    2. (2)5
    3. (3)6
    4. (4)4
    We corrected a printing error in the original paper

    Source printed “f(l)=7f(l) = 7” and “g(l)=1g(l) = 1” (letter l for the number 1); the missing “If” added before “∑…=19607\sum \ldots = 19607”.

  9. MathsJEE Main 23 Jan 2026, Shift 1·Q1·MCQ·Moderate
    Open

    Domain of logarithmic function

    Let the domain of the function f(x)=log⁡3log⁡5log⁡7(9x−x2−13)f(x) = \log_3\log_5\log_7(9x - x^2 - 13) be the interval (m,n)(m, n). Let the hyperbola x2a2−y2b2=1\dfrac{x^2}{a^2} - \dfrac{y^2}{b^2} = 1 have eccentricity n3\dfrac{n}{3} and the length of the latus rectum 8m3\dfrac{8m}{3}. Then b2−a2b^2 - a^2 is equal to:
    1. (1)5
    2. (2)11
    3. (3)9
    4. (4)7
  10. MathsJEE Main 23 Jan 2026, Shift 1·Q6·MCQ·Moderate
    Open

    Reflexive and symmetric relations

    Let A={−2,−1,0,1,2,3,4}A = \{-2, -1, 0, 1, 2, 3, 4\}. Let RR be a relation on AA defined by xRyxRy if and only if 2x+y≤22x + y \le 2. Let ll be the number of elements in RR. Let mm and nn be the minimum number of elements required to be added in RR to make it reflexive and symmetric relations respectively. Then l+m+nl + m + n is equal to:
    1. (1)32
    2. (2)34
    3. (3)33
    4. (4)35
  11. MathsJEE Main 23 Jan 2026, Shift 2·Q5·MCQ·Moderate
    Open

    Number of onto functions

    Consider two sets A={x∈Z:∣(∣x−3∣−3)∣≤1}A = \{x \in \mathbb{Z} : \lvert(\lvert x - 3\rvert - 3)\rvert \le 1\} and B={x∈R−{1,2}:(x−2)(x−4)x−1log⁡e(∣x−2∣)=0}.B = \left\{x \in \mathbb{R} - \{1, 2\} : \dfrac{(x-2)(x-4)}{x-1}\log_e(\lvert x - 2\rvert) = 0\right\}. Then the number of onto functions f:A→Bf : A \to B is equal to:
    1. (1)62
    2. (2)79
    3. (3)32
    4. (4)81
    We corrected a printing error in the original paper

    Source printed “x∈zx \in z” (lower-case z) for the set of integers.

  12. MathsJEE Main 23 Jan 2026, Shift 2·Q16·MCQ·Easy–moderate
    Open

    Equivalence relations

    Let A={0,1,2,…,9}A = \{0, 1, 2, \ldots, 9\}. Let RR be a relation on AA defined by (x,y)∈R(x, y) \in R if and only if ∣x−y∣\lvert x - y\rvert is a multiple of 3.
    Given below are two statements:
    Statement I: n(R)=36n(R) = 36
    Statement II: RR is an equivalence relation.
    In the light of the above statements, choose the correct answer from the options given below
    1. (1)Both Statement I and Statement II are correct
    2. (2)Statement I is incorrect but Statement II is correct
    3. (3)Statement I is correct but Statement II is incorrect
    4. (4)Both Statement I and Statement II are incorrect
    We corrected a printing error in the original paper

    Source printed the set AA with a closing parenthesis, “2,....9)”, instead of a closing brace.

  13. MathsJEE Main 24 Jan 2026, Shift 1·Q6·MCQ·Moderate
    Open

    Domain of logarithmic function

    If the domain of the function f(x)=log⁡(10x2−17x+7)(18x2−11x+1)f(x) = \log_{(10x^2 - 17x + 7)}\left(18x^2 - 11x + 1\right) is (−∞,a)∪(b,c)∪(d,∞)−{e}(-\infty, a) \cup (b, c) \cup (d, \infty) - \{e\}, then 90(a+b+c+d+e)90(a + b + c + d + e) equals:
    1. (1)170
    2. (2)177
    3. (3)307
    4. (4)316
  14. MathsJEE Main 24 Jan 2026, Shift 1·Q12·MCQ·Easy–moderate
    Open

