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Quadratic Equations

22 JEE Main questions · Maths

  1. MathsJEE Main 21 Jan 2026, Shift 1·Q19·MCQ·Easy–moderate
    Open

    Equations involving modulus

    The sum of all the roots of the equation (x−1)2−5∣x−1∣+6=0(x-1)^2 - 5\lvert x - 1\rvert + 6 = 0, is:
    1. (1)4
    2. (2)3
    3. (3)1
    4. (4)5
  2. MathsJEE Main 21 Jan 2026, Shift 2·Q9·MCQ·Easy–moderate
    Open

    Location of roots

    Let α\alpha and β\beta be the roots of equation x2+2ax+(3a+10)=0x^2 + 2ax + (3a + 10) = 0 such that α<1<β\alpha < 1 < \beta. Then the set of all possible values of aa is:
    1. (1)(−∞,−115)∪(5,∞)\left(-\infty, \dfrac{-11}{5}\right) \cup (5, \infty)
    2. (2)(−∞,−2)∪(5,∞)(-\infty, -2) \cup (5, \infty)
    3. (3)(−∞,−3)(-\infty, -3)
    4. (4)(−∞,−115)\left(-\infty, \dfrac{-11}{5}\right)
  3. MathsJEE Main 22 Jan 2026, Shift 1·Q8·MCQ·Easy–moderate
    Open

    Equations involving modulus

    The number of distinct real solutions of the equation x∣x+4∣+3∣x+2∣+10=0x\lvert x + 4\rvert + 3\lvert x + 2\rvert + 10 = 0 is
    1. (1)3
    2. (2)1
    3. (3)0
    4. (4)2
  4. MathsJEE Main 22 Jan 2026, Shift 2·Q13·MCQ·Easy–moderate
    Open

    Difference of roots

    Let α,β\alpha, \beta be the roots of the quadratic equation 12x2−20x+3λ=012x^2 - 20x + 3\lambda = 0, λ∈Z\lambda \in \mathbb{Z}. If 12≤∣β−α∣≤32\dfrac12 \le \lvert\beta - \alpha\rvert \le \dfrac32, then the sum of all possible values of λ\lambda is:
    1. (1)6
    2. (2)1
    3. (3)3
    4. (4)4
  5. MathsJEE Main 23 Jan 2026, Shift 1·Q8·MCQ·Moderate
    Open

    Equations reducible to quadratic with modulus

    If α\alpha and β\beta (α<β)(\alpha < \beta) are the roots of the equation (−2+3)(∣x−3∣)+(x−6x)+(9−23)=0,\left(-2 + \sqrt3\right)\left(\left\lvert\sqrt x - 3\right\rvert\right) + \left(x - 6\sqrt x\right) + \left(9 - 2\sqrt3\right) = 0, x≥0x \ge 0, then βα+αβ\sqrt{\dfrac{\beta}{\alpha}} + \sqrt{\alpha\beta} is equal to:
    1. (1)8
    2. (2)9
    3. (3)10
    4. (4)11
  6. MathsJEE Main 23 Jan 2026, Shift 1·Q19·MCQ·Easy–moderate
    Open

    Word problem leading to quadratic

    A building construction work can be completed by two masons AA and BB together in 22.5 days. Mason AA alone can complete the construction work in 24 days less than mason BB alone. Then mason AA alone will complete the construction work in:
    1. (1)24 days
    2. (2)42 days
    3. (3)30 days
    4. (4)36 days
  7. MathsJEE Main 23 Jan 2026, Shift 2·Q7·MCQ·Moderate
    Open

    Logarithmic equations

    The sum of all the real solutions of the equation log⁡(x+3)(6x2+28x+30)=5−2log⁡(6x+10)(x2+6x+9)\log_{(x+3)}(6x^2 + 28x + 30) = 5 - 2\log_{(6x+10)}(x^2 + 6x + 9) is equal to:
    1. (1)2
    2. (2)1
    3. (3)0
    4. (4)4
  8. MathsJEE Main 24 Jan 2026, Shift 1·Q20·MCQ·Moderate
    Open

    Equations involving modulus

    The number of the real solutions of the equation : x∣x+3∣+∣x−1∣−2=0x\lvert x + 3\rvert + \lvert x - 1\rvert - 2 = 0 is
    1. (1)3
    2. (2)2
    3. (3)5
    4. (4)4
  9. MathsJEE Main 24 Jan 2026, Shift 2·Q18·MCQ·Moderate
    Open

