Motion in a Straight Line

8 JEE Main questions · Physics

PhysicsJEE Main 23 Jan 2026, Shift 2·Q5·MCQ·Moderate
Open
Motion in a straight line
A paratrooper jumps from an aeroplane and opens a parachute after 2 s of free fall and starts decelerating with $3\ \mathrm{m/s^2}$ . At 10 m height from ground, while descending with the help of parachute, the speed of paratrooper is 5 m/s. The initial height of the aeroplane is m.
( $g = 10\ \mathrm{m/s^2}$ )
1. (1)62.5
2. (2)92.5
3. (3)20
4. (4)82.5
We corrected a printing error in the original paper
Source printed “deaccelerating”.
PhysicsJEE Main 24 Jan 2026, Shift 2·Q19·MCQ·Moderate
Open
Motion in a straight line
The velocity ( $v$ ) – Distance ( $x$ ) graph is shown in figure. Which graph represents acceleration ( $a$ ) versus distance ( $x$ ) variation of this system?
1. (1)
2. (2)
3. (3)
4. (4)
PhysicsJEE Main 28 Jan 2026, Shift 1·Q5·MCQ·Easy–moderate
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Motion in a straight line
Water drops fall from a tap on the floor, 5 m below, at regular intervals of time, the first drop strikes the floor when the sixth drop begins to fall. The height at which the fourth drop will be from ground, at the instant when the first drop strikes the ground is m.
( $g = 10\ \mathrm{m/s^2}$ )
1. (1)2.5
2. (2)4.0
3. (3)4.2
4. (4)3.8

PhysicsJEE Main 28 Jan 2026, Shift 2·Q8·MCQ·Moderate

Motion in a straight line

A particle starts moving from time

t = 0

and its coordinate is given as

x(t) = 4t^3 - 3t

A.	The particle returns to its original position (origin) 0.866 units later
B.	The particle is 1 unit away from origin at its turning point.
C.	Acceleration of the particle is non-negative.
D.	The particle is 0.5 units away from origin at its turning point.
E.	Particle never turns back as acceleration is non-negative.

Choose the correct answer from the options given below:

(1)A, C, D only
(2)A, B, C only
(3)C, E only
(4)A, C only

PhysicsJEE Main 5 Apr 2026, Shift 1·Q22·Numerical·Easy–moderate
Open
Motion in a straight line
From 18 m height above the ground a ball is dropped from rest. The height above the ground at which the magnitude of velocity is equal to the magnitude of acceleration (in the same set of units) due to gravity is m. (Take $g = 10\ \mathrm{m/s^2}$ and neglect the air resistance)
We corrected a printing error in the original paper
Source printed “the magnitude of velocity equal to” (“is” missing).
PhysicsJEE Main 5 Apr 2026, Shift 2·Q4·MCQ·Easy–moderate
Open
Motion in a straight line
The velocity( $v$ ) versus time ( $t$ ) plot of a particle is shown in the figure, for a time interval of 40s. The total distance travelled by the particle and the average velocity during this period are, respectively
1. (1)25 m and zero
2. (2)50 m and zero
3. (3)100 m and zero
4. (4)100 m and 2.5 m/s
PhysicsJEE Main 8 Apr 2026, Shift 2·Q4·MCQ·Moderate
Open
Motion in a straight line
A gas balloon is going up with a constant velocity of 10 m/s. When this balloon reached a height of 75 m, a stone is dropped from it and balloon keeps moving up with the same velocity. The height of the balloon when the stone hits the ground is m. (Take $g = 10\ \mathrm{m/s^2}$ )
1. (1)85
2. (2)150
3. (3)129
4. (4)125
PhysicsJEE Main 8 Apr 2026, Shift 2·Q25·Numerical·Moderate
Open
Motion in a straight line
Two masses of 3.4 kg and 2.5 kg are accelerated from an initial speed of 5 m/s and 12 m/s, respectively. The distances traversed by the masses in the $5^{\text{th}}$ second are 104 m and 129 m, respectively. The ratio of their momenta after 10 s is $\dfrac{x}{8}$ . The value of $x$ is .