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ChemistryJEE Main 8 Apr 2026, Shift 2·Q6·MCQ·Easy–moderate

Electrochemistry · Combining electrode potentials

Given at 298 K : EFe2+/Fe⊖=XE^{\ominus}_{\mathrm{Fe^{2+}/Fe}} = X Volt

 EFe3+/Fe⊖=YE^{\ominus}_{\mathrm{Fe^{3+}/Fe}} = Y Volt

The EFe3+/Fe2+⊖E^{\ominus}_{\mathrm{Fe^{3+}/Fe^{2+}}} in Volt at 298 K is given by :

  1. (1)2X−3Y2X - 3Y
  2. (2)3Y−2X3Y - 2X
  3. (3)3Y+2X3Y + 2X
  4. (4)Y+XY + X

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See the full 8 Apr 2026, Shift 2 paper