    Location of roots

    The smallest positive integral value of aa, for which all the roots of x4−ax2+9=0x^4 - ax^2 + 9 = 0 are real and distinct, is equal to
    1. (1)9
    2. (2)3
    3. (3)4
    4. (4)7
  10. MathsJEE Main 28 Jan 2026, Shift 1·Q8·MCQ·Easy–moderate
    Open

    Polynomial divisibility

    Let S={x3+ax2+bx+c:a,b,c∈N and a,b,c≤20}S = \{x^3 + ax^2 + bx + c : a, b, c \in \mathbb{N} \text{ and } a, b, c \le 20\} be a set of polynomials. Then the number of polynomials in SS, which are divisible by x2+2x^2 + 2, is
    1. (1)20
    2. (2)6
    3. (3)120
    4. (4)10
  11. MathsJEE Main 28 Jan 2026, Shift 1·Q10·MCQ·Easy–moderate
    Open

    Roots and coefficients

    If α,β\alpha, \beta, where α<β\alpha < \beta, are the roots of the equation λx2−(λ+3)x+3=0\lambda x^2 - (\lambda + 3)x + 3 = 0 such that 1α−1β=13\dfrac{1}{\alpha} - \dfrac{1}{\beta} = \dfrac{1}{3}, then the sum of all possible values of λ\lambda is:
    1. (1)6
    2. (2)2
    3. (3)4
    4. (4)8
  12. MathsJEE Main 28 Jan 2026, Shift 2·Q7·MCQ·Moderate
    Open

    Location of roots

    Let the arithmetic mean of 1a\dfrac1a and 1b\dfrac1b be 516\dfrac{5}{16}, a>2a > 2. If α\alpha is such that a,4,α,ba, 4, \alpha, b are in A.P., then the equation αx2−ax+2(α−2b)=0\alpha x^2 - ax + 2(\alpha - 2b) = 0 has :
    1. (1)One root in (1,4)(1, 4) and another in (−2,0)(-2, 0)
    2. (2)One root in (0,2)(0, 2) and another in (−4,−2)(-4, -2)
    3. (3)Complex roots of magnitude less than 2
    4. (4)Both roots in the interval (−2,0)(-2, 0)
  13. MathsJEE Main 2 Apr 2026, Shift 1·Q1·MCQ·Moderate
    Open

    Roots differing by a constant

    Let α,α+2\alpha, \alpha + 2, α∈Z\alpha \in \mathbb{Z}, be the roots of the quadratic equation x(x+2)+(x+1)(x+3)+(x+2)(x+4)+…+(x+n−1)(x+n+1)=4nx(x+2) + (x+1)(x+3) + (x+2)(x+4) + \ldots + (x+n-1)(x+n+1) = 4n for some n∈Nn \in \mathbb{N}. Then (n+α)(n + \alpha) is equal to:
    1. (1)0
    2. (2)1
    3. (3)2
    4. (4)3
  14. MathsJEE Main 2 Apr 2026, Shift 2·Q1·MCQ·Moderate
    Open

    Relation between roots and coefficients

    Let α,β\alpha, \beta be the roots of the equation x2−3x+r=0x^2 - 3x + r = 0, and α2,2β\dfrac{\alpha}{2}, 2\beta be the roots of the equation x2+3x+r=0x^2 + 3x + r = 0. If the roots of the equation x2+6x=mx^2 + 6x = m are 2α+β+2r2\alpha + \beta + 2r and α−2β−r2\alpha - 2\beta - \dfrac{r}{2}, then mm is equal to:
    1. (1)−135-135
    2. (2)−567-567
    3. (3)135
    4. (4)567
  15. MathsJEE Main 2 Apr 2026, Shift 2·Q12·MCQ·Easy–moderate
    Open

    Vertex of quadratic expression

    Let the parabola y=x2+px+qy = x^2 + px + q passing through the point (1,−1)(1, -1) be such that the distance between its vertex and the xx-axis is minimum. Then the value of p2+q2p^2 + q^2 is:
    1. (1)2
    2. (2)4
    3. (3)5
    4. (4)8
  16. MathsJEE Main 4 Apr 2026, Shift 1·Q2·MCQ·Moderate
    Open