    Number of elements in relation

    Let RR be a relation defined on the set {1,2,3,4}×{1,2,3,4}\{1, 2, 3, 4\} \times \{1, 2, 3, 4\} by R={((a,b),(c,d)):2a+3b=3c+4d}.R = \{((a, b), (c, d)) : 2a + 3b = 3c + 4d\}. Then the number of elements in RR is
    1. (1)6
    2. (2)18
    3. (3)12
    4. (4)15
  15. MathsJEE Main 24 Jan 2026, Shift 2·Q17·MCQ·Moderate
    Open

    Functional equations

    Let ff be a function such that 3f(x)+2f(m19x)=5x3f(x) + 2f\left(\dfrac{m}{19x}\right) = 5x, x≠0x \neq 0, where m=∑i=19(i)2m = \displaystyle\sum_{i=1}^{9}(i)^2. Then f(5)−f(2)f(5) - f(2) is equal to
    1. (1)−9-9
    2. (2)36
    3. (3)18
    4. (4)9
  16. MathsJEE Main 28 Jan 2026, Shift 1·Q1·MCQ·Moderate
    Open

    Composite function equation

    If g(x)=3x2+2x−3g(x) = 3x^2 + 2x - 3, f(0)=−3f(0) = -3 and 4g(f(x))=3x2−32x+724g(f(x)) = 3x^2 - 32x + 72, where ff is a differentiable function, then f(g(2))f(g(2)) is equal to:
    1. (1)256\dfrac{25}{6}
    2. (2)−256-\dfrac{25}{6}
    3. (3)72\dfrac{7}{2}
    4. (4)−72-\dfrac{7}{2}
    We corrected a printing error in the original paper

    Assumption “where ff is a differentiable function” added; the source leaves it unstated, and without it ff may change at x=16/3x = 16/3 to the other root (14−3x)/6(14 - 3x)/6 of the equation, which gives f(13)=−25/6f(13) = -25/6 (option 2).

  17. MathsJEE Main 28 Jan 2026, Shift 2·Q8·MCQ·Easy–moderate
    Open

    One-one and many-one functions

    Given below are two statements :

    Statement I : The function f:R→Rf : \mathbb{R} \to \mathbb{R} defined by f(x)=x1+∣x∣f(x) = \dfrac{x}{1 + \lvert x\rvert} is one-one.

    Statement II : The function f:R→Rf : \mathbb{R} \to \mathbb{R} defined by f(x)=x2+4x−30x2−8x+18f(x) = \dfrac{x^2 + 4x - 30}{x^2 - 8x + 18} is many-one.

    In the light of the above statements, choose the correct answer from the options given below :

    1. (1)Both Statement I and Statement II are false.
    2. (2)Both Statement I and Statement II are true.
    3. (3)Statement I is false but Statement II is true.
    4. (4)Statement I is true but Statement II is false.
  18. MathsJEE Main 2 Apr 2026, Shift 1·Q21·Numerical·Moderate
    Open

    Domain of a function

    If the domain of the function f(x)=log⁡(0.6)(∣2x−5x2−4∣)f(x) = \sqrt{\log_{(0.6)}\left(\left\lvert\dfrac{2x-5}{x^2-4}\right\rvert\right)} is (−∞,a]∪{b}∪[c,d)∪(e,∞)(-\infty, a] \cup \{b\} \cup [c, d) \cup (e, \infty), then the value of a+b+c+d+ea + b + c + d + e is .
  19. MathsJEE Main 2 Apr 2026, Shift 2·Q21·Numerical·Easy–moderate
    Open

    Number of elements in relation

    Let A={2,3,4,5,6}A = \{2, 3, 4, 5, 6\}. Let RR be a relation on the set A×AA \times A given by (x,y)R(z,w)(x, y)R(z, w) if and only if xx divides zz and y≤wy \le w. Then the number of elements in RR is .
  20. MathsJEE Main 4 Apr 2026, Shift 1·Q4·MCQ·Easy–moderate
    Open

    Number of onto functions

    The number of functions f:{1,2,3,4}→{a,b,c}f : \{1, 2, 3, 4\} \to \{a, b, c\}, which are not onto, is:
    1. (1)48
    2. (2)45
    3. (3)51
    4. (4)35
  21. MathsJEE Main 4 Apr 2026, Shift 2·Q1·MCQ·Moderate
    Open

