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PhysicsJEE Main 4 Apr 2026, Shift 1·Q5·MCQ·Moderate

Rotational Motion · Moment of inertia

A solid sphere of mass MM and radius RR is divided into two unequal parts. The smaller part having mass M/8M/8 is converted into a sphere of radius rr and the larger part is converted into a circular disc of thickness tt and radius 2R2R. If I1I_1 is moment of inertia of a sphere having radius rr about an axis through its centre and I2I_2 is the moment of inertia of a disc about its diameter, the ratio of their moment of inertia I2/I1=I_2/I_1 = .
  1. (1)35
  2. (2)70
  3. (3)140
  4. (4)210
We corrected a printing error in the original paper

Source printed “mas”.

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