    Modulus equations and inequalities

    If the set of all solutions of ∣x2+x−9∣=∣x∣+∣x2−9∣\lvert x^2 + x - 9\rvert = \lvert x\rvert + \lvert x^2 - 9\rvert is [α,β]∪[γ,∞)[\alpha, \beta] \cup [\gamma, \infty), then (α2+β2+γ2)(\alpha^2 + \beta^2 + \gamma^2) is equal to:
    1. (1)9
    2. (2)18
    3. (3)36
    4. (4)72
  17. MathsJEE Main 4 Apr 2026, Shift 2·Q4·MCQ·Moderate
    Open

    Cubic with complex roots

    If α=1\alpha = 1 and β=1+i2\beta = 1 + i\sqrt2, where i=−1i = \sqrt{-1} are two roots of the equation x3+ax2+bx+c=0x^3 + ax^2 + bx + c = 0, a,b,c∈Ra, b, c \in \mathbb{R}, then ∫−11(x3+ax2+bx+c)dx\displaystyle\int_{-1}^{1}\left(x^3 + ax^2 + bx + c\right)dx is equal to:
    1. (1)−2-2
    2. (2)−4-4
    3. (3)−8-8
    4. (4)−10-10
  18. MathsJEE Main 4 Apr 2026, Shift 2·Q5·MCQ·Moderate
    Open

    Location of roots

    If the quadratic equation (λ+2)x2−3λx+4λ=0(\lambda + 2)x^2 - 3\lambda x + 4\lambda = 0, λ≠−2\lambda \neq -2, has two positive roots, then the number of possible integral values of λ\lambda is:
    1. (1)1
    2. (2)2
    3. (3)3
    4. (4)4
  19. MathsJEE Main 5 Apr 2026, Shift 1·Q1·MCQ·Moderate
    Open

    Symmetric functions of roots

    Let a,b∈Ca, b \in \mathbb{C}. Let α,β\alpha, \beta be the roots of the equation x2+ax+b=0x^2 + ax + b = 0. If β−α=11\beta - \alpha = \sqrt{11} and β2−α2=3i11\beta^2 - \alpha^2 = 3i\sqrt{11}, then (β3−α3)2(\beta^3 - \alpha^3)^2 is equal to:
    1. (1)160
    2. (2)176
    3. (3)194
    4. (4)187
  20. MathsJEE Main 5 Apr 2026, Shift 2·Q1·MCQ·Moderate
    Open

    Roots in geometric progression

    Let α,β\alpha, \beta be the roots of the equation x2−x+p=0x^2 - x + p = 0 and γ,δ\gamma, \delta be the roots of the equation x2−4x+q=0x^2 - 4x + q = 0; p,q∈Zp, q \in \mathbb{Z}. If α,β,γ,δ\alpha, \beta, \gamma, \delta are in G.P., then ∣p+q∣\lvert p + q\rvert equals:
    1. (1)16
    2. (2)32
    3. (3)34
    4. (4)38
    We corrected a printing error in the original paper

    Source printed “be the roots the equation x2−4x+q=0x^2 - 4x + q = 0” (missing “of”).

  21. MathsJEE Main 6 Apr 2026, Shift 1·Q2·MCQ·Moderate
    Open

    Relation between roots and coefficients

    Let one root of the quadratic equation in xx: (k2−15k+27)x2+9(k−1)x+18=0(k^2 - 15k + 27)x^2 + 9(k - 1)x + 18 = 0 be twice the other. Then the length of the latus rectum of the parabola y2=6kxy^2 = 6kx is equal to:
    1. (1)4
    2. (2)6
    3. (3)8
    4. (4)12
  22. MathsJEE Main 8 Apr 2026, Shift 2·Q21·Numerical·Moderate
    Open

    Logarithmic equations

    The sum of squares of all real solutions of the equation log⁡(x+1)(2x2+5x+3)=4−log⁡(2x+3)(x2+2x+1)\log_{(x+1)}(2x^2 + 5x + 3) = 4 - \log_{(2x+3)}(x^2 + 2x + 1) is equal to .
    We corrected a printing error in the original paper

    Source printed “all real solution” (singular).