    Inverse of a function

    For the function f:[1,∞)→[1,∞)f : [1, \infty) \to [1, \infty) defined by f(x)=(x−1)4+1f(x) = (x-1)^4 + 1, among the two statements:
    (I) The set S={x∈[1,∞):f(x)=f−1(x)}S = \{x \in [1, \infty) : f(x) = f^{-1}(x)\} contains exactly two elements, and
    (II) The set S={x∈[1,∞):f(x)=f−1(x+1)}S = \{x \in [1, \infty) : f(x) = f^{-1}(x+1)\} is an empty set,
    1. (1)only (I) is TRUE
    2. (2)only (II) is TRUE
    3. (3)both (I) and (II) are TRUE
    4. (4)neither (I) nor (II) is TRUE
  22. MathsJEE Main 4 Apr 2026, Shift 2·Q16·MCQ·Moderate
    Open

    Functional equations

    Let for some α∈R\alpha \in \mathbb{R}, f:R→Rf : \mathbb{R} \to \mathbb{R} be a function satisfying f(x+y)=f(x)+2y2+y+αxyf(x + y) = f(x) + 2y^2 + y + \alpha xy for all x,y∈Rx, y \in \mathbb{R}. If f(0)=−1f(0) = -1 and f(1)=2f(1) = 2, then the value of ∑n=15(α+f(n))\displaystyle\sum_{n=1}^{5}\left(\alpha + f(n)\right) is:
    1. (1)110
    2. (2)140
    3. (3)150
    4. (4)170
  23. MathsJEE Main 5 Apr 2026, Shift 2·Q21·Numerical·Moderate
    Open

    Counting elements of a relation

    Let A={1,4,7}A = \{1, 4, 7\} and B={2,3,8}B = \{2, 3, 8\}. Then the number of elements, in the relation R={((a1,b1),(a2,b2))∈((A×B)×(A×B)):a1+b2 divides a2+b1}R = \{((a_1, b_1), (a_2, b_2)) \in ((A \times B) \times (A \times B)) : a_1 + b_2 \text{ divides } a_2 + b_1\} is .
  24. MathsJEE Main 6 Apr 2026, Shift 2·Q1·MCQ·Easy–moderate
    Open

    One-one and onto functions

    Let f:R→Rf : \mathbb{R} \to \mathbb{R} be defined as f(x)=2x2−3x+23x2+x+3f(x) = \dfrac{2x^2 - 3x + 2}{3x^2 + x + 3}. Then ff is:
    1. (1)both one-one and onto
    2. (2)one-one but not onto
    3. (3)onto but not one-one
    4. (4)neither one-one nor onto
  25. MathsJEE Main 6 Apr 2026, Shift 2·Q21·Numerical·Moderate
    Open

    Transitive closure of relation

    Let R={(x,y)∈N×N:log⁡e(x+y)≤2}R = \{(x, y) \in \mathbb{N} \times \mathbb{N} : \log_e(x + y) \le 2\}. Then the minimum number of elements, required to be added in RR to make it a transitive relation, is .
  26. MathsJEE Main 8 Apr 2026, Shift 2·Q1·MCQ·Easy–moderate
    Open

    Equivalence relations and counting

    Consider the relation RR on the set {−2,−1,0,1,2}\{-2, -1, 0, 1, 2\} defined by (a,b)∈R(a, b) \in R if and only if 1+ab>01 + ab > 0. Then among the statements:

    I. The number of elements in RR is 17

    II. RR is an equivalence relation

    1. (1)Only I is true
    2. (2)Only II is true
    3. (3)Both I and II are true
    4. (4)Neither I nor II is true
  27. MathsJEE Main 8 Apr 2026, Shift 2·Q25·Numerical·Moderate
    Open

    Polynomial functional equation

    Let ff be a polynomial function such that log⁡2(f(x))=(log⁡2(2+23+29+…∞))⋅log⁡3(1+f(x)f(1x)),\log_2(f(x)) = \left(\log_2\left(2 + \frac23 + \frac29 + \ldots\infty\right)\right)\cdot\log_3\left(1 + \frac{f(x)}{f\left(\frac1x\right)}\right), x>0x > 0 and f(6)=37f(6) = 37. Then ∑n=110f(n)\displaystyle\sum_{n=1}^{10} f(n) is equal to .